ÌâÄ¿ÄÚÈÝ

¡¾»¯Ñ§Ñ¡ÐÞ2£º»¯Ñ§Óë¼¼Êõ¡¿Éú̬¹¤ÒµÔ°ÇøµÄ½¨É裬²»½ö½öÊÇÌåÏÖ»·±£ÀíÄî¸üÒªÒÀ¾ÝÑ­»·¾­¼ÃÀíÂۺͳä·Ö¿¼ÂǾ­¼ÃµÄ¿É³ÖÐø·¢Õ¹¡£ÏÂͼÊÇijÆóÒµÉè¼ÆµÄÁòËá-Á×ï§-Ë®ÄàÁª²ú£¬º£Ë®-µ­Ë®¶àÓá¢ÑÎ-ÈÈ-µçÁª²úÈý´óÉú̬²úÒµÁ´Á÷³Ìͼ¡£»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©´ÓÔ­ÁÏ¡¢ÄÜÔ´¡¢½»Í¨½Ç¶È¿¼ÂÇ¸ÃÆóÒµÓ¦½¨ÔÚ

AÎ÷²¿É½Çø BÑØº£µØÇø C·¢´ï³ÇÊÐ D¶«±±ÄÚ½

£¨2£©¸ÃÁ÷³Ì¢Ù¡¢¢Ú¡¢¢Û¡¢¢Ü¡¢¢ÝΪÄÜÁ¿»òÎïÖʵÄÊäËÍ£¬Çë·Ö±ðд³öÊäË͵ÄÖ÷ÒªÎïÖʵĻ¯Ñ§Ê½»òÄÜÁ¿ÐÎʽ£º¢Ù________¡¢¢Ú________¡¢¢Û________¡¢¢Ü________¡¢¢Ý________£»

£¨3£©·ÐÌÚ¯·¢Éú·´Ó¦µÄ»¯Ñ§·½³Ìʽ__________£»Á׷ʳ§µÄÖ÷Òª²úÆ·ÊÇÆÕ¸Æ£¬ÆäÖ÷Òª³É·ÖÊÇ___________(Ìѧʽ)£»

£¨4£©Èȵ糧µÄÀäÈ´Ë®ÊÇ________£¬¸ÃÁ÷³ÌÖÐŨËõÑÎË®³ýÌáÈ¡ÑÎÒÔÍ⻹¿ÉÌáÈ¡µÄÎïÖÊÓÐ_________£»(д³öÒ»ÖÖ¼´¿É)

£¨5£©¸ù¾ÝÏÖ´ú»¯¹¤³§Ã»¼ÆÀíÄîÇëÌá³ö¸ß¯Á¶Ìú³§·ÏÆø¡¢·ÏÔü¼°¶àÓàÈÈÄܵÄÀûÓÃÉèÏë______________¡£(д³öÁ½µã¼´¿É)

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

ÑÇÏõËáÂÈ(C1NO)ÊÇÓлúºÏ³ÉÖеÄÖØÒªÊÔ¼Á¡£¿ÉÓÉNOÓëCl2ÔÚͨ³£Ìõ¼þÏ·´Ó¦µÃµ½£¬»¯Ñ§·½³ÌʽΪ2NO(g)+C12(g)2C1NO(g)£¬

£¨1£©µªÑõ»¯ÎïÓëÐü¸¡ÔÚ´óÆøÖеĺ£ÑÎÁ£×ÓÏ໥×÷ÓÃʱ»áÉú³ÉÑÇÏõËáÂÈ£¬Éæ¼°ÈçÏ·´Ó¦£º

¢Ù2NO2(g)+NaC1(s)NaNO3(s)+ClNO(g)K1

¢Ú4NO2(g)+2NaC1(s)2NaNO3(s)+2NO(g)+Cl2(g)K2

¢Û2NO(g)+C12(g)2C1NO(g)K3

ÔòK1£¬K2£¬K3Ö®¼äµÄ¹ØÏµÎªK3=______________¡£

£¨2£©ÒÑÖª¼¸ÖÖ»¯Ñ§¼üµÄ¼üÄÜÊý¾ÝÈçϱí(ÑÇÏõËáÂȵĽṹΪCl-N=O):

Ôò2NO(g)+C12(g)2C1NO(g)·´Ó¦µÄ¡÷HºÍaµÄ¹ØÏµÎª¡÷H=______________kJ/mol¡£

£¨3£©300¡æÊ±.2NO(g)+C12(g)2ClNO(g)µÄÕý·´Ó¦ËÙÂʱí´ïʽΪvÕý=k¡¤cn(ClNO)£¬

²âµÃËÙÂʺÍŨ¶ÈµÄ¹ØÏµÈçÏÂ±í£º

n=____________£»k=____________(×¢Ã÷µ¥Î»)¡£

£¨4£©ÔÚ1LµÄºãÈÝÃܱÕÈÝÆ÷ÖгäÈë2molNO(g)ºÍ1molC12(g)£¬ÔÚ²»Í¬Î¶ÈϲâµÃc(C1NO)Óëʱ¼äµÄ¹ØÏµÈçͼA:

¢Ù¸Ã·´Ó¦µÄ¡÷H____________0(Ìî¡°>¡±¡°<¡±»ò¡°=¡±)¡£

¢Ú·´Ó¦¿ªÊ¼µ½10minʱNOµÄƽ¾ù·´Ó¦ËÙÂÊv(NO)=____________mol/(L¡¤min)£¬

¢ÛT2ʱ¸Ã·´Ó¦µÄƽºâ³£ÊýK=____________

£¨5£©Ò»¶¨Ìõ¼þÏÂÔÚºãκãÈݵÄÃܱÕÈÝÆ÷Öа´Ò»¶¨±ÈÀý³äÈëNO(g)ºÍCl2(g)£¬Æ½ºâʱClNOµÄÌå»ý·ÖÊýËæn(NO)/n(C12)µÄ±ä»¯Í¼ÏóÈçͼB£¬ÔòA¡¢B¡¢CÈý״̬ÖУ¬NOµÄת»¯ÂÊ×î´óµÄÊÇ____________µã£¬µ±n(NO)/n(C12)=1.5ʱ£¬´ïµ½Æ½ºâ״̬ClNOµÄÌå»ý·ÖÊý¿ÉÄÜÊÇD¡¢E¡¢FÈýµãÖеÄ____________µã¡£

¡¾»¯Ñ§Ñ¡ÐÞ3£ºÎïÖʽṹÓëÐÔÖÊ¡¿¢ñ£®80%×óÓҵķǽðÊôÔªËØÔÚÏÖ´ú¼¼Êõ°üÀ¨ÄÜÔ´¡¢¹¦ÄܲÄÁϵÈÁìÓòÕ¼Óм«ÎªÖØÒªµÄµØÎ»¡£

£¨1£©µª¼°Æä»¯ºÏÎïÓëÈËÀàÉú²ú¡¢Éú»îϢϢÏà¹Ø£¬»ù̬NÔ­×ÓÖеç×ÓÔÚ2p¹ìµÀÉϵÄÅŲ¼×ñÑ­µÄÔ­ÔòÊÇ__________£¬N2F2·Ö×ÓÖÐNÔ­×ÓµÄÔÓ»¯·½Ê½ÊÇ_____________£¬1mol N2F2º¬ÓÐ___________¸ö¦Ò¼ü£®

£¨2£©¸ßÎÂÌմɲÄÁÏSi3N4¾§ÌåÖмü½ÇN-Si-N___Si-N-Si(Ìî¡°£¾¡±¡°£¼¡±»ò¡°=¡±)£¬Ô­ÒòÊÇ__________£»

II£®½ðÊôÔªËØÔÚÏÖ´ú¹¤ÒµÖÐÒ²Õ¼¾Ý¼«ÆäÖØÒªµÄµØÎ»£¬îÑÒ²±»³ÆÎª¡°Î´À´µÄ¸ÖÌú¡±£¬¾ßÓÐÖÊÇᣬ¿¹¸¯Ê´£¬Ó²¶È´ó£¬ÊÇÓ¡¢º½º£¡¢»¯¹¤É豸µÈµÄÀíÏë²ÄÁÏ¡£

£¨4£©»ù̬îÑÔ­×ÓºËÍâ¹²ÓÐ________ÖÖÔ˶¯×´Ì¬²»ÏàͬµÄµç×Ó£®½ðÊôîѾ§°ûÈçÏÂͼ1Ëùʾ£¬Îª_______¶Ñ»ý(Ìî¶Ñ»ý·½Ê½)£®

£¨5£©ÄÉÃ×TiO2ÊÇÒ»ÖÖÓ¦Óù㷺µÄ´ß»¯¼Á£¬Æä´ß»¯µÄÒ»¸öʵÀýÈçÏÂͼ2£®»¯ºÏÎïÒҵķеãÃ÷ÏÔ¸ßÓÚ»¯ºÏÎï¼×£¬Ö÷ÒªÔ­ÒòÊÇ_____________£»»¯ºÏÎïÒÒÖвÉÈ¡sp3ÔÓ»¯µÄÔ­×ӵĵ縺ÐÔÓÉ´óµ½Ð¡µÄ˳ÐòΪ_____________£»

£¨6£©¸ÆîÑ¿ó¾§ÌåµÄ½á¹¹Èçͼ3Ëùʾ£®¼ÙÉè°ÑÑõÀë×Ó¿´×öÓ²Çò½Ó´¥Ä£ÐÍ£¬¸ÆÀë×ÓºÍîÑÀë×ÓÌî³äÑõÀë×ӵĿÕ϶£¬ÑõÀë×ÓÐγÉÕý°ËÃæÌ壬îÑÀë×ÓλÓÚÕý°ËÃæÌåÖÐÐÄ£¬ÔòÒ»¸öîÑÀë×Ó±»________¸öÑõÀë×Ó°üΧ¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø