ÌâÄ¿ÄÚÈÝ

£¨¼×´¼ÊÇÖØÒªµÄ»¯Ñ§¹¤Òµ»ù´¡Ô­ÁϺÍÇå½àÒºÌåȼÁÏ£¬Ëü¹ã·ºÓÃÓÚÓлúºÏ³É¡¢Ò½Ò©¡¢Å©Ò©¡¢Í¿ÁÏ¡¢È¾ÁÏ¡¢Æû³µºÍ¹ú·ÀµÈ¹¤ÒµÖС£¹¤ÒµÉÏÒ»°ãÔÚºãÈÝÃܱÕÈÝÆ÷ÖвÉÓÃÏÂÁз´Ó¦ºÏ³É¼×´¼£º
CO(g)2H2(g)CH3OH(g)Q
ϱíËùÁÐÊý¾ÝÊÇ·´Ó¦ÔÚ²»Í¬Î¶ÈÏµĻ¯Ñ§Æ½ºâ³£Êý£¨K£©¡£
ζÈ
250¡æ
300¡æ
350¡æ
K
2.041
0.270
0.012
 
£¨1£©ÅжϷ´Ó¦´ïµ½Æ½ºâ״̬µÄÒÀ¾ÝÊÇ£¨  £©
A£®»ìºÏÆøÌåµÄÃܶȲ»±ä
B£®»ìºÏÆøÌåµÄƽ¾ùÏà¶Ô·Ö×ÓÖÊÁ¿²»±ä
C£®Éú³ÉCH3OHµÄËÙÂÊÓëÏûºÄCOµÄËÙÂÊÏàµÈ
D£®CH3OH¡¢CO¡¢H2µÄŨ¶È¶¼²»ÔÙ·¢Éú±ä»¯
£¨2£©ÓɱíÖÐÊý¾ÝÅжÏQ        0 £¨Ìî¡°£¾¡±¡¢¡°¡±»ò¡°£¼¡±£©£¬ÒªÌá¸ßCOת»¯ÂÊ£¬¿É²ÉÈ¡µÄ´ëÊ©
ÊÇ£¨  £©
A£®¼ÓÈë´ß»¯¼Á       B£®³äÈëCO       C£®³äÈëH2      D£®ÉýÎÂ
£¨3£©Ä³Î¶ÈÏ£¬½«2 mol COºÍ6 mol H2³äÈë2 LµÄÃܱÕÈÝÆ÷ÖУ¬³ä·Ö·´Ó¦10minºó£¬´ïµ½Æ½ºâʱ²âµÃcmol£¯L£¬ÔòÒÔCH3OH±íʾµÄ·´Ó¦ËÙÂÊv           mol /(L¡¤min)£¬
COµÄת»¯ÂÊΪ               ¡£
£¨4£©Ô­ÁÏCOºÍH2¿ÉÒÔÓÉCºÍH2O·´Ó¦ÖÆÈ¡£¬Éæ¼°µÄ·´Ó¦·½³ÌʽÈçÏ£º
C(s)CO2(g) 2CO(g)              Æ½ºâ³£ÊýK1
C(s)H2O(g) CO(g)H2(g)         Æ½ºâ³£ÊýK2
CO(g)H2O(g) H2(g)CO2(g)       Æ½ºâ³£ÊýK3
ÔòK1¡¢K2¡¢K3Ö®¼äµÄ¹ØÏµÊÇ£º                       ¡£

£¨1£©BD  (2·Ö)
£¨2£©>(1·Ö)¡¢C (1·Ö)
£¨3£©0.08  (1·Ö)       80%  (1·Ö)
£¨4£©K2=K1¡¤K3 (2·Ö)

ÊÔÌâ·ÖÎö£º
£¨1£©AºãÈÝÃܱÕÈÝÆ÷£¬Ìå»ý²»±ä£¬¶¼ÊÇÆøÌ壬ÖÊÁ¿Êغ㣬»ìºÏÆøÌåµÄÃܶÈʼÖÕ²»±ä£¬²»ÄÜ×öƽºâ±êÖ¾£¬´íÎó£»BÕýÈ·£»CÉú³ÉCH3OHºÍÏûºÄCOµÄËÙÂÊÊÇͬÏòËÙÂÊ£¬´íÎó£»DÕýÈ·¡£
£¨2£©Óɱí¿ÉÖª£¬TÉý¸ß£¬K¼õС£¬Õý·´Ó¦ÊÇ·ÅÈÈ·´Ó¦£¬Q>0¡£Ìá¸ßCOת»¯ÂÊ£¬·´Ó¦ÕýÏò½øÐУ¬Ñ¡C¡£
£¨3£© CO(g)2H2(g)CH3OH(g)Q
³õŨ¶È£º  1    3               0
±äŨ¶È   0.8   1.6             0.8    
ƽºâ     0.2
v0.8/10=0.08(mol£¯L¡¤min)
COµÄת»¯ÂÊ=" 0.8" /1*100%=  80%
£¨4£©¢ÙC(s)CO2(g) 2CO(g)     Æ½ºâ³£ÊýK1
¢ÚC(s)H2O(g) CO(g)H2(g)     Æ½ºâ³£ÊýK2
¢ÛCO(g)H2O(g) H2(g)CO2(g)   Æ½ºâ³£ÊýK3
¢Ú=¢Ù+¢Û ËùÒÔK2=K1¡¤K3
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø