ÌâÄ¿ÄÚÈÝ


¾ÛºÏÁòËáÌúÓֳƾÛÌú£¬»¯Ñ§Ê½Îª[Fe2(OH)n(SO4)3£­0.5n]m£¬¹ã·ºÓÃÓÚÎÛË®´¦Àí¡£ÊµÑéÊÒÀûÓÃÁòËá³§ÉÕÔü(Ö÷Òª³É·ÖΪÌúµÄÑõ»¯Îï¼°ÉÙÁ¿FeS¡¢SiO2µÈ)ÖÆ±¸¾ÛÌúºÍÂÌ·¯(FeSO4·7H2O)£¬¹ý³ÌÈçÏÂËùʾ£º

(1)ÑéÖ¤¹ÌÌåW±ºÉÕºó²úÉúµÄÆøÌåÖк¬ÓÐSO2µÄ·½·¨ÊÇ

________________________________________________________________________¡£

(2)ÖÆ±¸ÂÌ·¯Ê±£¬ÏòÈÜÒºXÖмÓÈë¹ýÁ¿__________£¬³ä·Ö·´Ó¦ºó£¬¾­__________²Ù×÷µÃµ½ÈÜÒºY£¬ÔÙ¾­Å¨Ëõ¡¢½á¾§µÈ²½ÖèµÃµ½ÂÌ·¯¡£

(3)ÈÜÒºZµÄpHÓ°Ïì¾ÛÌúÖÐÌúµÄÖÊÁ¿·ÖÊý£¬ÓÃpHÊÔÖ½²â¶¨ÈÜÒºpHµÄ²Ù×÷·½·¨Îª________________________________________________________________________¡£

ÈôÈÜÒºZµÄpHƫС£¬½«µ¼Ö¾ÛÌúÖÐÌúµÄÖÊÁ¿·ÖÊý________(Ìî¡°Æ«´ó¡±»ò¡°Æ«Ð¡¡±)¡£


´ð°¸¡¡(1)½«²úÉúµÄÆøÌåͨÈëÊ¢ÓÐÆ·ºìÈÜÒºµÄСÊÔ¹ÜÖУ¬ÈôÆ·ºìÈÜÒºÍÊÉ«£¬¼ÓÈÈÄָܻ´Ô­É«£¬Ö¤Ã÷ÆøÌåÖк¬ÓÐSO2

(2)Ìúм¡¡¹ýÂË

(3)ȡһС¿épHÊÔÖ½£¬·ÅÔÚ¸ÉÔï¡¢½à¾»µÄ±íÃæÃó(»ò²£Á§Æ¬)ÉÏ£¬ÓøÉÔï¡¢½à¾»µÄ²£Á§°ôպȡ´ý²âÈÜÒº£¬µÎµ½pHÊÔÖ½ÉÏ£¬È»ºóÓë±ê×¼±ÈÉ«¿¨±È½Ï¡¡Æ«Ð¡

½âÎö¡¡(1)ÀûÓÃSO2µÄƯ°×ÐÔÀ´¼ø±ð¶þÑõ»¯Áò¡£

(2)ÈÜÒºÖÐÓÐFe3£«¡¢Fe2£«£¬ÓûÖÆÂÌ·¯£¬Ó¦°ÑFe3£«×ª»¯ÎªFe2£«£¬ËùÒÔÒª¼Ó¹ýÁ¿µÄÌúм¡£

(3)ÓÃpHÊÔÖ½²â¶¨ÈÜÒºµÄpH£¬ÎªÁ˲ⶨµÄ׼ȷÐÔ£¬Ó¦Ñ¡ÓøÉÔï¡¢½à¾»µÄ×°Öá£ÈôpHƫС£¬ËáÐÔ¹ýÇ¿£¬ÔòFe3£«ÄÑÒÔÐγɾÛÌú½ºÌ壬ËùÒÔ¾ÛÌúÖÐÌúµÄÖÊÁ¿·ÖÊýƫС¡£


Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

¼×¡¢ÒÒÁ½Í¬Ñ§Ñо¿Na2SO3ÈÜÒºÓëFeCl3ÈÜÒº·´Ó¦µÄÇé¿ö¡£

²½Öè

²Ù×÷

ÏÖÏó

¢ñ

Ïò2 mL 1 mol·L£­1FeCl3ÈÜÒºÖмÓÈëÒ»¶¨Á¿µÄNa2SO3ÈÜÒº

ÈÜÒºÓÉר»ÆÉ«±äΪºìºÖÉ«£¬²¢ÓÐÉÙÁ¿´Ì¼¤ÐÔÆøÎ¶µÄÆøÌåÒݳö

(1)³£ÎÂÏ£¬FeCl3ÈÜÒºµÄpH________7(Ìî¡°<¡±¡¢¡°>¡±»ò¡°£½¡±)¡£

(2)·ÖÎöºìºÖÉ«²úÉúµÄÔ­Òò¡£

¢Ù¼×ͬѧÈÏΪ²½Öè¢ñÖÐÈÜÒº³ÊºìºÖÉ«ÊÇÒòΪÉú³ÉÁËFe(OH)3£¬Óû¯Ñ§Æ½ºâÒÆ¶¯Ô­Àí½âÊÍÈÜÒº³ÊºìºÖÉ«µÄÔ­Òò£º________________________________________________________________________¡£

¢ÚÒÒͬѧÈÏΪ¿ÉÄÜÊÇ·¢ÉúÁËÑõ»¯»¹Ô­·´Ó¦£¬Íê³É²¢Å䯽Æä·´Ó¦µÄÀë×Ó·½³Ìʽ£º

Fe3£«£«SO£«________——Fe2£«£«________£«________

ÒÒͬѧ²éÔÄ×ÊÁϵÃÖª£º

ⅰ.Fe2£«Óë·´Ó¦Éú³ÉÄ«ÂÌÉ«µÄÐõ×´³ÁµíFeSO3£»

ⅱ.Ä«ÂÌÉ«µÄFeSO3Óë»ÆÉ«µÄFeCl3ÈÜÒº»ìºÏºó£¬ÈÜÒº³ÊºìºÖÉ«¡£

(3)¼×ͬѧΪÁËÈ·ÈÏÈÜÒº³ÊºìºÖÉ«µÄÔ­ÒòÊÇÉú³ÉÁËFe(OH)3£¬Éè¼Æ²¢Íê³ÉÁËÈçÏÂʵÑ飺

²½Öè

²Ù×÷

ÏÖÏó

¢ò

Óü¤¹â±ÊÕÕÉä²½Öè¢ñÖеĺìºÖÉ«ÈÜÒº

³öÏÖ¡°¶¡´ï¶ûЧӦ¡±

¼×ͬѧÒò´ËµÃ³ö½áÂÛ£ºÈÜÒº³ÊºìºÖÉ«ÊÇÒòΪÉú³ÉÁËFe(OH)3¡£¶øÒÒͬѧÈÏΪ¼×ͬѧµÃ³ö½áÂÛµÄÖ¤¾ÝÈÔÈ»²»×㣬ÒÒͬѧµÄÀíÓÉÊÇ________________________________________________________________________¡£

(4)Ϊ½øÒ»²½È·ÈÏNa2SO3ÈÜÒºÓëFeCl3ÈÜÒº·´Ó¦µÄÇé¿ö£¬ÒÒͬѧÉè¼Æ²¢Íê³ÉÁËÈçÏÂʵÑ飺

²½Öè

²Ù×÷

ÏÖÏó

¢ó

Ïò1 mol·L£­1µÄFeCl3ÈÜÒºÖÐͨÈëÒ»¶¨Á¿µÄSO2

ÈÜÒºÓÉ»ÆÉ«±äΪºìºÖÉ«

¢ô

Óü¤¹â±ÊÕÕÉä²½Öè¢óÖеĺìºÖÉ«ÈÜÒº

ûÓгöÏÖ¡°¶¡´ï¶ûЧӦ¡±

¢Ù¾­¼ìÑé²½Öè¢óÖкìºÖÉ«ÈÜÒºº¬ÓÐFe2£«£¬¼ìÑéFe2£«Ñ¡ÓõÄÊÔ¼ÁÊÇ________(Ìî×Öĸ)¡£

a£®K3[Fe(CN)6]ÈÜÒº

b£®KSCNÈÜÒº

c£®KMnO4ÈÜÒº

¢ÚÒÑÖªH2SO3ÊÇÈõËᣬÇë½áºÏµçÀë·½³Ìʽ˵Ã÷²½Öè¢óÖгöÏÖºìºÖÉ«µÄÔ­Òò£º________________________________________________________________________¡£

(5)½áÂÛ£ºÓÉÉÏÊöʵÑéµÃÖª£¬¼×¡¢ÒÒÁ½Í¬Ñ§Ëù³Ö¹Ûµã¾ùÕýÈ·¡£


ĿǰÁ÷ÐеĹØÓÚÉúÃüÆðÔ´¼ÙÉèµÄÀíÂÛÈÏΪ£¬ÉúÃüÆðÔ´ÓÚÔ¼40ÒÚÄêǰµÄ¹ÅÑóµ×µÄÈÈÒº»·¾³£¬ÕâÖÖ»·¾³ÏµÍ³ÖÐÆÕ±é´æÔÚÌúÁò´Ø½á¹¹£¬ÈçFe2S2¡¢Fe4S4¡¢Fe8S7µÈ£¬ÕâЩÌúÁò´Ø½á¹¹²ÎÓëÁËÉúÃüÆðÔ´µÄÏà¹Ø·´Ó¦¡£Ä³»¯Ñ§ÐËȤС×éÔÚÑо¿Ä³ÌúÁò´Ø½á¹¹µÄ×é³Éʱ£¬Éè¼ÆÁËÏÂÁÐʵÑé¡£

¡¾ÊµÑé¢ñ¡¿¡¡È·¶¨ÁòµÄÖÊÁ¿£º

°´Í¼Á¬½Ó×°Ö㬼ì²éºÃ×°ÖÃµÄÆøÃÜÐÔºó£¬ÔÚÓ²Öʲ£Á§¹ÜAÖзÅÈë1.0 gÌúÁò´Ø½á¹¹(º¬Óв¿·Ö²»·´Ó¦µÄÔÓÖÊ)£¬ÔÚÊÔ¹Ü BÖмÓÈë50 mL 0.100 mol·L£­1µÄËáÐÔKMnO4ÈÜÒº£¬ÔÚÊÔ¹ÜCÖмÓÈëÆ·ºìÈÜÒº¡£Í¨Èë¿ÕÆø²¢¼ÓÈÈ£¬·¢ÏÖ¹ÌÌåÖð½¥×ª±äΪºìרɫ¡£´ý¹ÌÌåÍêȫת»¯ºó£¬½«BÖÐÈÜÒº×ªÒÆÖÁ 250 mL ÈÝÁ¿Æ¿£¬Ï´µÓÊÔ¹ÜBºó¶¨ÈÝ¡£È¡25.00 mL ¸ÃÈÜÒºÓÃ0.01 mol·L£­1µÄ²ÝËá(H2C2O4)ÈÜÒºµÎ¶¨Ê£ÓàµÄ KMnO4¡£¼Ç¼Êý¾ÝÈçÏ£º

µÎ¶¨´ÎÊý

´ý²âÈÜÒºÌå»ý/mL

²ÝËáÈÜÒºÌå»ý/mL

µÎ¶¨Ç°¿Ì¶È

µÎ¶¨ºó¿Ì¶È

1

25.00

1.50

23.70

2

25.00

1.02

26.03

3

25.00

0.00

24.99

Ïà¹Ø·´Ó¦£º¢Ù2MnO£«2H2O£«5SO2===2Mn2£«£«5SO£«4H£«

¢Ú2MnO£«6H£«£«5H2C2O4===2Mn2£«£«10CO2¡ü£«8H2O

¡¾ÊµÑé¢ò¡¿¡¡È·¶¨ÌúµÄÖÊÁ¿£º

½«ÊµÑé¢ñÓ²Öʲ£Á§¹ÜAÖеIJÐÁô¹ÌÌå¼ÓÈëÏ¡ÑÎËáÖУ¬³ä·Ö½Á°èºó¹ýÂË£¬ÔÚÂËÒºÖмÓÈë×ãÁ¿µÄNaOHÈÜÒº£¬¹ýÂ˺óÈ¡ÂËÔü£¬¾­³ä·ÖׯÉÕµÃ0.6 g¹ÌÌå¡£

ÊԻشðÏÂÁÐÎÊÌ⣺

(1)Åжϵζ¨ÖÕµãµÄ·½·¨ÊÇ______________________________________________

________________________________________________________________________¡£

(2)ÊÔ¹ÜCÖÐÆ·ºìÈÜÒºµÄ×÷ÓÃÊÇ_____________________________________________¡£

ÓÐͬѧÌá³ö£¬³·È¥C×°ÖöÔʵÑéûÓÐÓ°Ï죬ÄãµÄ¿´·¨ÊÇ________(Ñ¡ÌͬÒ⡱»ò¡°²»Í¬Ò⡱)£¬ÀíÓÉÊÇ___________________________________________________

________________________________________________________________________¡£

(3)¸ù¾ÝʵÑé¢ñºÍʵÑé¢òÖеÄÊý¾Ý¿ÉÈ·¶¨¸ÃÌúÁò´Ø½á¹¹µÄ»¯Ñ§Ê½Îª________________________________________________________________________¡£

¡¾ÎÊÌâ̽¾¿¡¿¡¡µÎ¶¨¹ý³ÌÖУ¬Ï¸ÐĵÄͬѧ·¢ÏÖ¸ÃKMnO4ÈÜÒºÑÕÉ«ÍÊÈ¥µÄËÙÂÊ½ÏÆ½³£µÎ¶¨Ê±Òª¿ìµÃ¶à¡£ÎªÑо¿ËÙÂʼӿìµÄÔ­Òò£¬¸Ãͬѧ¼ÌÐø½øÐÐÁËÏÂÁÐʵÑ飬ʵÑéÊý¾ÝÈçÏÂ±í£º

񅧏

ζÈ/¡æ

ËữµÄH2C2O4ÈÜÒº/mL

KMnO4ÈÜÒº/mL

ÈÜÒºÍÊɫʱ¼ä/s

1

25

5.0

2.0

40

2

25

5.0(Áí¼ÓÉÙÁ¿¿ÉÈÜÓÚË®µÄMnSO4·ÛÄ©)

2.0

4

3

60

5.0

2.0

25

(4)·ÖÎöÉÏÊöÊý¾Ý£¬µÎ¶¨¹ý³ÌÖз´Ó¦ËÙÂʼӿìµÄÒ»ÖÖ¿ÉÄÜÔ­ÒòÊÇ___________________

________________________________________________________________________¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø