ÌâÄ¿ÄÚÈÝ

ÒÑÖª¨DNH3Á¬ÔÚ±½»·ÉÏÏÔ¼îÐÔ Á¬ÔÚ±½»·ÉÏÏÔÖÐÐÔ£¬»¯Ñ§Ê½ÎªC7H7NO2µÄÓлúÎïÖÐÆä·Ö×ӽṹÖÐÓÐÒ»¸ö±½»·£¬Á½¸ö²àÁ´£¨¼ä룩£¬·ûºÏÏÂÁÐÌõ¼þµÄ½á¹¹¼òʽΪ£º

£¨1£©¼ÈÓÐËáÐÔÓÖÓмîÐÔ               £»

£¨2£©Ö»ÓÐËáÐÔ                     £»

£¨3£©Ö»ÓмîÐÔ                       £»

£¨4£©ÏÔÖÐÐÔ                       ¡£

£¨5£©ÓÉÓÚ¨DCOOHÄܸú¨DNH2Ðγɠ £¬ËùÒÔ¿ÉÓÃÒÒ¶þ´¼¡¢¶Ô±½¶þ¼×Ëá¸úÉÏÊö¼ÈÏÔËáÐÔÓÖÏÔ¼îÐÔµÄÎïÖÊ·¢Éú·´Ó¦£¬Éú³É¸ß·Ö×Ó»¯ºÏÎï[(C17H13NO5)]¡£¸Ã»¯ºÏÎïΪ¸ßÇ¿¶ÈÏËά²ÄÁÏ£¬Æä½á¹¹¼òʽΪ                                     ¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
»¯ºÏÎïA¡¢B¾ùÊÇ·Ö×ÓʽΪC8H8O3µÄÎÞɫҺÌ壬¾ùÄÑÈÜÓÚË®£®´ÓA¡¢B¿ªÊ¼£¬¿É·¢ÉúͼʾµÄһϵÁз´Ó¦£¨·´Ó¦ÖеÄÎÞ»úÎïÒѲ¿·ÖÂÔÈ¥£©£¬EµÄ±½»·ÉϵÄÒ»ÔªÏõ»ù»¯ÎïÖ»ÓÐÁ½ÖÖ£¬K¿É·¢ÉúÒø¾µ·´Ó¦£®

£¨1£©Ð´³öAºÍKµÄ½á¹¹¼òʽ£ºA
K
HCOOCH3
HCOOCH3
£»XÓëK»¥ÎªÍ¬·ÖÒì¹¹ÌåÇÒÒ²¿É·¢ÉúÒø¾µ·´Ó¦£¬ÔòXËùº¬¹ÙÄÜÍŵÄΪ
£®
£¨2£©ÉÏͼa-iµÄ·´Ó¦ÖУ¬ÊôÓÚõ¥»¯·´Ó¦µÄÓÐ
e¡¢i
e¡¢i
£¨Ìî×Öĸ£©
£¨3£©Ð´³ö·´Ó¦aµÄ»¯Ñ§·½³ÌʽÊÇ
£®
£¨4£©ÒÑÖªCH3COONa+NaOH
CaO
¸ßÎÂ
CH4¡ü+Na2CO3£¬ÇëÍê³ÉE¡úDµÄ·´Ó¦·½³Ìʽ
£®
£¨5£©ÊµÑéÊÒÅäÖÆÒø°±ÈÜÒºµÄÖ÷Òª²Ù×÷ÊÇ
ÔڽྻµÄÊÔ¹ÜÀï¼ÓÈë1mL2%µÄÏõËáÒøÈÜÒº£¬È»ºóÒ»±ßÒ¡¶¯ÊÔ¹ÜÒ»±ßÖðµÎµÎÈë2%µÄÏ¡°±Ë®£¬ÖÁ×î³õ²úÉúµÄ³ÁµíÇ¡ºÃÍêÈ«ÈܽâΪֹ£¬¼´ÅäµÃÒø°±ÈÜÒº
ÔڽྻµÄÊÔ¹ÜÀï¼ÓÈë1mL2%µÄÏõËáÒøÈÜÒº£¬È»ºóÒ»±ßÒ¡¶¯ÊÔ¹ÜÒ»±ßÖðµÎµÎÈë2%µÄÏ¡°±Ë®£¬ÖÁ×î³õ²úÉúµÄ³ÁµíÇ¡ºÃÍêÈ«ÈܽâΪֹ£¬¼´ÅäµÃÒø°±ÈÜÒº
д³öKÓëÒø°±ÈÜÒº·´Ó¦µÄÀë×Ó·½³ÌʽΪ
HCOOCH3+2Ag£¨NH3£©2++2OH-
¡÷
CH3OH+CO32-+2NH4++2Ag¡ý+2NH3
HCOOCH3+2Ag£¨NH3£©2++2OH-
¡÷
CH3OH+CO32-+2NH4++2Ag¡ý+2NH3

£¨6£©Ã¢Ïã×廯ºÏÎïWÓëA»¥ÎªÍ¬·ÖÒì¹¹ÌåÇÒÂú×ãÒÔÏÂÌõ¼þ£º¢Ù1molWÄÜÓ뺬3molNaOH
µÄÈÜҺǡºÃ·´Ó¦£¬¢Ú±½»·Éϲ»Ö±½ÓÁ¬¼×»ù£¬Ôò·ûºÏÉÏÊöÌõ¼þµÄWµÄͬ·ÖÒì¹¹ÌåÓÐ
10
10
ÖÖ£®

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø