ÌâÄ¿ÄÚÈÝ


ʳÑÎÖк¬ÓÐÒ»¶¨Á¿µÄþ¡¢ÌúµÈÔÓÖÊ£¬¼ÓµâÑÎÖеâµÄËðʧÖ÷ÒªÊÇÓÉÓÚÔÓÖÊ¡¢Ë®·Ö¡¢¿ÕÆøÖеÄÑõÆøÒÔ¼°¹âÕÕ¡¢ÊÜÈȶøÒýÆðµÄ¡£ÒÑÖª£ºÑõ»¯ÐÔ£º

£¾Fe3£«£¾I2£»»¹Ô­ÐÔ£º£¾I£­£»

3I2£«6OH£­£«5I£­£«3H2O£»

KI£«I2KI3

£¨1£©Ä³Ñ§Ï°Ð¡×é¶Ô¼ÓµâÑνøÐÐÈçÏÂʵÑ飺ȡһ¶¨Á¿Ä³¼ÓµâÑÎ(¿ÉÄܺ¬ÓÐKIO3¡¢KI¡¢Mg2£«¡¢Fe3£«)£¬ÓÃÊÊÁ¿ÕôÁóË®Èܽ⣬²¢¼ÓÏ¡ÑÎËáËữ£¬½«ËùµÃÈÜÒº·ÖΪ3·Ý¡£µÚÒ»·ÝÊÔÒºÖеμÓKSCNÈÜÒººóÏÔºìÉ«£»µÚ¶þ·ÝÊÔÒºÖмÓ×ãÁ¿KI¹ÌÌ壬ÈÜÒºÏÔµ­»ÆÉ«£¬ÓÃCCl4ÝÍÈ¡£¬Ï²ãÈÜÒºÏÔ×ϺìÉ«£»µÚÈý·ÝÊÔÒºÖмÓÈëÊÊÁ¿KIO3¹ÌÌåºó£¬µÎ¼Óµí·ÛÊÔ¼Á£¬ÈÜÒº²»±äÉ«¡£

¢Ù¼ÓKSCNÈÜÒºÏÔºìÉ«£¬¸ÃºìÉ«ÎïÖÊÊÇ_________£¨Óû¯Ñ§Ê½±íʾ£©£»CCl4ÖÐÏÔ×ϺìÉ«µÄÎïÖÊÊÇ___________________£¨Óõç×Óʽ±íʾ£©¡£

¢ÚµÚ¶þ·ÝÊÔÒºÖмÓÈë×ãÁ¿KI¹ÌÌåºó£¬·´Ó¦µÄÀë×Ó·½³ÌʽΪ___________________________¡¢______________________________________¡£

£¨2£©KI×÷Ϊ¼Óµâ¼ÁµÄʳÑÎÔÚ±£´æ¹ý³ÌÖУ¬ÓÉÓÚ¿ÕÆøÖÐÑõÆøµÄ×÷Óã¬ÈÝÒ×ÒýÆðµâµÄËðʧ¡£

д³ö³±Êª»·¾³ÏÂKIÓëÑõÆø·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º_____________________________¡£

½«I2ÈÜÓÚKIÈÜÒº£¬ÔÚµÍÎÂÌõ¼þÏ£¬¿ÉÖÆµÃKI3¡¤H2O¡£¸ÃÎïÖÊ×÷ΪʳÑμӵâ¼ÁÊÇ·ñºÏÊÊ£¿______£¨Ìî¡°ÊÇ¡±»ò¡°·ñ¡±£©£¬²¢ËµÃ÷ÀíÓÉ________________________________________¡£

£¨3£©ÎªÁËÌá¸ß¼ÓµâÑΣ¨Ìí¼ÓKI£©µÄÎȶ¨ÐÔ£¬¿É¼ÓÎȶ¨¼Á¼õÉÙµâµÄËðʧ¡£ÏÂÁÐÎïÖÊÖÐÓпÉÄÜ×÷ΪÎȶ¨¼ÁµÄÊÇ___________________¡£

A£®Na2S2O3               B£®AlCl3        C£®Na2CO3            D£®NaNO2

£¨4£©¶Ôº¬Fe2£«½Ï¶àµÄʳÑÎ(¼ÙÉè²»º¬Fe3£«)£¬¿ÉÑ¡ÓÃKI×÷Ϊ¼Óµâ¼Á¡£ÇëÉè¼ÆÊµÑé·½°¸£¬¼ìÑé¸Ã¼ÓµâÑÎÖеÄFe2£«£º__________________________________________________________________________¡£


¡¾½âÎö¡¿£¨1£©¢ÙFe3£«ÓëSCN£­µÄÅäºÏ²úÎïÓжàÖÖ£¬Èç¡¢µÈ£»I2µÄCCl4ÈÜÒºÏÔ×ϺìÉ«¡£¢ÚÓ¦ÓÃÐÅÏ¢£º¡°Ñõ»¯ÐÔ£º£¾Fe3£«£¾I2¡±£¬ËµÃ÷ºÍFe3£«¾ùÄÜÑõ»¯I£­Éú³ÉI2¡£

£¨2£©KI±»³±Êª¿ÕÆøÑõ»¯£¬²»ÄÜд³ÉI£­£«O2£«H£«¡ú£¬ÒªÁªÏµ½ðÊôÎüÑõ¸¯Ê´£¬²úÎïI2£«KOHËÆºõ²»ºÏÀí(»á·´Ó¦)£¬Ó¦¿¼ÂÇ»ºÂý·´Ó¦£¬Î¢Á¿²úÎïI2»áÉý»ªºÍKOHÓë¿ÕÆøÖÐCO2·´Ó¦¡£

KI3¡¤H2O×÷¼Óµâ¼ÁÎÊÌ⣬±È½ÏÄÑ·ÖÎö£¬ÒòΪKI3ºÜİÉú¡£´ÓÌâÖУº¡°µÍÎÂÌõ¼þÏ¿ÉÖÆµÃ¡±»òÉú»îÖв¢ÎÞÕâһʹÓÃʵÀýÀ´È¥È·¶¨¡£ÔÙ¸ù¾ÝÐÅÏ¢£º¡°KI£«I2KI3¡±½âÎöÆä²»Îȶ¨ÐÔ¡£

£¨3£©¸ù¾ÝÐÅÏ¢¡°»¹Ô­ÐÔ£º£¾I£­¡±¿ÉÅжÏA£»C±È½ÏÄÑ·ÖÎö£¬Ó¦¿¼ÂÇʳÑγ±½âÖ÷ÒªÊÇMg2£«¡¢Fe3£«ÒýÆð£¬¼ÓNa2CO3ÄÜʹ֮ת»¯ÎªÄÑÈÜÎDÖÐNaNO2ÄÜÑõ»¯I¨D¡£

£¨4£©ÊµÑé·½°¸¼ò´ðҪעÒâ¹æ·¶ÐÔ£¬¡°ÈçÈ¡¡­¼ÓÈë¡­ÏÖÏó¡­½áÂÛ¡­¡±£¬±¾ÊµÑéI¨D¶ÔFe2£«µÄ¼ìÑéÓиÉÈÅ£¬ÓùýÁ¿ÂÈË®ÓÖ¿ÉÄÜÑõ»¯SCN£­£¬µ±È»Êµ¼Ê²Ù×÷ÄÜÅжϣ¬²»¹ý¶Ô³Ì¶ÈºÃµÄͬѧÀ´Ëµ£¬ÓÃÆÕ³ʿÀ¶³Áµí·¨È·¶¨ÐÔÇ¿¡£

¡¾´ð°¸¡¿£¨1£©¢ÙFe(SCN)3      

¢ÚIO3£­£«5I£­£«6H£«=3I2£«3H2O   2Fe3£«£«2I£­=2Fe2£«£«I2

£¨2£©O2£«4I£­£«2H2O=2I2£«4KOH

·ñ  KI3ÔÚÊÜÈÈ£¨»ò³±Êª£©Ìõ¼þϲúÉúI2ºÍKI£¬KI±»ÑõÆøÑõ»¯£¬I2Ò×Éý»ª¡£

£¨3£©AC

£¨4£©È¡×ãÁ¿¸Ã¼ÓµâÑÎÈÜÓÚÕôÁóË®ÖУ¬ÓÃÑÎËáËữ£¬µÎ¼ÓÊÊÁ¿Ñõ»¯¼Á£¨È磺ÂÈË®¡¢¹ýÑõ»¯ÇâµÈ£©£¬ÔٵμÓKSCNÈÜÓÚ£¬ÈôÏÔѪºìÉ«£¬Ôò¸Ã¼ÓµâÑÎÖдæÔÚFe2+¡£


Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø