ÌâÄ¿ÄÚÈÝ


ÏÂÁÐʵÑéÖУ¬Ëù²ÉÈ¡µÄ·ÖÀë·½·¨Óë¶ÔÓ¦Ô­Àí¶¼ÕýÈ·µÄÊÇ£¨    £©

Ñ¡Ïî

Ä¿µÄ

·ÖÀë·½·¨

Ô­Àí

A£®

CO2ÖлìÓеÄÉÙÁ¿CO

ͨÈëÊÊÁ¿O2µãȼ

CO»áȼÉÕ³ÉCO2

B£®

³ýÈ¥¼¦µ°Ç彺ÌåÖлìÓеÄNaCl

¹ýÂË

¼¦µ°Ç彺Ìå²»ÄÜͨ¹ýÂËÖ½

C£®

³ýÈ¥NaHCO3¹ÌÌåÖлìÓеÄNa2CO3

¼ÓÈÈ

NaHCO3ÊÜÈÈ·Ö½â

D£®

³ýÈ¥BaSO4·ÛÄ©ÖлìÓеÄBaCO3

ÑÎËáÈܽâºó¹ýÂË¡¢Ï´µÓ

ÑÎËá¿ÉÈܽâBaCO3£¬²»ÈܽâBaSO4

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

ij¿ÎÍâÐËȤС×éΪ̽¾¿Ä³ÖÖÂÁºÏ½ð£¨ºÏ½ðÔªËØÎªMg ºÍAl£©ÊÇ·ñ·ûºÏ¹ú¼ÒÖÊÁ¿±ê×¼£¨¹ú¼Ò¹æ¶¨ÆäÖÐÂÁº¬Á¿²»ÄܵÍÓÚ78£¥£©£¬Éè¼ÆÏÂͼװÖýøÐÐʵÑé¡£

£¨1£©ÈçºÎ¼ìÑé¸Ã×°ÖÃµÄÆøÃÜÐÔ                                                                                     ¡£

£¨2£©ºÏ½ðÑùÆ·¹ÌÌåMÓëÇâÑõ»¯ÄÆÈÜÒº·´Ó¦µÄÀë×Ó·½³Ìʽ                                         ¡£

£¨3£©·´Ó¦Ç°ÏȵÚÒ»´Î¶ÁÈ¡Á¿Æø¹ÜÒºÃæ¿Ì¶È£¬È»ºóÇãб×ó±ß×°ÖÃʹÇâÑõ»¯ÄÆÈÜÒº(×ãÁ¿)Óëa gºÏ½ð·ÛÄ©(¹ÌÌåM)³ä·Ö·´Ó¦£¬´ý·´Ó¦Í£Ö¹ºó£¬ÆøÌåζȻָ´µ½ÊÒΣ¬ÏëÒªµÚ¶þ´Î¶ÁÈ¡Á¿Æø¹ÜÒºÃæ¿Ì¶ÈǰÐèÒª½øÐеÄÒ»²½²Ù×÷ÊÇ                 ¡£Í¨¹ý¶ÁÈ¡ÒºÃæ²î£¬²¢½«ÆøÌåÌå»ýÕÛËã³É±ê×¼×´¿öÏÂÌå»ýΪV mL¡£ÈôÁ¿Æø¹Ü×î´óÁ¿³ÌΪ50 mL£¬Ôò¹ÌÌåMÖÐÂÁµÄÖÊÁ¿(mA1)·¶Î§Îª                                     ¡£

£¨4£©Èôa£½38 mg£¬V£½44.8 mL(±ê×¼×´¿ö)£¬Çëͨ¹ý¼ÆËã˵Ã÷¸ÃºÏ½ðÊÇ·ñ·ûºÏ¹ú¼Ò±ê×¼                                (Ìî¡°·ûºÏ¡±»ò¡°²»·ûºÏ¡±)¡£

£¨5£©Èô½«×°ÖÃÖеÄÇâÑõ»¯ÄÆÈÜÒºÌæ»»Îª×ãÁ¿µÄÑÎËᣬÔò·´Ó¦Í£Ö¹ºóÁ¿Æø¹ÜÄÚÆøÌåÌå»ý                                      (Ìî¡°£¾¡±¡°£¼¡±¡°£½¡±)V mL¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø