ÌâÄ¿ÄÚÈÝ


Çâ·úËá(HF)ÊÇÒ»ÖÖÈõËá¡£25¡æÊ±£¬Ïò20mLO.1mol•L-1Çâ·úËáÖмÓÈëVmL0.1mol•L-1NaOHÈÜÒº³ä·Ö·´Ó¦¡£ÒÑÖª: HF(aq)+OH-(aq)¨TF-(aq)+H2O(1)   ¡÷H= - 67.7kJ•mol-1£¬

H+(aq)+OH-(aq)¨TH2O(1)   ¡÷H¨T - 57.3kJ•mol-  ¸ù¾ÝÌâÒ⣬ÏÂÁÐÅжϻò½áÂÛÕýÈ·µÄÊÇ

A.Çâ·úËáµÄµçÀë¹ý³ÌÊÇÎüÈȵÄ

B.µ±V=20ʱ£¬ÈÜÒºÖÐ:c(F-)£¼c(Na+)=0.1mol•L-1

C.µ±V£¼20ʱ£¬ÈÜÒºÖÐÀë×ÓŨ¶È¹ØÏµ¿ÉÄÜΪ:c(Na+)=c(F-)

D.µ±V£¾20ʱ£¬ÈÜÒºÖÐÀë×ÓŨ¶È¹ØÏµÒ»¶¨Îª:c(Na+)£¾c(F-)£¾c(OH-)£¾c(H+)

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

£¨1£©Ð´³öÏÂͼÖÐÐòºÅ¢Ù¡«¢ÛÒÇÆ÷µÄÃû³Æ£º

¢Û

 
    

         

                I                     II                   III

¢Ù                £»   ¢Ú                   £»   ¢Û                    ¡£

£¨2£©ÒÇÆ÷¢Ù¡«¢ÜÖУ¬Ê¹ÓÃʱ±ØÐë¼ì²éÊÇ·ñ©ˮµÄÓÐ              ¡££¨ÌîÒÇÆ÷ÐòºÅ£©

£¨3£©ÏÂͼÊÇijѧУʵÑéÊÒ´Ó»¯Ñ§ÊÔ¼ÁÉ̵êÂò»ØµÄŨÁòËáÊÔ¼Á±êÇ©ÉϵIJ¿·ÖÄÚÈÝ¡£ÏÖÓøÃŨÁòËáÅäÖÆ480 mL 1 mol¡¤ L£­1µÄÏ¡ÁòËá¡£

¿É¹©Ñ¡ÓõÄÒÇÆ÷ÓУº¢Ù½ºÍ·µÎ¹Ü ¢ÚÉÕÆ¿ ¢ÛÉÕ±­ ¢Ü²£Á§°ô ¢ÝÒ©³× ¢ÞÁ¿Í² ¢ßÍÐÅÌÌìÆ½¡£

Çë»Ø´ðÏÂÁÐÎÊÌ⣺

a£®¸ÃÁòËáµÄÎïÖʵÄÁ¿Å¨¶ÈΪ             mol¡¤L£­1¡£

b£®ÅäÖÆÏ¡ÁòËáʱ£¬»¹È±ÉÙµÄÒÇÆ÷ÓÐ           (дÒÇÆ÷Ãû³Æ)¡£

c£®¾­¼ÆË㣬ÅäÖÆ480mL  1mol¡¤ L£­1µÄÏ¡ÁòËáÐèÒªÓÃÁ¿Í²Á¿È¡ÉÏÊöŨÁòËáµÄÌå»ýΪ          mL¡£

d£®¶ÔËùÅäÖÆµÄÏ¡ÁòËá½øÐвⶨ£¬·¢ÏÖÆäŨ¶ÈСÓÚ1 mol¡¤L£­1£¬ÅäÖÆ¹ý³ÌÖÐÏÂÁи÷Ïî²Ù×÷¿ÉÄÜÒýÆð¸ÃÎó²îµÄÔ­ÒòÓР             ¡££¨Ìî×Öĸ£©                           

A£®¶¨ÈÝʱ£¬¸©ÊÓÈÝÁ¿Æ¿¿Ì¶ÈÏß½øÐж¨ÈÝ         

B£®½«Ï¡ÊͺóµÄÁòËáδ¾­ÀäÈ´Ö±½Ó×ªÒÆÖÁÈÝÁ¿Æ¿ÖÐ

C£®×ªÒÆÈÜҺʱ£¬²»É÷½«ÉÙÁ¿ÈÜÒºÈ÷µ½ÈÝÁ¿Æ¿ÍâÃæ

D£®ËùÓÃÈÝÁ¿Æ¿¾­ÕôÁóˮϴµÓºóδ¸ÉÔÓÐÉÙÁ¿²ÐÁôÕôÁóË®

E£®¶¨Èݺ󣬰ÑÈÝÁ¿Æ¿µ¹ÖÃÒ¡ÔȺó·¢ÏÖÒºÃæµÍÓڿ̶ÈÏߣ¬ÔÙµÎË®ÖÁ¿Ì¶ÈÏß´¦

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø