ÌâÄ¿ÄÚÈÝ
ÏÖÓÐij»ìºÏÎïµÄÎÞɫ͸Ã÷ÈÜÒº£¬¿ÉÄܺ¬ÓÐÒÔÏÂÀë×ÓÖеÄÈô¸ÉÖÖ£º
Na£«¡¢NH4£«¡¢Cl£¡¢Mg2£«¡¢Ba2£«¡¢CO32£¡¢SO42££¬ÏÖÈ¡Èý·Ý¸÷100mLÈÜÒº½øÐÐÈçÏÂʵÑ飺
¢ÙµÚÒ»·Ý¼ÓÈë×ãÁ¿AgNO3ÈÜÒºÓгÁµí²úÉú£¬¼Ó×ãÁ¿Ï¡ÏõËáºó³Áµí²¿·ÖÈܽ⣻
¢ÚµÚ¶þ·Ý¼Ó×ãÁ¿NaOHÈÜÒº³ä·Ö¼ÓÈȺó£¬ÊÕ¼¯µ½ÆøÌå0.896L(±ê×¼×´¿ö)£»
¢ÛµÚÈý·Ý¼Ó×ãÁ¿BaCl2ÈÜÒººó£¬¹ýÂ˺ó³ä·Ö¸ÉÔïµÃµ½³Áµí6.27g£¬ÔÙ¾×ãÁ¿Ï¡ÏõËáÏ´µÓ¡¢¸ÉÔïºó£¬³ÁµíÖÊÁ¿±äΪ2.33g¡£¸ù¾ÝÉÏÊöʵÑéÏÖÏóºÍÓйØÊý¾Ý£¬»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©ÔÈÜÒºÖÐÒ»¶¨´æÔÚµÄÒõÀë×ÓÊÇ £¬Ò»¶¨²»´æÔÚµÄÀë×ÓÊÇ £¬¿ÉÄÜ´æÔÚµÄÀë×ÓÊÇ ¡£
£¨2£©¢ÚÖз¢Éú»¯Ñ§·´Ó¦µÄÀë×Ó·½³ÌʽΪ ¡£
£¨3£©¢ÛÖÐÉú³É¿ÉÈÜÓÚÏ¡ÏõËáµÄ³Áµí»¯Ñ§Ê½Îª £¬ÎïÖʵÄÁ¿Îª mol,¸Ã³ÁµíÈÜÓÚÏ¡ÏõËáµÄÀë×Ó·½³ÌʽΪ ¡£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿