题目内容

已知101 k Pa时辛烷的燃烧热为-5518 kJ· mol1。则下列热化学方程式书写正确的是

A.2C8H18 + 25O2 = 16CO2 + 18H2O△H =-11036 kJ·mol1
B.2C8H18(l) + 25O2(g) = 16CO2(g) + 18H2O(l)△H =-11036 kJ·mol1
C.2C8H18(l) + 25O2(g) = 16CO2(g) + 18H2O(g)△H =-11036 kJ·mol1
D.2C8H18(l) + 25O2(g) = 16CO2(g))+18H2O(l)△H =-5518kJ·mol1

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