题目内容
已知101 k Pa时辛烷的燃烧热为－5518 kJ· mol－1。则下列热化学方程式书写正确的是
A．2C8H18+ 25O2 = 16CO2 + 18H2O △H =－11036 kJ·mol－1
B．2C8H18(l)+ 25O2(g) = 16CO2(g) + 18H2O(l) △H =－11036 kJ·mol－1
C．2C8H18(l)+ 25O2(g) = 16CO2(g) + 18H2O(g) △H =－11036 kJ·mol－1
D．2C8H18(l)+ 25O2(g) = 16CO2(g)）+18H2O(l) △H =－5518kJ·mol－1
B
解析:略
练习册系列答案
相关题目
已知101 k Pa时辛烷的燃烧热为－5518 kJ· mol－1。则下列热化学方程式书写正确的是
| A．2C8H18 + 25O2 = 16CO2 + 18H2O △H =－11036 kJ·mol－1 |
| B．2C8H18(l) + 25O2(g) = 16CO2(g) + 18H2O(l) △H =－11036 kJ·mol－1 |
| C．2C8H18(l) + 25O2(g) = 16CO2(g) + 18H2O(g) △H =－11036 kJ·mol－1 |
| D．2C8H18(l) + 25O2(g) = 16CO2(g)）+18H2O(l) △H =－5518kJ·mol－1 |
已知101 k Pa时辛烷的燃烧热为－5518 kJ· mol－1。则下列热化学方程式书写正确的是
| A．2C8H18 + 25O2 = 16CO2 + 18H2O△H =－11036 kJ·mol－1 |
| B．2C8H18(l) + 25O2(g) = 16CO2(g) + 18H2O(l)△H =－11036 kJ·mol－1 |
| C．2C8H18(l) + 25O2(g) = 16CO2(g) + 18H2O(g)△H =－11036 kJ·mol－1 |
| D．2C8H18(l) + 25O2(g) = 16CO2(g)）+18H2O(l)△H =－5518kJ·mol－1 |