ÌâÄ¿ÄÚÈÝ
ÓйØÈÈ»¯Ñ§·½³ÌʽÊéдÓë¶ÔÓ¦±íÊö¾ùÕýÈ·µÄÊÇ
- A.Ï¡´×ËáÓë0.1 mol/LNaOHÈÜÒº·´Ó¦£ºH+(aq)+OH-(aq) = H2O(l)¡÷H = -57.3kJ/mol
- B.ÇâÆøµÄȼÉÕÈÈΪ285.5 kJ/mol£¬ÔòË®·Ö½âµÄÈÈ»¯Ñ§·½³Ìʽ£º
2H2O(l)=2H2(g)+O2(g)¡÷H = +285.5kJ/mol - C.ÃܱÕÈÝÆ÷ÖУ¬9.6 gÁò·ÛÓë11. 2 gÌú·Û»ìºÏ¼ÓÈÈÉú³ÉÁò»¯ÑÇÌú17 .6 gʱ£¬·Å³ö19.12 kJÈÈÁ¿¡£ÔòFe(s)+S(s)=FeS(s)¡÷H=" -" 95£®6KJ/mol
- D.ÒÑÖª2C(s)+O2(g)=2CO(g)¡÷H=-221 kJ/mol£¬Ôò¿ÉÖªCµÄȼÉÕÈÈΪ110.5 kJ/mol
C
´×ËáÊÇÈõËᣬ´æÔÚµçÀëÆ½ºâ£¬¶øµçÀëÊÇÎüÈȵģ¬ËùÒÔÏ¡´×ËáÓë0.1 mol/LNaOHÈÜÒº·´Ó¦£¬Éú³É1molˮʱ·Å³öµÄÈÈÁ¿ÒªÐ¡ÓÚ57.3kJ¡£È¼ÉÕÈÈÊÇÖ¸1mol¿ÉȼÎïÍêȫȼÉÕÉú³ÉÎȶ¨µÄÑõ»¯Îïʱ·Å³öµÄÈÈÁ¿£¬ËùÒÔB¡¢D²»ÕýÈ·¡£17 .6 gÁò»¯ÑÇÌúÊÇ
£¬Òò´ËÉú³É1molÁò»¯ÑÇÌú·Å³öµÄÈÈÁ¿ÊÇ
£¬ËùÒÔ´ð°¸ÊÇC¡£
´×ËáÊÇÈõËᣬ´æÔÚµçÀëÆ½ºâ£¬¶øµçÀëÊÇÎüÈȵģ¬ËùÒÔÏ¡´×ËáÓë0.1 mol/LNaOHÈÜÒº·´Ó¦£¬Éú³É1molˮʱ·Å³öµÄÈÈÁ¿ÒªÐ¡ÓÚ57.3kJ¡£È¼ÉÕÈÈÊÇÖ¸1mol¿ÉȼÎïÍêȫȼÉÕÉú³ÉÎȶ¨µÄÑõ»¯Îïʱ·Å³öµÄÈÈÁ¿£¬ËùÒÔB¡¢D²»ÕýÈ·¡£17 .6 gÁò»¯ÑÇÌúÊÇ
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿