ÌâÄ¿ÄÚÈÝ
ij»¯Ñ§Ñ§Ï°Ð¡×éͬѧ¶ÔʵÑéÊÒÖÆÈ¡°±ÆøºÍ°±ÆøµÄ»¹ÔÐԵȽøÐÐÁËÒÔÏÂ̽¾¿£¬ÇëÄã²ÎÓë²¢Íê³É¶ÔÓйØÎÊ ÌâµÄ½â´ð¡£
[×ÊÁÏ»ñϤ]
¢Ù°±ÆøÓëCuO·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º3CuO+2NH3
3Cu+N2+3H2O
¢ÚCu2O·ÛÄ©³ÊºìÉ«£»Cu2OÊǼîÐÔÑõ»¯ÎÔÚËáÐÔÈÜÒºÖÐCu+²»Îȶ¨£¬Ò×ת»¯ÎªCu ºÍCu2+ £ºCu+
Cu+Cu2+ ¡£
¢ÛÔÚ¿ÕÆøÖиßÎÂׯÉÕʱ£ºCu2OÎȶ¨¡¢²»·Ö½â£¬¶øCuO½«·Ö½âÉú³ÉCu2OºÍO2¡£
[ʵÑéÉè¼Æ]
[×ÊÁÏ»ñϤ]
¢Ù°±ÆøÓëCuO·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º3CuO+2NH3
¢ÚCu2O·ÛÄ©³ÊºìÉ«£»Cu2OÊǼîÐÔÑõ»¯ÎÔÚËáÐÔÈÜÒºÖÐCu+²»Îȶ¨£¬Ò×ת»¯ÎªCu ºÍCu2+ £ºCu+
¢ÛÔÚ¿ÕÆøÖиßÎÂׯÉÕʱ£ºCu2OÎȶ¨¡¢²»·Ö½â£¬¶øCuO½«·Ö½âÉú³ÉCu2OºÍO2¡£
[ʵÑéÉè¼Æ]
[ʵÑé̽¾¿]
£¨1£©A×°ÖÃÊǰ±ÆøµÄ·¢Éú×°Öã¬ÔòʵÑéǰ´óÊÔ¹ÜÖÐÓ¦¼ÓÈëµÄÒ©Æ·ÊÇ____________¡£
£¨2£©¼×ͬѧÈÏΪ¸ÃʵÑéÉè¼ÆÓÐÒ»¶¨µÄȱÏÝ£¬A×°ÖòúÉúµÄ°±ÆøÖк¬ÓÐË®ÕôÆø£¬Ó°ÏìÁËʵÑé½áÂÛ£¬Ó¦ÔÚAºÍBÖ®¼äÔö¼ÓÒ»¸ö×°ÓÐ___________£¨ÌîÒ©Æ·Ãû³Æ£©µÄ¸ÉÔï×°Öá£
£¨3£©ÀûÓøĽøºóµÄ×°ÖýøÐÐʵÑ飬¿É¹Û²ìµ½B×°ÖÃÖеÄÏÖÏóΪºÚÉ«¹ÌÌå±ä³ÉºìÉ«£¬C×°ÖÃÖеÄÏÖÏóΪ____________ ¡£
[½»Á÷ÌÖÂÛ]
£¨4£©ÒÒͬѧÈÏΪNH3ÓëCuO·´Ó¦Éú³ÉµÄºìÉ«ÎïÖÊÖпÉÄܺ¬ÓÐCu2O(Ñõ»¯ÑÇÍ)¡£ÏÖÓÐŨÏõËᡢϡÁòËᡢϡÏõËá¡¢ÇâÑõ»¯ÄÆÈÜÒº¼°pHÊÔÖ½£¬ÓÃ×î¼ò±ãµÄʵÑé·½·¨Ö¤Ã÷ºìÉ«¹ÌÌåÖÐÊÇ·ñº¬ÓÐCu2OËùҪѡÓõÄÊÔ¼ÁÊÇ____________¡£
£¨5£©±ûͬѧÈÏΪ¿Éͨ¹ý¸ßÎÂׯÉÕºìÉ«¹ÌÌ壬²¢³ÆÁ¿·´Ó¦Ç°ºó¹ÌÌåÖÊÁ¿µÄ±ä»¯À´È·¶¨ÊÇ·ñº¬ÓÐCu2O¡£ËûÏȳƸÉÔïÛáÛöµÄÖÊÁ¿Îªa g£¬ÔÙÈ¡ºìÉ«¹ÌÌåÖÃÓÚÛáÛöÖгƵÃ×ÜÖÊÁ¿Îªb g£¬ÔÚ¿ÕÆøÖиßÎÂׯÉÕÖÁÖÊÁ¿ºã¶¨£¬×îºó³ÆµÃ×ÜÖÊÁ¿Îªc g¡£ÈôÈ·ÈϺìÉ«¹ÌÌåÖÐÖ»º¬ÓÐCu£¬Ôò¾¸ßÎÂׯÉÕºóµÃµ½µÄÎïÖÊÊÇ____________¡£ÈôÈ·ÈϺìÉ«¹ÌÌåÖк¬ÓÐCu2O£¬Ôòa¡¢b¡¢cÓ¦·ûºÏÊýѧ¹ØÏµÎªc< ____________ ¡£
[ÍØÕ¹ÑÓÉì]
£¨6£©¶¡Í¬Ñ§ÈÏΪÀûÓÃÉÏÊöʵÑéÉè¼Æ¸Ä½øºóµÄ×°Öû¹¿É²â¶¨CuµÄÏà¶ÔÔ×ÓÖÊÁ¿£¬ËûÊÇͨ¹ý²â¶¨·´Ó¦ÎïCuOµÄÖÊÁ¿ºÍÉú³ÉÎïH2OµÄÖÊÁ¿À´Íê³ÉµÄ¡£ÈôʵÑé²âµÃÍêÈ«·´Ó¦µÄCuOºÍÉú³ÉµÄH2OµÄÖÊÁ¿·Ö±ðΪm(CuO)¡¢m(H2O)£¬Ôò¾Ý´Ë¼ÆËãCuµÄÏà¶ÔÔ×ÓÖÊÁ¿µÄ´úÊýʽΪ_________¡£
£¨1£©A×°ÖÃÊǰ±ÆøµÄ·¢Éú×°Öã¬ÔòʵÑéǰ´óÊÔ¹ÜÖÐÓ¦¼ÓÈëµÄÒ©Æ·ÊÇ____________¡£
£¨2£©¼×ͬѧÈÏΪ¸ÃʵÑéÉè¼ÆÓÐÒ»¶¨µÄȱÏÝ£¬A×°ÖòúÉúµÄ°±ÆøÖк¬ÓÐË®ÕôÆø£¬Ó°ÏìÁËʵÑé½áÂÛ£¬Ó¦ÔÚAºÍBÖ®¼äÔö¼ÓÒ»¸ö×°ÓÐ___________£¨ÌîÒ©Æ·Ãû³Æ£©µÄ¸ÉÔï×°Öá£
£¨3£©ÀûÓøĽøºóµÄ×°ÖýøÐÐʵÑ飬¿É¹Û²ìµ½B×°ÖÃÖеÄÏÖÏóΪºÚÉ«¹ÌÌå±ä³ÉºìÉ«£¬C×°ÖÃÖеÄÏÖÏóΪ____________ ¡£
[½»Á÷ÌÖÂÛ]
£¨4£©ÒÒͬѧÈÏΪNH3ÓëCuO·´Ó¦Éú³ÉµÄºìÉ«ÎïÖÊÖпÉÄܺ¬ÓÐCu2O(Ñõ»¯ÑÇÍ)¡£ÏÖÓÐŨÏõËᡢϡÁòËᡢϡÏõËá¡¢ÇâÑõ»¯ÄÆÈÜÒº¼°pHÊÔÖ½£¬ÓÃ×î¼ò±ãµÄʵÑé·½·¨Ö¤Ã÷ºìÉ«¹ÌÌåÖÐÊÇ·ñº¬ÓÐCu2OËùҪѡÓõÄÊÔ¼ÁÊÇ____________¡£
£¨5£©±ûͬѧÈÏΪ¿Éͨ¹ý¸ßÎÂׯÉÕºìÉ«¹ÌÌ壬²¢³ÆÁ¿·´Ó¦Ç°ºó¹ÌÌåÖÊÁ¿µÄ±ä»¯À´È·¶¨ÊÇ·ñº¬ÓÐCu2O¡£ËûÏȳƸÉÔïÛáÛöµÄÖÊÁ¿Îªa g£¬ÔÙÈ¡ºìÉ«¹ÌÌåÖÃÓÚÛáÛöÖгƵÃ×ÜÖÊÁ¿Îªb g£¬ÔÚ¿ÕÆøÖиßÎÂׯÉÕÖÁÖÊÁ¿ºã¶¨£¬×îºó³ÆµÃ×ÜÖÊÁ¿Îªc g¡£ÈôÈ·ÈϺìÉ«¹ÌÌåÖÐÖ»º¬ÓÐCu£¬Ôò¾¸ßÎÂׯÉÕºóµÃµ½µÄÎïÖÊÊÇ____________¡£ÈôÈ·ÈϺìÉ«¹ÌÌåÖк¬ÓÐCu2O£¬Ôòa¡¢b¡¢cÓ¦·ûºÏÊýѧ¹ØÏµÎªc< ____________ ¡£
[ÍØÕ¹ÑÓÉì]
£¨6£©¶¡Í¬Ñ§ÈÏΪÀûÓÃÉÏÊöʵÑéÉè¼Æ¸Ä½øºóµÄ×°Öû¹¿É²â¶¨CuµÄÏà¶ÔÔ×ÓÖÊÁ¿£¬ËûÊÇͨ¹ý²â¶¨·´Ó¦ÎïCuOµÄÖÊÁ¿ºÍÉú³ÉÎïH2OµÄÖÊÁ¿À´Íê³ÉµÄ¡£ÈôʵÑé²âµÃÍêÈ«·´Ó¦µÄCuOºÍÉú³ÉµÄH2OµÄÖÊÁ¿·Ö±ðΪm(CuO)¡¢m(H2O)£¬Ôò¾Ý´Ë¼ÆËãCuµÄÏà¶ÔÔ×ÓÖÊÁ¿µÄ´úÊýʽΪ_________¡£
£¨1£©NH4Cl £¬ Ca(OH)2
£¨2£©¼îʯ»Ò
£¨3£©ÎÞË®CuSO4±ä³ÉÀ¶É«
£¨4£©Ï¡H2SO4
£¨5£©Cu2O £»
£¨6£©
£¨2£©¼îʯ»Ò
£¨3£©ÎÞË®CuSO4±ä³ÉÀ¶É«
£¨4£©Ï¡H2SO4
£¨5£©Cu2O £»
£¨6£©
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿