ÌâÄ¿ÄÚÈÝ

£¨10·Ö£©25ʱ£¬Èç¹ûÈ¡0.1 mol¡¤L-1HAÈÜÒºÓë0.1 mol¡¤L-1NaOHÈÜÒºµÈÌå»ý»ìºÏ(»ìºÏºóÈÜÒºÌå»ýµÄ±ä»¯²»¼Æ)£¬²âµÃ»ìºÏÈÜÒºµÄpH=8£¬ÊԻشðÒÔÏÂÎÊÌ⣺
£¨1£©»ìºÏÈÜÒºµÄpH=8µÄÔ­Òò                                    £¨ÓÃÀë×Ó·½³Ìʽ±íʾ£©£»
£¨2£©»ìºÏÈÜÒºÖÐÓÉË®µçÀë³öµÄc(H+)__    ___0.1 mol¡¤L-1 NaOHÈÜÒºÖÐÓÉË®µçÀë³öµÄc(H+)£»(Ìî>¡¢<¡¢=)
£¨3£©ÒÑÖªNH4AÈÜҺΪÖÐÐÔ£¬ÓÖÖª½«HAÈÜÒº¼Óµ½Na2CO3ÈÜÒºÖÐÓÐÆøÌå·Å³ö£¬ÊÔÍÆ¶Ï
(NH4)2CO3ÈÜÒºµÄpH       7 (Ìî>¡¢<¡¢=)£»
£¨4£©½«ÏàͬζÈÏÂÏàͬŨ¶ÈµÄËÄÖÖÑÎÈÜÒº£º

A£®NH4HCO3B£®NH4AC£®£¨NH4£©2SO4D£®NH4Cl
°´pHÓÉ´óµ½Ð¡µÄ˳ÐòÅÅÁР                     £¨ÌîÐòºÅ£©

£¨10·Ö£© (1)A-+H2OHA+ OH-  £¨3·Ö£©
(2) >  £¨2·Ö£©   (3) >  £¨2·Ö£©  (4)  ABDC £¨3·Ö£©

½âÎö

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø