Question

£¨1£©ÒÑÖª:

Fe£¨s£©+1/2O₂£¨g£©=FeO£¨s£©    

2Al£¨s£©+3/2O₂£¨g£©= Al₂O₃£¨s£© 

AlºÍFeO·¢ÉúÂÁÈÈ·´Ó¦µÄÈÈ»¯Ñ§·½³ÌʽÊÇ

_____________________________________________________¡£

£¨2£©·´Ó¦ÎïÓëÉú³ÉÎï¾ùΪÆø̬µÄij¿ÉÄæ·´Ó¦ÔÚ²»Í¬Ìõ¼þϵķ´Ó¦Àú³Ì·Ö±ðΪA¡¢B£¬ÈçÏÂͼËùʾ¡£

¢Ù¾ÝͼÅжϸ÷´Ó¦ÊÇ_____(Ìî¡°Îü¡±»ò¡°·Å¡±) ÈÈ·´Ó¦£¬µ±·´Ó¦´ïµ½Æ½ºâ

 ºó£¬ÆäËûÌõ¼þ²»±ä£¬Éý¸ßζȣ¬·´Ó¦ÎïµÄת»¯ÂÊ__  _  

 (Ìî¡°Ôö´ó¡±¡¢¡°¼õС¡±»ò¡°²»±ä¡±)

¢ÚÆäÖÐBÀú³Ì±íÃ÷´Ë·´Ó¦²ÉÓõÄÌõ¼þΪ______ (Ñ¡ÌîÏÂÁÐ

ÐòºÅ×Öĸ)

A£®Éý¸ßζȠ                B£®Ôö´ó·´Ó¦ÎïµÄŨ¶È

C£®½µµÍζȠ               D£®Ê¹ÓÃÁË´ß»¯¼Á

£¨3£©1000¡æʱ£¬ÁòËáÄÆÓëÇâÆø·¢ÉúÏÂÁз´Ó¦£ºNa₂SO₄(s) + 4H₂(g)  Na₂S(s) + 4H₂O(g) ¡£

¢Ù¸Ã·´Ó¦µÄƽºâ³£Êý±í´ïʽΪ____________________¡£ÒÑÖªK_1000¡æ£¼K_1200¡æ£¬Ôò¸Ã·´Ó¦ÊÇ________·´Ó¦£¨Ìî¡°ÎüÈÈ¡±»ò¡°·ÅÈÈ¡±£©¡£

¢ÚÓÃÓйØÀë×Ó·½³Ìʽ˵Ã÷ÉÏÊö·´Ó¦ËùµÃ¹ÌÌå²úÎïµÄË®ÈÜÒºµÄËá¼îÐÔ_______                 _____

£¨4£©³£ÎÂÏ£¬Èç¹ûÈ¡0.1mol¡¤L^£­1HAÈÜÒºÓë0.1mol¡¤L^£­1NaOHÈÜÒºµÈÌå»ý»ìºÏ£¨»ìºÏºóÈÜÒºÌå»ýµÄ±ä»¯ºöÂÔ²»¼Æ£©£¬²âµÃ»ìºÏÒºµÄpH£½8£¬Çë»Ø´ðÏÂÁÐÎÊÌ⣺

¢Ù»ìºÏÈÜÒºÖÐË®µçÀë³öµÄc(H^£«)Óë0.1mol¡¤L^£­1NaOHÈÜÒºÖÐË®µçÀë³öµÄc(H^£«)±È½Ï

                  £¨Ì¡¢£¾¡¢£½£©¡£

¢ÚÒÑÖªNH₄AÈÜҺΪÖÐÐÔ£¬ÓÖÖª½«HAÈÜÒº¼Óµ½Na₂CO₃ÈÜÒºÖÐÓÐÆøÌå·Å³ö£¬ÊÔÍƶÏ(NH₄)₂CO₃ÈÜÒºµÄpH             7£¨Ì¡¢£¾¡¢£½£©£»ÏàͬζÈÏ£¬µÈÎïÖʵÄÁ¿Å¨¶ÈµÄÏÂÁÐÑÎÈÜÒº°´pHÓÉ´óµ½Ð¡µÄÅÅÁÐ˳ÐòΪ                          ¡££¨ÌîÐòºÅ£©

a.£®NH₄HCO₃       b£®NH₄A          c£®(NH₄)₂CO₃       d£®NH₄Cl

Answer 1

£¨1£©^{3FeO£¨s£©+ 2Al£¨s£©=Al2O3£¨s£©+3Fe£¨s£©     ¡÷H=£­859£®7kJ/mol}£¨2·Ö£©

£¨2£©¢ÙÎü£¨1·Ö£©£»Ôö´ó£¨1·Ö£©¢ÚD£¨1·Ö£©

£¨3£©¢ÙK=£¬£¨2·Ö£©  ÎüÈÈ£»£¨1·Ö£©

¢ÚS^2¡ª + H₂O  HS^¡ª + OH^¡ª£¨2·Ö£©

£¨4£©¢Ù£¾£¨2·Ö£©    ¢Ú£¾£¨2·Ö£©  c£¾a£¾b£¾d£¨2·Ö£©