ÌâÄ¿ÄÚÈÝ

£¨11·Ö£©A¡¢B¡¢C¡¢DËÄÖÖÔªËØ¶¼ÊǶÌÖÜÆÚÔªËØ£¬AÔªËØµÄÀë×Ó¾ßÓлÆÉ«µÄÑæÉ«·´Ó¦¡£A¡¢BÔªËØµÄÀë×ӽṹºÍNe¾ßÓÐÏàͬµÄµç×Ó²ãÅŲ¼£»5.8 g BµÄÇâÑõ»¯ÎïÇ¡ºÃÄÜÓë100 mL 2 mol¡¤L¡ª1ÑÎËáÍêÈ«·´Ó¦£»BÔ­×ÓºËÖÐÖÊ×ÓÊýºÍÖÐ×ÓÊýÏàµÈ¡£H2ÔÚCµ¥ÖÊÖÐȼÉÕ²úÉú²Ô°×É«»ðÑæ¡£ CµÄ×î¸ß¼ÛÑõ»¯ÎïµÄË®»¯ÎïÊÇËùÓк¬ÑõËáÖÐËáÐÔ×îÇ¿µÄ£»DÔªËØÔ­×ӵĵç×Ó²ã½á¹¹ÖУ¬×îÍâ²ãµç×ÓÊýÊÇ´ÎÍâ²ãµç×ÓÊýµÄ3±¶¡£¸ù¾ÝÉÏÊöÌõ¼þ»Ø´ð£º

£¨1£©ÔªËØCλÓÚµÚ__________ÖÜÆÚµÚ__________×壬ËüµÄ×î¸ß¼ÛÑõ»¯ÎïµÄË®»¯ÎïµÄ»¯Ñ§Ê½Îª____________¡£

£¨2£©AÔªËØÊÇ_______£¬BÔªËØÊÇ______£¬DÔªËØÊÇ______¡££¨Ð´ÔªËØ·ûºÅ£©

£¨3£©AÓëDÐγɵÄÔ­×Ó¸öÊý±ÈΪ2:1µÄ»¯ºÏÎïµÄ»¯Ñ§Ê½ÊÇ___ _ ____£¬

Óõç×Óʽ±íʾËüµÄÐγɹý³Ì                                        

£¨4£©CÔªËØµÄµ¥ÖÊÓж¾£¬¿ÉÓÃAµÄ×î¸ß¼ÛÑõ»¯Îï¶ÔÓ¦µÄË®»¯ÎïµÄÈÜÒºÎüÊÕ£¬

ÆäÀë×Ó·½³ÌʽΪ______________________________ __________________¡£

 

¡¾´ð°¸¡¿

£¨1£©Èý  VIIA  HClO4£¨2£©Na  Mg  O  £¨3£©Na2O  ÂÔ

£¨4£©Cl2 + 2OH=  Cl+ ClO - + H2O

¡¾½âÎö¡¿

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø