ÌâÄ¿ÄÚÈÝ

¢ñ£¨4·Ö£©ÓÃÔªËØ·ûºÅ»ò»¯Ñ§Ê½»Ø´ðÔ­×ÓÐòÊý11¡«18µÄÔªËØµÄÓйØÎÊÌ⣺

£¨1£©³ýÏ¡ÓÐÆøÌåÍ⣬ԭ×Ó°ë¾¶×î´óµÄÔªËØÊÇ________________£»

£¨2£©×î¸ß¼ÛÑõ»¯Îï¶ÔӦˮ»¯Îï³ÊÁ½ÐÔµÄÔªËØÊÇ________________£»

£¨3£©×î¸ßÕý¼ÛÑõ»¯Îï¶ÔӦˮ»¯ÎïËáÐÔ×îÇ¿µÄËáÊÇ________________£»

£¨4£©ÄÜÐÎ³ÉÆøÌ¬Ç⻯ÎïÇÒÇ⻯Îï×îÎȶ¨µÄÔªËØÊÇ________________¡£

¢ò£¨4·Ö£©ÔÚMgCl2ºÍAlCl3µÄ»ìºÍÈÜÒºÖУ¬ÖðµÎ¼ÓÈëNaOHÈÜÒºÖ±ÖÁ¹ýÁ¿£¬¾­²â¶¨£¬¼ÓÈëNaOHµÄÎïÖʵÄÁ¿ºÍËùµÃ³ÁµíµÄÎïÖʵÄÁ¿µÄ¹ØÏµÈçÏÂͼËùʾ£¬ÔòÈÜÒºÖÐn(Mg2+):n(Al3+)=            £¬AB¶Î·¢ÉúµÄÀë×Ó·´Ó¦Îª                             ¡£

 

¡¾´ð°¸¡¿

¢ñ£¨Ã¿¿Õ1·Ö£©(1)Na  £¨2£©Al £¨3£©HClO4 (4)Cl

¢ò(ÿ¿Õ2·Ö)1£º1 £¬A1(OH)3 + OH£­ = [A1(OH)4] £­

¡¾½âÎö¡¿

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø