ÌâÄ¿ÄÚÈÝ

½ñÓТÙCH3COOH£»¢ÚHCl£»¢ÛH2SO4ÈýÖÖÈÜÒº£¬Ñ¡ÔñÌî¿Õ£º

A£®¢Ù£¾¢Ú£¾¢Û    B£®¢Ù£¼¢Ú£¼¢Û   C£®¢Ù=¢Ú=¢Û    E£®¢Ù£¾¢Ú=¢Û  

D£®¢Ù=¢Û£¾¢Ú     F£®¢Ù£¼¢Ú=¢Û     G£®¢Ù=¢Ú£¼¢Û   H£®¢Ù=¢Ú£¾¢Û

(1)µ±ËüÃÇpHÏàͬʱ£¬ÆäÎïÖʵÄÁ¿Å¨¶È¹ØÏµÊÇ___________¡£

(2)Ìå»ýºÍÎïÖʵÄÁ¿Å¨¶ÈÏàͬµÄ¢Ù¡¢¢Ú¡¢¢ÛÈýÈÜÒº£¬·Ö±ðÓëͬŨ¶ÈµÄÉÕ¼îÈÜÒº·´Ó¦£¬ÒªÊ¹·´Ó¦ºóµÄÈÜÒº³ÊÖÐÐÔ£¬ËùÐèÉÕ¼îÈÜÒºµÄÌå»ý¹ØÏµÎª_________________¡£

(3)µ±ËüÃÇpHÏàͬ¡¢Ìå»ýÏàͬʱ£¬·Ö±ð¼ÓÈë×ãÁ¿Ð¿£¬Ôò¿ªÊ¼Ê±·´Ó¦ËÙÂÊ_________£¬Ïàͬ״¿öϲúÉúÆøÌåÌå»ý¹ØÏµÎª____________¡£

(4)ijѧÉúÓÃ0.2000mol/L NaOHÈÜÒºµÎ¶¨Î´ÖªÅ¨¶ÈµÄÑÎËáÈÜÒº£¬Æä²Ù×÷¿É·Ö½âΪÈçϼ¸²½£º

£¨A£©ÒÆÈ¡20.00mL´ý²âµÄÑÎËáÈÜҺעÈë½à¾»µÄ×¶ÐÎÆ¿£¬²¢¼ÓÈë2-3µÎ·Ó̪

£¨B£©Óñê×¼ÈÜÒºÈóÏ´µÎ¶¨¹Ü2-3´Î

£¨C£©°ÑÊ¢Óбê×¼ÈÜÒºµÄ¼îʽµÎ¶¨¹Ü¹Ì¶¨ºÃ£¬µ÷½ÚÒºÃæÊ¹µÎ¶¨¹Ü¼â×ì³äÂúÈÜÒº

£¨D£©È¡±ê×¼NaOHÈÜҺעÈë¼îʽµÎ¶¨¹ÜÖÁ0¿Ì¶ÈÒÔÉÏ2-3cm

£¨E£©µ÷½ÚÒºÃæÖÁ0»ò0¿Ì¶ÈÒÔÏ£¬¼Ç϶ÁÊý

£¨F£©°Ñ×¶ÐÎÆ¿·ÅÔڵζ¨¹ÜµÄÏÂÃæ£¬Óñê×¼NaOHÈÜÒºµÎ¶¨ÖÁÖյ㣬¼ÇÏµζ¨¹ÜÒºÃæµÄ¿Ì¶È

Íê³ÉÒÔÏÂÌî¿Õ£º

¢ÙÕýÈ·²Ù×÷µÄ˳ÐòÊÇ£¨ÓÃÐòºÅ×ÖĸÌîд£©______________________.

¢ÚʵÑéÖУ¬ÑÛ¾¦Ó¦×¢ÊÓ_______£¬Ö±ÖÁµÎ¶¨Öյ㡣

¢Û¼¸´ÎµÎ¶¨ÏûºÄNaOHÈÜÒºµÄÌå»ýÈçÏÂ:

ʵÑéÐòºÅ

1

2

3

4

ÏûºÄNaOHÈÜÒºµÄÌå»ý(mL)

20.05

20.00

18.80

19.95

Ôò¸ÃÑÎËáÈÜÒºµÄ׼ȷŨ¶ÈΪ_____________¡£(±£ÁôСÊýµãºó4λ)

£¨5£©¡¢Óñê×¼µÄNaOHµÎ¶¨Î´ÖªÅ¨¶ÈµÄÑÎËᣬѡÓ÷Ó̪Ϊָʾ¼Á£¬Ôì³É²â¶¨½á¹ûÆ«¸ßµÄÔ­Òò¿ÉÄÜÊÇ:____________ (´íѡȫ¿Û)

A. ÅäÖÆ±ê×¼ÈÜÒºµÄÇâÑõ»¯ÄÆÖлìÓÐNa2CO3ÔÓÖÊ

B. µÎ¶¨ÖÕµã¶ÁÊýʱ£¬¸©Êӵζ¨¹ÜµÄ¿Ì¶È£¬ÆäËü²Ù×÷¾ùÕýÈ·

C. ʢװδ֪ҺµÄ×¶ÐÎÆ¿ÓÃÕôÁóˮϴ¹ý£¬Î´Óôý²âÒºÈóÏ´

D. µÎ¶¨µ½ÖÕµã¶ÁÊýʱ·¢Ïֵζ¨¹Ü¼â×ì´¦Ðü¹ÒÒ»µÎÈÜÒº

E. δÓñê×¼ÒºÈóÏ´¼îʽµÎ¶¨¹Ü           

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø