ÌâÄ¿ÄÚÈÝ

X¡¢Y¡¢Z¡¢M¡¢R¡¢QÊǶÌÖÜÆÚÖ÷×åÔªËØ£¬²¿·ÖÐÅÏ¢ÈçϱíËùʾ£º

X
Y
Z
M
R
Q
Ô­×Ó°ë¾¶/nm
0.186
0.074
0.099
0.143
Ö÷Òª»¯ºÏ¼Û
-4£¬+4
-2
-1£¬+7
+3
ÆäËü
ÑôÀë×ÓºËÍâÎÞµç×Ó
ÎÞ»ú·Ç½ðÊô²ÄÁϵÄÖ÷½Ç
ÑæÉ«·´Ó¦³Ê»ÆÉ«
 
£¨1£©RÔÚÔªËØÖÜÆÚ±íÖеÄλÖÃÊÇ________________£»RÔÚ×ÔÈ»½çÖÐÓÐÖÊÁ¿ÊýΪ35ºÍ37µÄÁ½ÖÖºËËØ£¬ËüÃÇÖ®¼äµÄ¹ØÏµ»¥Îª________________¡£
£¨2£©ZµÄµ¥ÖÊÓëË®·´Ó¦µÄÀë×Ó·½³ÌʽÊÇ_________________________¡£
£¨3£©¸ù¾Ý±íÖÐÊý¾ÝÍÆ²â£¬YµÄÔ­×Ó°ë¾¶µÄ×îС·¶Î§ÊÇ________________¡£
£¨4£©Z¡¢M¡¢QµÄ¼òµ¥Àë×ÓµÄÀë×Ó°ë¾¶µÄ´óС˳ÐòΪ________________¡£
£¨5£©YÓëRÏà±È£¬·Ç½ðÊôÐÔ½ÏÇ¿µÄÊÇ________________£¨ÓÃÔªËØ·ûºÅ±íʾ£©£¬ÏÂÁÐÊÂʵÄÜÖ¤Ã÷ÕâÒ»½áÂÛµÄÊÇ________________£¨Ñ¡Ìî×ÖĸÐòºÅ£©¡£
a.³£ÎÂÏÂYµÄµ¥ÖʳʹÌ̬£¬RµÄµ¥ÖÊ³ÊÆøÌ¬
b.Îȶ¨ÐÔXR £¾YX4
c.YÓëRÐγɵϝºÏÎïÖÐY³ÊÕý¼Û
£¨6£©¼×¡¢ÒÒÊÇÉÏÊö²¿·ÖÔªËØµÄ×î¸ß¼ÛÑõ»¯ÎïµÄË®»¯ÎÇÒ¼×+ÒÒ¡ú±û+Ë®¡£Èô±ûµÄË®ÈÜÒº³Ê¼îÐÔ£¬Ôò±ûµÄ»¯Ñ§Ê½ÊÇ_______________________________¡£
£¨7£©YµÄµ¥ÖÊÄܺÍZµÄ×î¸ß¼ÛÑõ»¯ÎïµÄË®»¯ÎïµÄË®ÈÜÒº·¢Éú·´Ó¦£¬Éú³ÉÏàͬÌõ¼þÏÂÃܶÈ×îСµÄÆøÌå¡£Çëд³ö¸Ã·´Ó¦µÄ»¯Ñ§·½³Ìʽ_____________________¡£

£¨1£©µÚÈýÖÜÆÚ¢÷A×å£»Í¬Î»ËØ
£¨2£©2Na+2H2O=2Na++2OH¡ª +H2¡ü
£¨3£©´óÓÚ0.099nmСÓÚ0.143nm
£¨4£© O2-£¾Na+£¾Al3+
£¨5£©Cl     b c
£¨6£©NaAlO2»òNa2SiO3
£¨7£©Si+2NaOH+H2O=Na2SiO3+2H2¡ü

½âÎö

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
ÓÐx¡¢Y¡¢Z¡¢M¡¢R¡¢QÁùÖÖ¶ÌÖÜÆÚÖ÷×åÔªËØ£¬²¿·ÖÐÅÏ¢ÈçϱíËùʾ£º
   X  Y  M  R  Q
 Ô­×Ó°ë¾¶/nm      0.186  0.074  0.099  0.160
 Ö÷Òª»¯ºÏ¼Û   -4£¬+4   -2 -1£¬+7  
 ÆäËü  ÑôÀë×ÓºËÍâÎÞµç×Ó  ÎÞ»ú·Ç½ðÊô²ÄÁϵÄÖ÷½Ç  ÁùÖÖÔªËØÖÐÔ­×Ó°ë¾¶×î´ó      ´ÎÍâ²ãµç×ÓÊýÊÇ×îÍâ²ãµç×ÓÊýµÄ4±¶
Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©RÔÚÔªËØÖÜÆÚ±íÖеÄλÖÃÊÇ
µÚÈýÖÜÆÚ¢÷A×å
µÚÈýÖÜÆÚ¢÷A×å
£®
£¨2£©¸ù¾Ý±íÖÐÊý¾ÝÍÆ²â£¬YµÄÔ­×Ó°ë¾¶µÄ×îС·¶Î§ÊÇ
´óÓÚ0.099nm£¬Ð¡ÓÚ0.160nm
´óÓÚ0.099nm£¬Ð¡ÓÚ0.160nm
£®
£¨3£©Z¡¢M¡¢QµÄ¼òµ¥Àë×ÓµÄÀë×Ó°ë¾¶µÄ´óС˳ÐòΪ
O2£¾Na+£¾Mg2+
O2£¾Na+£¾Mg2+
 £¨ÓÃÔªËØ·ûºÅ±íʾ£©£®
£¨4£©YÓëRÏà±È£¬·Ç½ðÊôÐÔ½ÏÇ¿µÄÊÇ
Cl
Cl
 £¨ÓÃÔªËØ·ûºÅ±íʾ£©£¬ÏÂÁÐÊÂʵÄÜÖ¤Ã÷ÕâÒ»½áÂÛµÄÊÇ
bc
bc
 £¨Ñ¡Ìî×ÖĸÐòºÅ£©£®
a£®³£ÎÂÏÂYµÄµ¥ÖʳʹÌ̬£¬RµÄµ¥ÖÊ³ÊÆøÌ¬
b£®Îȶ¨ÐÔXR£¾YX£®
c£®YÓëRÐγɵϝºÏÎïÖÐY³ÊÕý¼Û
£¨5£©X¡¢M¡¢ZÈýÖÖÔªËØ×é³ÉµÄ»¯ºÏÎïÖк¬ÓеĻ¯Ñ§¼üΪ
Àë×Ó¼ü¡¢¹²¼Û¼ü
Àë×Ó¼ü¡¢¹²¼Û¼ü
£»Ð´³öRµÄµ¥ÖÊÓëÉÏÊö»¯ºÏÎïµÄË®ÈÜÒº·´Ó¦µÄÀë×Ó·½³Ìʽ£º
Cl2+2OH=Cl-+ClO-+H2O
Cl2+2OH=Cl-+ClO-+H2O
£®

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø