ÌâÄ¿ÄÚÈÝ
11£®Ð´³öÏÂÁз´Ó¦µÄÈÈ»¯Ñ§·½³Ìʽ£º£¨1£©1mol C2H5OH£¨l£©ÍêȫȼÉÕÉú³ÉCO2£¨g£©ºÍH2O£¨l£©£¬·Å³ö1 366.8kJÈÈÁ¿£ºC2H5OH£¨l£©+3O2£¨g£©=2CO2£¨g£©+3H2O£¨l£©¡÷H=-1366.8KJ/mol£®
£¨2£©1mol C£¨Ê¯Ä«£©ÓëÊÊÁ¿H2O£¨g£©·´Ó¦Éú³ÉCO£¨g£©ºÍH2£¨g£©£¬ÎüÊÕ131.3kJÈÈÁ¿£ºC£¨s£¬Ê¯Ä«£©+H2O £¨g£©=CO£¨g£©+H2 £¨g£©¡÷H=+131.3kJ/mol£®
£¨3£©1.7g NH3£¨g£©·¢Éú´ß»¯Ñõ»¯·´Ó¦Éú³ÉÆøÌ¬²úÎ·Å³ö22.67kJµÄÈÈÁ¿£º4NH3£¨g£©+5O2£¨g£©¨T4NO£¨g£©+6H2O£¨g£©¡÷H=-906.80kJ/mol£®
£¨4£©ÒÑÖªÏÂÁз´Ó¦µÄ·´Ó¦ÈÈΪ
¢ÙCH3COOH£¨l£©+2O2£¨g£©=2CO2£¨g£©+2H2O£¨l£©¡÷H1=-870.3kJ/mol
¢ÚC£¨s£©+O2£¨g£©=CO2£¨g£©¡÷H2=-393.5kJ/mol
¢ÛH2£¨g£©+$\frac{1}{2}$O2£¨g£©=H2O£¨l£©¡÷H3=-285.8kJ/mol
ÊÔ¼ÆËãÏÂÊö·´Ó¦µÄ·´Ó¦ÈÈ£º2C£¨s£©+2H2£¨g£©+O2£¨g£©=CH3COOH£¨l£©¡÷H=-488.3kJ/mol£®
·ÖÎö ÒÀ¾ÝÈÈ»¯Ñ§·½³ÌʽÊéд·½·¨£¬½áºÏÈÈ»¯Ñ§·½³ÌµÄÒâÒå¡¢±ê×¢ÎïÖʾۼ¯×´Ì¬ºÍ¶ÔÓ¦·´Ó¦µÄìʱäд³ö£»
£¨4£©¢ÙCH3COOH£¨l£©+2O2£¨g£©¨T2CO2£¨g£©+2H2O£¨l£©¡÷H1=-870.3kJ/mol
¢ÚC£¨s£©+O2£¨g£©¨TCO2£¨g£©¡÷H2=-393.5kJ/mol
¢ÛH2£¨g£©+$\frac{1}{2}$O2£¨g£©¨TH2O£¨l£©¡÷H3=-258.8kJ/mol
½áºÏ¸Ç˹¶¨ÂÉ¿ÉÖª£¬¢Ú¡Á¢Ú+¢Û¡Á2-¢ÙµÃµ½2C£¨s£©+2H2£¨g£©+O2£¨g£©¨TCH3COOH£¨l£©£¬ÒÔ´ËÀ´½â´ð£®
½â´ð ½â£º£¨1£©1mol C2H5OH£¨l£©ÍêȫȼÉÕÉú³ÉCO2£¨g£©ºÍH2O£¨l£©£¬·Å³ö1366.8KJÈÈÁ¿£¬±ê×¢ÎïÖʾۼ¯×´Ì¬ºÍ¶ÔÓ¦·´Ó¦ìʱäд³öÈÈ»¯Ñ§·½³ÌʽΪ C2H5OH£¨l£©+3O2£¨g£©=2CO2£¨g£©+3H2O£¨l£©¡÷H=-1366.8KJ/mol£¬¹Ê´ð°¸Îª£ºC2H5OH£¨l£©+3O2£¨g£©=2CO2£¨g£©+3H2O£¨l£©¡÷H=-1366.8KJ/mol£»
£¨2£©1mol̼£¨Ê¯Ä«£©ÓëÊÊÁ¿Ë®ÕôÆøÍêÈ«·´Ó¦£¬Éú³ÉÒ»Ñõ»¯Ì¼ÆøÌåºÍÇâÆø£¬ÎüÊÕ131.3KJÈÈÁ¿£¬ÈÈ»¯Ñ§·½³ÌʽΪ£ºC£¨s£©+H2O £¨g£©=CO£¨g£©+H2 £¨g£©¡÷H=+131.3kJ/mol£¬
¹Ê´ð°¸Îª£ºC£¨s£¬Ê¯Ä«£©+H2O £¨g£©=CO£¨g£©+H2 £¨g£©¡÷H=+131.3kJ/mol£»
£¨3£©1.7g ¼´0.1molNH3£¨g£©·¢Éú´ß»¯Ñõ»¯·´Ó¦Éú³ÉÆøÌ¬²úÎ·Å³ö22.67kJµÄÈÈÁ¿£¬ËùÒÔ4molNH3£¨g£©·¢Éú´ß»¯Ñõ»¯·´Ó¦Éú³ÉÆøÌ¬²úÎ·Å³ö22.67kJ¡Á40=906.80kJµÄÈÈÁ¿£¬¼´4NH3£¨g£©+5O2£¨g£©¨T4NO£¨g£©+6H2O£¨g£©¡÷H=-906.80kJ/mol£¬
¹Ê´ð°¸Îª£º4NH3£¨g£©+5O2£¨g£©¨T4NO£¨g£©+6H2O£¨g£©¡÷H=-906.80kJ/mol£»
£¨4£©¢ÙCH3COOH£¨l£©+2O2£¨g£©¨T2CO2£¨g£©+2H2O£¨l£©¡÷H1=-870.3kJ/mol
¢ÚC£¨s£©+O2£¨g£©¨TCO2£¨g£©¡÷H2=-393.5kJ/mol
¢ÛH2£¨g£©+$\frac{1}{2}$O2£¨g£©¨TH2O£¨l£©¡÷H3=-258.8kJ/mol
½áºÏ¸Ç˹¶¨ÂÉ¿ÉÖª£¬¢Ú¡Á¢Ú+¢Û¡Á2-¢ÙµÃµ½2C£¨s£©+2H2£¨g£©+O2£¨g£©¨TCH3COOH£¨l£©£¬¡÷H=£¨-393.5kJ/mol-258.8kJ/mol£©¡Á2-£¨-870.3kJ/mol£©=-488.3kJ/mol£¬
¹Ê´ð°¸Îª£º-488.3kJ/mol£®
µãÆÀ ±¾Ì⿼²éÁËÈÈ»¯Ñ§·½³ÌʽµÄ·ÖÎöÅжϣ¬ÈÈ»¯Ñ§·½³ÌʽµÄ¼ÆËãÓ¦Óã¬×¢ÒâÊéд·½·¨£¬ÕÆÎÕ»ù´¡Êǹؼü£¬ÌâÄ¿½Ï¼òµ¥£®
| A£® | ¸´·½ÇâÑõ»¯ÂÁÓÐÖкÍθËá¡¢½â¾·Ö¹Í´µÄ×÷Óã¬Î¸Í´¡¢Î¸Ëá¹ý¶àµÄ»¼Õ߿ɴóÁ¿·þÓà | |
| B£® | ʳÑοÉ×÷µ÷ζ¼Á£¬Ò²¿É×÷ʳƷ·À¸¯¼Á | |
| C£® | ÌìÈ»´æÔڵֲ͝ÎïÓÍÖ¬¼¸ºõ¶¼ÊÇ»ìºÏÎûÓй̶¨µÄÈ۷еã | |
| D£® | Áò»¯ÇâÊÇ¿ÕÆøÎÛȾÎÓгô¼¦µ°ÆøÎ¶£¬Óо綾 |
| A£® | MµÄÃû³ÆÎªÒì¶¡Íé | |
| B£® | NµÄͬ·ÖÒì¹¹ÌåÓÐ7ÖÖ£¨²»¿¼ÂÇÁ¢ÌåÒì¹¹£¬²»°üÀ¨±¾Éí£© | |
| C£® | Q¿ÉÓëäåË®·´Ó¦Éú³ÉN | |
| D£® | M¡¢N¡¢Q¾ùÄÜʹËáÐÔKMnO4ÈÜÒºÍÊÉ« |
| A£® | N2£¨g£©+3H2£¨g£©?2NH3£¨g£©[ÔÚ»ìºÏÆøÌåÖЦգ¨NH3£©=33.3%] | |
| B£® | CO£¨g£©+H2O£¨g£©?CO2£¨g£©+H2£¨g£©£¨ÔÚºãÈÝÈÝÆ÷ÖУ¬ÈÝÆ÷ÄÚѹǿ²»Ôٸı䣩 | |
| C£® | 2SO2£¨g£©+O2£¨g£©?2SO3£¨g£©£¨ÔÚºãѹÌõ¼þÏ£¬×ÜÖÊÁ¿²»Ôٸı䣩 | |
| D£® | 2NO2£¨g£©?2NO£¨g£©+O2£¨g£©£¨ÔÚºãÈÝÌõ¼þÏ£¬ÆøÌåÑÕÉ«²»Ôٸı䣩 |
¢ÙÖÊ×ÓÊý ¢ÚÖÐ×ÓÊý ¢ÛÖÊÁ¿Êý ¢ÜºËµçºÉÊý ¢ÝºËÍâµç×ÓÊý ¢ÞÔªËØÔÚÖÜÆÚ±íÖеÄλÖã®
| A£® | ¢Ù¢Ú¢Û¢Ü | B£® | ¢Ù¢Ü¢Ý¢Þ | C£® | ¢Ú¢Û¢Ü¢Ý | D£® | ¢Û¢Ü¢Ý¢Þ |
Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨l£©¶ÔÇàÝï½øÐÐÆÆËéµÄÄ¿µÄÊÇÔö´óÇàÝïÓëÒÒÃѵĽӴ¥Ãæ»ý£¬Ìá¸ßÇàÝïËØµÄ½þÈ¡ÂÊ£®
£¨2£©²Ù×÷IÓõ½µÄ²£Á§ÒÇÆ÷ÊÇ©¶·¡¢²£Á§°ô¡¢ÉÕ±£¬²Ù×÷¢òµÄÃû³ÆÊÇÕôÁó£®
£¨3£©ÓÃͼ2ʵÑé×°ÖòⶨÇàÝïËØµÄ»¯Ñ§Ê½£¬½«28.2gÇàÝïËØ·ÅÔÚȼÉÕ¹ÜCÖгä·ÖȼÉÕ£º
¢ÙÒÇÆ÷¸÷½Ó¿ÚµÄÁ¬½Ó˳Ðò´Ó×óµ½ÓÒÒÀ´ÎΪafgdebchi£¨Ã¿¸ö×°ÖÃÏÞÓÃÒ»´Î£©£®A×°ÖÃÖз¢ÉúµÄ»¯Ñ§·´Ó¦·½³ÌʽΪ2H2O2$\frac{\underline{\;MnO_2\;}}{\;}$2H2O+O2¡ü£®
¢Ú×°ÖÃCÖÐCuOµÄ×÷ÓÃÊÇʹÇàÝïËØ³ä·ÖÑõ»¯Éú³ÉCO2ºÍH2O£®
¢Û×°ÖÃDÖеÄÊÔ¼ÁΪŨÁòËᣮ
¢ÜÒÑÖªÇàÝïËØÊÇÌþµÄº¬ÑõÑÜÉúÎÓúÏÀíÁ¬½ÓºóµÄ×°ÖýøÐÐʵÑ飮²âÁ¿Êý¾ÝÈç±í£º
| ×°ÖÃÖÊÁ¿ | ʵÑéǰ/g | ʵÑéºó/g |
| B | 22.6 | 42.4 |
| E£¨²»º¬¸ÉÔï¹Ü£© | 80.2 | 146.2 |
£¨4£©Ä³Ñ§Éú¶ÔÇàÝïËØµÄÐÔÖʽøÐÐ̽¾¿£®½«ÇàÝïËØ¼ÓÈ뺬ÓÐNaOH¡¢·Ó̪µÄË®ÈÜÒºÖУ¬ÇàÝïËØµÄÈܽâ¶È½ÏС£¬¼ÓÈȲ¢½Á°è£¬ÇàÝïËØµÄÈܽâ¶ÈÔö´ó£¬ÇÒÈÜÒººìÉ«±ädz£¬ÓëÇàÝïËØ»¯Ñ§ÐÔÖÊÏàËÆµÄÎïÖÊÊÇC£¨Ìî×Öĸ´úºÅ£©£®
A£®ÒÒ´¼ B£®ÒÒËá C£®ÒÒËáÒÒõ¥ D£®ÆÏÌÑÌÇ£®
| A£® | 0.1 mol/L | B£® | 0.2 mol/L | C£® | 0.3 mo/L | D£® | 0.4 mo/L |