ÌâÄ¿ÄÚÈÝ

°´ÒªÇóдÈÈ»¯Ñ§·½³Ìʽ£º

(1)ÒÑ֪ϡÈÜÒºÖУ¬1 mol¡¡H2SO4ÓëNaOHÈÜҺǡºÃÍêÈ«·´Ó¦Ê±£¬·Å³ö114.6 kJÈÈÁ¿£¬Ð´³ö±íʾH2SO4ÓëNaOH·´Ó¦µÄÖкÍÈÈ»¯Ñ§·½³Ìʽ________£®

(2)25¡æ¡¢101 kPaÌõ¼þϳä·ÖȼÉÕÒ»¶¨Á¿µÄ¶¡Í鯸Ìå·Å³öÈÈÁ¿ÎªQ kJ£¬¾­²â¶¨£¬½«Éú³ÉµÄCO2ͨÈë×ãÁ¿³ÎÇåʯ»ÒË®ÖвúÉú25 g°×É«³Áµí£¬Ð´³ö±íʾ¶¡ÍéȼÉÕÈÈ»¯Ñ§·½³Ìʽ________£®

(3)ÒÑÖªÏÂÁÐÈÈ»¯Ñ§·½³Ìʽ£º

¢ÙCH3COOH(l)£«2O2(g)2CO2(g)£«2H2O(l)¡¡¦¤H1£½£­870.3 kJ/mol

¢ÚC(s)£«O2(g)CO2(g)¡¡¦¤H2£½£­393.5 kJ/mol

¢ÛH2(g)£«O2(g)H2O(l)¡¡¦¤H3£½£­285.8 kJ/mol

д³öÓÉC(s)¡¢H2(g)ºÍO2(g)»¯ºÏÉú³ÉCH3COOH(l)µÄÈÈ»¯Ñ§·½³Ìʽ________£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø