ÌâÄ¿ÄÚÈÝ
ijѧÉúʵÑéÐËȤС×éÄâÓÃͼ1×°ÖÃÀ´Íê³É¡°NaHCO3ºÍNaCl»ìºÏÎïÖÐNaHCO3º¬Á¿µÄ²â¶¨¡±µÄʵÑ飮
(1)¸÷ÒÇÆ÷½Ó¿ÚÁ¬½Ó˳ÐòÊÇ________(ÓýӿÚ×ÖĸÌîд)£®
(2)¸Ã×°ÖÃÁ¬½ÓºÃ¶øÎ´×°Ò©Æ·Ç°£¬¼ìÑ鯸ÃÜÐԵIJÙ×÷ÊÇ________£®
(3)¼×ͬѧÈÏΪÉÏÊö·½·¨Îó²î½Ï´ó£¬Ìá³öÈçϸĽø´ëÊ©£¬ÄãÈÏΪ¿ÉÐеÄÓÐ________£®(ÌîÐòºÅ)
A£®ÔÚµÎÈëÑÎËá֮ǰ£¬Ó¦Åž»×°ÖÃÄÚµÄCO2ÆøÌå
B£®ÔÚ×°ÖâÙÖÐÏ¡ÑÎËá»»³ÉÏ¡ÁòËᣬװÖâÚÖÐË®»»³É±¥ºÍNaHCO3ÈÜÒº
C£®ÔÚ×°ÖâÚÖÐË®»»³É±¥ºÍNa2CO3ÈÜÒº
D£®µÎ¼ÓÑÎËá²»Ò˹ý¿ì
(4)ÒÒͬѧÈÏΪÔÚ×°ÖâڢÛÖ®¼äµÄµ¼¹ÜÄÚ»á»ý´æË®£¬Ê¹²â¶¨½á¹û²»×¼£¬´Ó¶ø¸ÄÓÃͼ2×°Ö㮼ٶ¨µÎ¶¨¹ÜÆðʼ¶ÁÊýΪV1 mL£¬ÖÕÁ˶ÁÊýΪV2 mL£¬¶ø×¢ÉäÆ÷²â¶¨ÅųöµÄÆøÌåΪV3 mL(±ê×¼×´¿öÏÂ)£¬»ìºÏÎïÑùÆ·ÖÊÁ¿Îªm g£¬ÔòÔ»ìºÏÎïÖÐNaHCO3µÄÖÊÁ¿·ÖÊýµÄ±í´ïʽΪ________£®(Óú¬V1¡¢V2¡¢V3¡¢mµÄʽ×Ó±íʾ)£®
(5)±ûͬѧ¸ÄÓÃͼ3×°Öã¬Í¨¹ý²â¶¨ÉÕ±µÄÖÊÁ¿£®ÄãÈÏΪÒÒ¡¢±ûÁ½Í¬Ñ§µÄ·½°¸ÖУ¬ËµÄ·½°¸¸üºÏÀí________£¬ÀíÓÉÊÇ£º________£®
½âÎö£º
|
¡¡¡¡(1)a¡¢b¡¢c¡¢d(2·Ö) ¡¡¡¡(2)´ð°¸1£ºÔÚ¢ÚÖмÓË®½þû³¤µ¼¹Ü£¬¹Ø±Õ·ÖҺ©¶·»îÈû£¬ÓÃÊÖÎÕסԲµ×ÉÕÆ¿(»ò¾Æ¾«µÆÎ¢ÈÈ)£¬Èô¢ÚÖ㤵¼¹ÜÄÚÒºÃæÉÏÉý£¬Ôò˵Ã÷ÆøÃÜÐԺã»´ð°¸2£ºÔÚ¢ÛÖмÓË®½þûµ¼¹Ü£¬¹Ø±Õ·ÖҺ©¶·»îÈû£¬Óþƾ«µÆÎ¢ÈÈ£¬Èô¢ÛÖе¼¹Ü¿Ú²úÉú¾ùÔÈµÄÆøÅÝ£¬Í£Ö¹¼ÓÈȺ󣬵¼¹ÜÄ©¶ËÐγÉÒ»¶ÎË®ÖùÇÒ±£³ÖÒ»¶Îʱ¼ä²»Ï½µ£¬Ôò˵Ã÷ÆøÃÜÐԺã®(2·Ö) ¡¡¡¡(3)BD(2·Ö) ¡¡¡¡(4) ¡¡¡¡(5)ÒÒͬѧ(1·Ö)¡¡±ûͬѧµÄ·½°¸ÖУ¬Éú³ÉµÄCO2ûÓÐÈ«±»NaOHÈÜÒºÎüÊÕ£®(2·Ö) |
£¨12·Ö£©Ä³Ñ§ÉúʵÑéÐËȤС×éÄâÓÃͼ1×°ÖÃÀ´Íê³É¡°NaHCO3ºÍNaCl»ìºÏÎïÖÐNaHCO3º¬Á¿µÄ²â¶¨¡±µÄʵÑé¡£![]()
ͼ1
£¨1£©¸÷ÒÇÆ÷½Ó¿ÚÁ¬½Ó˳ÐòÊÇ_________________£¨ÓýӿÚ×ÖĸÌîд£©¡£
£¨2£©¸Ã×°ÖÃÁ¬½ÓºÃ¶øÎ´×°Ò©Æ·Ç°£¬¼ìÑ鯸ÃÜÐԵIJÙ×÷ÊÇ_________________________¡£
£¨3£©¼×ͬѧÈÏΪÉÏÊö·½·¨Îó²î½Ï´ó£¬Ìá³öÈçϸĽø´ëÊ©£¬ÄãÈÏΪ¿ÉÐеÄÓÐ______¡££¨ÌîÐòºÅ£©
| A£®ÔÚµÎÈëÑÎËá֮ǰ£¬Ó¦Åž»×°ÖÃÄÚµÄCO2ÆøÌå |
| B£®ÔÚ×°ÖâÙÖÐÏ¡ÑÎËá»»³ÉÏ¡ÁòËᣬװÖâÚÖÐË®»»³É±¥ºÍNaHCO3ÈÜÒº |
| C£®ÔÚ×°ÖâÚÖÐË®»»³É±¥ºÍNa2CO3ÈÜÒº |
| D£®µÎ¼ÓÑÎËá²»Ò˹ý¿ì |
£¨Óú¬V1¡¢V2¡¢V3¡¢mµÄʽ×Ó±íʾ£©¡£
£¨5£©±ûͬѧ¸ÄÓÃͼ3×°Öã¬Í¨¹ý²â¶¨ÉÕ±µÄÖÊÁ¿¡£ÄãÈÏΪÒÒ¡¢±ûÁ½Í¬Ñ§µÄ·½°¸ÖУ¬ËµÄ·½°¸¸üºÏÀí__________£¬ÀíÓÉÊÇ:_____________¡£
µÚÒ»×飬ȡ¸Õ½µµ½µØÃæµÄËáÓêË®Ñù£¬½øÐÐÁËÈçÏÂʵÑ飺
£¨1£©½«Ò»Æ¬ºìÉ«µÄõ¹å»¨°ê½þÔÚÒ»·ÝË®ÑùÖÐ
£¨2£©Ã¿¸ôÒ»¶¨Ê±¼ä²â¶¨ÆäpH£¬Êý¾ÝÈç±í¢ñËùʾ£®
£¨3£©ÏòÓêË®ÊÔÑùÖеμÓÂÈ»¯±µÈÜÒº£¬Óа×É«»ë×dzöÏÖ
±í¢ñ²»Í¬Ê±¼äËáÓêµÄpH
| ²â¶¨Ê±¼ä/СʱÖÓ | 1 | 2 | 4 | |
| pH | 4.73 | 4.62 | 4.56 | 4.55 |
£¨2£©Éú³É°×É«»ë×ǵĻ¯Ñ§·½³Ìʽ______£®
£¨3£©·ÖÎöÉÏÊöpHÊý¾Ý±ä»¯£¬ÄãÈÏΪ¿ÉÄܵÄÔÒòÊÇ£¨Óû¯Ñ§·½³Ìʽ±íʾ£©£º______£®
µÚ¶þ×飬ÓÃÄâÓÃÏÂÁÐ×°Öö¨Á¿·ÖÎö¿ÕÆøÖÐSO2µÄº¬Á¿£º
£¨4£©¸Ã×éͬѧ²é×ÊÁϵõ½µÄ·´Ó¦ÔÀíΪ£ºSO2ÓëËáÐÔKMnO4ÈÜÒº·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º5SO2+2KMnO4+2H2O=2H2SO4+2MnSO4+K2SO4£®
¸Ã·´Ó¦µÄÏÖÏóÊÇ______
£¨5£©KMnO4ÈÜÒºÖе¼¹ÜÄ©¶Ë×ö³ÉÇò×´¶à¿×½á¹¹µÄ×÷ÓÃÊÇ______£®
£¨6£©¸ÃʵÑéÖÐÒѾ֪µÀµÄÊý¾ÝÓÐÆøÌåÁ÷ËÙa L/min¡¢ËáÐÔKMnO4ÈÜÒºµÄÌå»ýb L£¬ÆäŨ¶ÈΪc mol/L£®Èô´ÓÆøÌåͨÈëµ½×ÏɫǡºÃÍÊÈ¥£¬ÓÃʱ5·ÖÖÓ£®Ôò´Ë´ÎÈ¡Ñù´¦µÄ¿ÕÆøÖжþÑõ»¯Áòº¬Á¿Îª______g/L£®