ÌâÄ¿ÄÚÈÝ

ÒÑÖªÈéËáµÄ½á¹¹¼òʽΪ£º
 
£¨1£©Ôò90gÈéËáÓë×ãÁ¿½ðÊôÄÆ·´Ó¦²úÉúµÄÆøÌåÔÚ±ê×¼×´¿öϵÄÌå»ýÊÇ_____________L¡£
·½³ÌʽΪ                                                             ¡£
ÒÑÖªÁ½·Ö×ÓÈéËá¿ÉÔÚÒ»¶¨Ìõ¼þÏ·´Ó¦Éú³É»·×´µÄõ¥£¬Ð´³ö¸Ã·´Ó¦µÄ·½³Ìʽ£º
                                                                       ¡£
£¨2£©ÒÑÖªÆÏÌÑÌÇ¿ÉÒԺʹ×ËáÔÚÒ»¶¨Ìõ¼þÏ·¢Éúõ¥»¯·´Ó¦£¬Ôò1Ħ¶ûÆÏÌÑÌÇ×î¶à¿ÉÒÔÏûºÄ
       Ä¦¶û´×Ëá¡£
£¨3£©·Ö×ÓʽΪC6H12µÄijÌþ£¬ÆäËùÓеÄ̼ԭ×Ó¶¼Ò»¶¨ÔÚÍ¬Ò»Æ½ÃæÉÏ£¬Ôò¸ÃÌþµÄ½á¹¹¼òʽΪ     
__________________¡£
£¨4£©Ä³±½µÄͬϵÎï·Ö×ÓʽΪC11H16£¬±½»·ÉÏÖ»ÓÐÒ»¸öÈ¡´ú»ù£¬Æäͬ·ÖÒì¹¹Ìå¹²ÓР      ÖÖ¡£

£¨1£©22.4 L      CH2OHCH2COOH+2Na ¡ú CH2(ONa)CH2COONa+H2¡ü

£¨2£©5         £¨3£© CH3-C(CH3)=C(CH3)-CH3      £¨4£© 8

½âÎöÊÔÌâ·ÖÎö£º£¨1£©µÄÏàµÈ·Ö×ÓÖÊÁ¿Îª180£¬ËùÒÔ90gÈéËáΪ0.5mol£¬Æä·Ö×Óº¬ÓÐôÈ»ùºÍôÇ»ù£¬ÆäÓëÄÆµÄ·´Ó¦Îª: CH2OHCH2COOH+2Na ¡ú CH2(ONa)CH2COONa+H2¡ü,ËùÒÔ0.5molµÄÈéËáÓë×ãÁ¿ÄÆ·´Ó¦Éú³É1molÇâÆø£¬¹ÊÔÚ±ê×¼×´¿öϵÄÌå»ýÊÇ22.4L£¬ÔÚÒ»¶¨Ìõ¼þÏ·´Ó¦Éú³É»·×´µÄõ¥µÄ»¯Ñ§·´Ó¦·½³ÌʽΪ£º£»£¨2£©ÆÏÌÑÌÇ¿ÉÒԺʹ×ËáÔÚÒ»¶¨Ìõ¼þÏ·¢Éúõ¥»¯·´Ó¦£¬Ò»¸öÆÏÌÑÌÇ·Ö×Óº¬ÓÐ5¸öôÇ»ù£¬ËùÒÔ1Ħ¶ûÆÏÌÑÌÇ×î¶à¿ÉÒÔÏûºÄ5Ħ¶û´×Ë᣻£¨3£©·Ö×ÓʽΪC6H12µÄijÌþ£¬ÆäËùÓеÄ̼ԭ×Ó¶¼Ò»¶¨ÔÚÍ¬Ò»Æ½ÃæÉÏ£¬Ôò¸ÃÌþµÄ½á¹¹¼òʽΪCH3-C(CH3)=C(CH3)-CH3£»£¨4£©Ä³±½µÄͬϵÎï·Ö×ÓʽΪC11H16£¬±½»·ÉÏÖ»ÓÐÒ»¸öÈ¡´ú»ù£¬ËùÒÔÕâЩ»¯ºÏÎï·Ö±ðΪ¡¢¡¢¡¢¡¢¡¢¡¢ºÍ£¬Ò»¹²8ÖÖ¡£
¿¼µã£ºÄÆÓë´¼´×ËáµÄ·´Ó¦¡¢Í¬·ÖÒì¹¹Ìå
µãÆÀ£º±¾Ì⿼²éÁËÄÆÓë´¼´×ËáµÄ·´Ó¦¡¢Í¬·ÖÒì¹¹Ì壬¸ÃÌâ×ÛºÏÐԽϸߣ¬ÌرðÊÇ×îºóÒ»¸öСÌ⣬¿¼²éÁ˱½µÄͬϵÎïµÄͬ·ÖÒì¹¹ÌåµÄÊéд£¬¸ÃСÌâÄѶȺܴó¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø