ÌâÄ¿ÄÚÈÝ

Óлú»¯ºÏÎïAÊÇÒ»ÖÖũҩÉú²úµÄÖмäÌ壬AÔÚÒ»¶¨Ìõ¼þÏ¿ɷ¢ÉúÏÂÁÐת»¯£º

Çë»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©A·Ö×ÓÖв»º¬Ñõ¹ÙÄÜÍŵÄÃû³ÆÎª                 ¡£

£¨2£©C²»ÄÜ·¢Éú·´Ó¦µÄÀàÐÍÓÐ                 £¨Ìî×Öĸ£©¡£

a.È¡´ú       b.ÏûÈ¥       c.¼Ó³É       d.Ñõ»¯        e.¼Ó¾Û

£¨3£©F¿ÉÄܵĽṹ¼òʽΪ                                            ¡£

£¨4£©·´Ó¦¢ÙµÄ»¯Ñ§·½³ÌʽΪ                                                ¡£

£¨5£©Ð´³öBµ½CµÄÀë×Ó·½³Ìʽ                                              ¡£

£¨6£©EÔÚÒ»¶¨Ìõ¼þÏ·´Ó¦ÄÜÉú³É¸ß·Ö×Ó»¯ºÏÎÆä¿ÉÄܵĽṹ¼òʽΪ            ¡£

£¨1£©ÂÈÔ­×Ó£¨Í¬Ê±ÌîÂÈÔ­×Ӻͱ½»ù²»¿Û·Ö£¬Ö»Ìî±½»ù²»¸ø·Ö£©£¨2·Ö£©

£¨2£©b e £¨2·Ö£©    £¨3£©    £¨¸÷1·Ö£¬3·Ö£©   

£¨4£©£¨3·Ö£©

 


£¨5£©        +CO2+H2O          + HCO3-    (3·Ö)

£¨6£©(¸÷1·Ö£¬¹²2·Ö)

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø