ÌâÄ¿ÄÚÈÝ
![]()
(3)ÒÑÖªÓÉG·Ö½âµÃµ½µÄH¡¢I¡¢JÈýÕßµÄÎïÖʵÄÁ¿ÏàµÈ£¬ÔòGµÄ»¯Ñ§Ê½Îª___¡£
(2) 2Fe2+ +Cl2=2Fe3+ +2Cl- £»FeO+ 2H+=Fe2+ +H2O
(3) FeC2O4
µçÀëÆ½ºâ³£Êý£¨ÓÃKa±íʾ)µÄ´óС¿ÉÒÔÅжϵç½âÖʵÄÏà¶ÔÇ¿Èõ¡£25¡æÊ±£¬ÓйØÎïÖʵĵçÀëÆ½ºâ³£ÊýÈçϱíËùʾ£º
|
»¯Ñ§Ê½ |
HF |
H2CO3 |
HClO |
|
µçÀëÆ½ºâ³£Êý £¨Ka£© |
7.2¡Á10-4 |
K1=4.4¡Á10-7 K2=4.7¡Á10-11 |
3.0¡Á10-8 |
£¨1£©ÒÑÖª25¡æÊ±£¬¢ÙHF(aq)+OH¡ª(aq)£½F¡ª(aq)+H2O(l) ¦¤H£½£67.7kJ/mol£¬
¢ÚH+(aq)+OH¡ª(aq)£½H2O(l) ¦¤H£½£57.3kJ/mol £¬
Çâ·úËáµÄµçÀë·½³Ìʽ¼°ÈÈЧӦ¿É±íʾΪ________________________¡£
£¨2£©½«Å¨¶ÈΪ0.1 mol/LHFÈÜÒº¼ÓˮϡÊÍÒ»±¶£¨¼ÙÉèζȲ»±ä£©£¬ÏÂÁи÷Á¿Ôö´óµÄÊÇ____¡£
A£®c(H+) B£®c(H+)¡¤c(OH¡ª) C£®
D£®![]()
£¨3£©25¡æÊ±£¬ÔÚ20mL0.1mol/LÇâ·úËáÖмÓÈëVmL0.1mol/LNaOHÈÜÒº£¬²âµÃ»ìºÏÈÜÒºµÄpH±ä»¯ÇúÏßÈçͼËùʾ£¬ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ_____¡£
![]()
A£®pH£½3µÄHFÈÜÒººÍpH£½11µÄNaFÈÜÒºÖУ¬ ÓÉË®µçÀë³öµÄc(H+)ÏàµÈ
B£®¢ÙµãʱpH£½6£¬´ËʱÈÜÒºÖУ¬c(F¡ª)£c(Na+)£½9.9¡Á10-7mol/L
C£®¢Úµãʱ£¬ÈÜÒºÖеÄc(F¡ª)£½c(Na+)
D£®¢ÛµãʱV£½20mL£¬´ËʱÈÜÒºÖÐc(F¡ª)< c(Na+)£½0.1mol/L
£¨4£©ÎïÖʵÄÁ¿Å¨¶È¾ùΪ0.1mol/LµÄÏÂÁÐËÄÖÖÈÜÒº£º ¢Ù Na2CO3ÈÜÒº ¢Ú NaHCO3ÈÜÒº ¢Û NaFÈÜÒº ¢ÜNaClOÈÜÒº¡£ÒÀ¾ÝÊý¾ÝÅжÏpHÓÉ´óµ½Ð¡µÄ˳ÐòÊÇ______________¡£
£¨5£©Na2CO3ÈÜÒºÏÔ¼îÐÔÊÇÒòΪCO32¡ªË®½âµÄÔµ¹Ê£¬ÇëÉè¼Æ¼òµ¥µÄʵÑéÊÂʵ֤Ã÷Ö®
___________________________________________________________¡£
£¨6£©³¤ÆÚÒÔÀ´£¬Ò»Ö±ÈÏΪ·úµÄº¬ÑõËá²»´æÔÚ¡£1971ÄêÃÀ¹ú¿ÆÑ§¼ÒÓ÷úÆøÍ¨¹ýϸ±ùĩʱ»ñµÃHFO£¬Æä½á¹¹Ê½ÎªH¡ªO¡ªF¡£HFOÓëË®·´Ó¦µÃµ½HFºÍ»¯ºÏÎïA£¬Ã¿Éú³É1molHF×ªÒÆ molµç×Ó¡£
ÏÖÓÐÁ½·Ýï§ÑÎÑùÆ·A¡¢B£¬Æä³É·Ö¶¼ÊÇ£¨NH4£©2SO4¡¢NH4HSO4µÄ»ìºÏÎ¼×¡¢ÒÒÁ½¸öÑо¿ÐÔѧϰС×éµÄͬѧÏëҪȷ¶¨AºÍBÖи÷³É·ÖµÄº¬Á¿£®
¼××éͬѧȡÁËÊý·ÖÏàͬÖÊÁ¿µÄÑùÆ·AÈÜÓÚË®£¬È»ºó·Ö±ð¼ÓÈ벻ͬÌå»ýµÄ1mol/LµÄNaOHÈÜÒº£¬Ë®Ô¡¼ÓÈÈÖÁÆøÌåÈ«²¿Òݳö£®£¨´ËζÈÏ£¬ï§Ñβ»·Ö½â£©£®¸ÃÆøÌå¸ÉÔïºóÓÃ×ãÁ¿µÄŨÁòËáÍêÈ«ÎüÊÕ£®Å¨ÁòËáÔöÖØµÄÖÊÁ¿Óë¼ÓÈëNaOHÈÜÒºµÄÌå»ýµÄ¹ØÏµÈçÓÒͼ£®·ÖÎö¸ÃͼÏ󣬲¢»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©Ð´³öab¶ÎÉæ¼°µÄÀë×Ó·½³Ìʽ£º______£®
£¨2£©cµã¶ÔÓ¦µÄÊýÖµÊÇ______£»ÑùÆ·AÖУ¨NH4£©2SO4¡¢NH4HSO4µÄÎïÖʵÄÁ¿Ö®±ÈΪ______£®
ÒÒ×éͬѧȡÁËÊý·Ý²»Í¬ÖÊÁ¿µÄÑùÆ·B£¬·Ö±ð¼ÓÈëµ½200mL 1mol/LµÄNaOHÈÜÒºÖУ¬Í¬ÑùÓÃˮԡ¼ÓÈÈ£¬½«ÒݳöÆøÌå¸ÉÔïºóÔÙÓÃŨH2SO4ÎüÊÕ£®²â¶¨½á¹ûÈçÏÂ±í£º
| ʵÑé±àºÅ | ¢ñ | ¢ò | ¢ó | ¢ô |
| ï§ÑεÄÖÊÁ¿£¨g£© | 9.88 | 19.76 | 29.64 | 49.40 |
| ŨÁòËáÔö¼ÓµÄÖÊÁ¿£¨g£© | m | m | 1.36 | 0 |
£¨3£©¢Ù·ÖÎöʵÑéÊý¾Ý¿ÉÖª£¬ÊµÑé±àºÅΪ______µÄʵÑéÖУ¬ÇâÑõ»¯ÄÆ×ãÁ¿£¬ï§ÑÎÖеÄ笠ùÀë×ÓÍêȫת»¯³ÉÆøÌ壻mµÄֵΪ______£®
¢Ú¼ÆËãÑùÆ·BÖеªÔªËصÄÖÊÁ¿·ÖÊý£®£¨ÓÃСÊý±íʾ£¬±£ÁôÁ½Î»Ð¡Êý£©
£¨4£©ÒÒ×éͬѧÔÚÑо¿Ê±·¢ÏÖ£¬Å¨ÁòËáÔöÖØµÄÖÊÁ¿ÓëÑùÆ·BµÄÖÊÁ¿Ö®¼äÂú×ãÒ»¶¨µÄº¯Êý¹ØÏµ£®¼ÙÉèÑùÆ·µÄÖÊÁ¿Îªx£¨g£©£¬Å¨ÁòËáÔöÖØµÄÖÊÁ¿Îªy£¨g£©£®Ç󣺵±xÔÚ²»Í¬·¶Î§Ê±yÓëxµÄº¯Êý¹ØÏµ£®