ÌâÄ¿ÄÚÈÝ

ij¿ÎÍâ»î¶¯Ð¡×éʵÑé²âµÃij¹èËáÑÎËùº¬Ñõ»¯ÎïµÄÖÊÁ¿·ÖÊýÈçÏÂ±í£º

Ñõ»¯Îï

CaO

Al2O3

SiO2

H2O

ÖÊÁ¿·ÖÊý

0.142 0

0.260 2

0.459 2

0.137 8

ÇëÄãͨ¹ý¼ÆË㣬д³ö¸Ã¹èËáÑÎµÄÆÕͨ»¯Ñ§Ê½ºÍÑõ»¯Îï±íʾʽ¡£?

£¨1£©ÆÕͨ»¯Ñ§Ê½Îª_____________________________________________________£»?

£¨2£©Ñõ»¯Îï±íʾΪ_____________________________________________________¡£?

¢ò.ÈçÓÒͼËùʾ£¬×°ÓÐÃÈ·¢ÖÖ×ӵĹã¿ÚÆ¿£¬¹ýÒ»¶Îʱ¼ä£¬Íù¹ã¿ÚÆ¿Àï×¢ÈëÇåË®£¬ÊÔ¹ÜÀïµÄÏÖÏóÊÇ_____________________________________________________£¬Óйصķ´Ó¦·½³ÌʽΪ___________________________¡£

¢ñ.£¨1£©CaAl2Si3O10¡¤3H2O£¨»òCaAl2H6Si3O13£©

£¨2£©CaO¡¤Al2O3¡¤3SiO2¡¤3H2O

¢ò.³ÎÇåʯ»ÒË®±ä»ë×Ç¡¡Ca£¨OH£©2+CO2 ====CaCO3¡ý+H2O


½âÎö:

¢ñ. ?N?£¨CaO£©¡Ã?N?£¨Al2O3£©¡Ã?N?£¨SiO2£©¡Ã?N?£¨H2O£©==1¡Ã1¡Ã3¡Ã3¡£

¢ò.ÃÈ·¢ÖÖ×ÓÉúÃü»î¶¯£¬Òª²»¶Ï½øÐкôÎü£¬ÎüÈëÑõÆø£¬Êͷųö¶þÑõ»¯Ì¼£¬Ê¹¹ã¿ÚÆ¿ÖеĶþÑõ»¯Ì¼Å¨¶ÈÏÔÖøÉý¸ß¡£´Ó©¶·×¢ÈëÇåË®µÄÄ¿µÄÊÇʹ¶þÑõ»¯Ì¼±»ÅÅÈë×°ÓгÎÇåʯ»ÒË®µÄÊÔ¹ÜÖУ¬¶þÑõ»¯Ì¼Óë³ÎÇåʯ»ÒË®Æð·´Ó¦£¬¿É¹Û²ìµ½Æä·´Ó¦µÄÏÖÏó¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø