ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿ÔÚË®ÈÜÒºÖгÈÉ«µÄCr2O72£Óë»ÆÉ«µÄCrO42£ÓÐÏÂÁÐÆ½ºâ¹ØÏµ£ºCr2O72££«H2O
2CrO42££«2H£«°ÑÖØ¸õËá¼ØK2Cr2O7ÈÜÓÚË®Åä³ÉµÄÏ¡ÈÜÒºÊdzÈÉ«µÄ£®
£¨1£©ÏòÉÏÊöÈÜÒºÖмÓÈëNaOHÈÜÒº£¬ÈÜÒº³Ê ______ É«
£¨2£©ÏòÒѼÓÈëNaOHÈÜÒºµÄ£¨1£©ÈÜÒºÖÐÔÙ¼ÓÈë¹ýÁ¿Ï¡ÁòËᣬÔòÈÜÒº³Ê ______ É«
£¨3£©ÏòÔÈÜÒºÖÐÖð½¥¼ÓÈë×ãÁ¿ÏõËá±µÈÜÒº
ÒÑÖªBaCrO4Ϊ»ÆÉ«³Áµí
£¬Ôòƽºâ ______
Ìî¡°Ïò×óÒÆ¶¯¡±»ò¡°ÏòÓÒÒÆ¶¯¡±
£¬ÈÜÒºÑÕÉ«½« ______ £®
¡¾´ð°¸¡¿»Æ ³È ÏòÓÒÒÆ¶¯ Öð½¥±äΪÎÞÉ«
¡¾½âÎö¡¿
£¨1£©Cr2O72££«H2O
2CrO42££«2H£«£¬¼ÓÈëNaOHÈÜÒº£¬ÇâÀë×ÓŨ¶È½µµÍ£¬Æ½ºâÕýÏòÒÆ¶¯£¬CrO42£µÄŨ¶ÈÔö´ó£¬ÈÜÒº³Ê»ÆÉ«£»
£¨2£©ÏòÒѼÓÈëNaOHÈÜÒºµÄ£¨1£©ÈÜÒºÖÐÔÙ¼ÓÈë¹ýÁ¿Ï¡ÁòËᣬÇâÀë×ÓŨ¶ÈÔö´ó£¬Æ½ºâÄæÏòÒÆ¶¯£¬Cr2O72£µÄŨ¶ÈÔö´ó£¬ÔòÈÜÒº³Ê³ÈÉ«£»
£¨3£©ÏòÔÈÜÒºÖÐÖð½¥¼ÓÈë×ãÁ¿ÏõËá±µÈÜÒº
ÒÑÖªBaCrO4Ϊ»ÆÉ«³Áµí
£¬CrO42£µÄŨ¶È½µµÍ£¬ÔòƽºâÏòÓÒÒÆ¶¯£¬ÓÉÓÚÉú³ÉBaCrO4³Áµí£¬Cr2O72£¡¢CrO42£µÄŨ¶È¶¼½µµÍ£¬ÈÜÒºÑÕÉ«½«Öð½¥±äΪÎÞÉ«¡£
¡¾ÌâÄ¿¡¿£¨1£©ÊµÑé²âµÃ£¬5gҺ̬¼×´¼(CH3OH)ÔÚÑõÆøÖгä·ÖȼÉÕÉú³É¶þÑõ»¯Ì¼ÆøÌåºÍҺ̬ˮʱÊͷųö113£®5kJµÄÈÈÁ¿£¬ÊÔд³ö¼×´¼È¼ÉÕµÄÈÈ»¯Ñ§·½³Ìʽ____________________________________¡£
£¨2£©¼ºÖª·´Ó¦N2+3H2
2NH3 ¡÷H=akJ/mol¡£ÊÔ¸ù¾ÝϱíÖÐËùÁмüÄÜÊý¾Ý¹ÀËãaµÄÊýֵΪ______¡£
»¯Ñ§¼ü | H-H | N-H | N¡ÔN |
¼üÄÜkJ/mol | 436 | 391 | 945 |
£¨3£©ÒÀ¾Ý¸Ç˹¶¨ÂÉ¿ÉÒÔ¶ÔijЩÄÑÒÔͨ¹ýʵÑéÖ±½Ó²â¶¨µÄ»¯Ñ§·´Ó¦µÄìÊ±ä½øÐÐÍÆËã¡£
¼ºÖª£ºC(s£¬Ê¯Ä«)+O2(g)=CO2(g) ¡÷Hl=-393. 5kJ/mol
2H2(g)+O2(g)=2H2O(l) ¡÷H2=-571.6kJ/mol
2C2H2(g) +5O2(g) =4CO2(g) +2H2O(1) ¡÷H3=-2599kJ/mol
ñÌÍÆ¸Ç˹¶¨ÂÉ£¬¼ÆËã298KʱÓÉC(s,ʯī)ºÍH2(g)Éú³É1mol C2H2(g)·´Ó¦ÈÈ»¯Ñ§·½³Ìʽ:__________¡£
¡¾ÌâÄ¿¡¿ÊÒÎÂÏ£¬½«Ò»¶¨Å¨¶ÈµÄÒ»ÔªËáHAÈÜÒººÍÒ»¶¨Å¨¶ÈµÄNaOHÈÜÒºµÈÌå»ý»ìºÏ£¨ºöÂÔÌå»ý±ä»¯£©£¬ÊµÑéÊý¾ÝÈçÏÂ±í£º
ʵÑé±àºÅ | ÆðʼŨ¶È£¨mol/L£© | ·´Ó¦ºóÈÜÒºµÄpH | |
|
| ||
¢Ù | 0.1 | 0.1 | 9 |
¢Ú |
| 0.2 | 7 |
ÏÂÁÐÅжϲ»ÕýÈ·µÄÊÇ£¨ £©
A.ʵÑé¢Ù·´Ó¦µÄÈÜÒºÖУº![]()
B.ʵÑé¢Ù·´Ó¦µÄÈÜÒºÖУº![]()
C.ʵÑé¢Ú·´Ó¦µÄÈÜÒºÖУº![]()
D.ʵÑé¢Ú·´Ó¦µÄÈÜÒºÖУº![]()