题目内容

【题目】乙醇与乙酸是生活中常见的两种有机物,试回答下列问题:

(1)乙醇中官能团的名称是__________,乙酸中官能团的结构简式为____________

(2)写出下列反应的化学方程式:

乙醇燃烧 _____________________________________________________

乙醇与Na _____________________________________________________

乙酸与NaHCO3_____________________________________________________

乙酸与CH3OH______________________________________________________

【答案】(1) 羟基,-COOH (2)CH3CH2OH+3O22CO2+3H2O 2CH3CH2OH+2Na---2CH3CH2ONa+H2

CH3COOH+NaHCO3CH3COONa+CO2+H2O CH3COOH + CH3OH CH3COOCH3 + H2O

【解析】

试题分析:(1) 乙醇中官能团的名称是羟基,乙酸中官能团是羧基,结构简式为-COOH

(2) 乙醇燃烧CH3CH2OH+3O22CO2+3H2O

乙醇与Na 2CH3CH2OH+2Na---2CH3CH2ONa+H2

乙酸与NaHCO3 CH3COOH+NaHCO3CH3COONa+CO2+H2O

乙酸与CH3OH CH3COOH + CH3OH CH3COOCH3 + H2O

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