ÌâÄ¿ÄÚÈÝ


ÏÖÓÐÏÂÁжÌÖÜÆÚÔªËØÐÔÖʵÄÏà¹ØÊý¾Ý£º

¢Ù

¢Ú

¢Û

¢Ü

¢Ý

¢Þ

Ô­×Ó°ë¾¶£¨10£­10m£©

1.30

0.82

0.99

1.11

0.90

1.18

×î¸ß»ò×îµÍ»¯ºÏ¼Û

+2

+3

+7

+4

+2

+3

£­1

£­4

Çë»Ø´ðÏÂÁÐÎÊÌ⣺

      £¨1£© ¢ÚºÍ¢ÛÐγɵϝºÏÎïÀàÐÍΪ               £¨Ìî¡°Àë×Ó¡±»ò¡°¹²¼Û¡±£©»¯ºÏÎ

      £¨2£©ÔªËآٵĽðÊôÐÔ±ÈÔªËØ¢ÞÒª                  £¨Ìî¡°Ç¿¡±»ò¡°Èõ¡±£©£¬ÊÔ´ÓÔ­×ӽṹ·½Ãæ½âÊÍÆäÔ­Òò£º                                                  £»

      £¨3£©ÔÚ×ÔÈ»½çÖУ¬ÔªËآܵĴæÔÚÐÎ̬Ϊ                   £¬¹¤ÒµÉÏ´ÖÖÆ¸ÃÔªËØµ¥ÖʵĻ¯Ñ§·½³ÌʽΪ                        £»

      £¨4£© ¢ÞµÄµ¥ÖÊÓëŨNaOHÈÜÒº·´Ó¦µÄÀë×Ó·½³ÌʽÊÇ                               £»

      £¨5£©ÊµÑéÊÒÏÖÓÐÔªËØ¢ÙµÄµ¥ÖʺÍijδ֪½ðÊôµ¥ÖÊM£¬Çë¼òҪд³ö±È½ÏÁ½Õß½ðÊôÐÔÇ¿ÈõµÄÒ»ÖÖʵÑé·½°¸                                          ¡£


£¨1£©¹²¼Û£¨2·Ö£©

£¨2£©Ç¿£¨1·Ö£©£»Ã¾µÄÔ­×Ó°ë¾¶´óÓÚÂÁ£¨1·Ö£©£¬Ô­×Ӻ˶Ô×îÍâ²ãµç×ÓµÄÎüÒýÁ¦±ÈÂÁÈõ£¬±ÈÂÁÔ­×Ó¸üÈÝÒ×ʧȥµç×Ó£¨1·Ö£©£¬ËùÒÔÃ¾ÔªËØµÄ½ðÊôÐÔ±ÈÂÁҪǿ¡£

£¨3£©»¯ºÏ̬£¨1·Ö£©£¬£¨2·Ö£©

 £¨4£©2Al £« 2OH£­ £« 2H2O = 2AlO2£­ £« 3H2¡ü   £¨2·Ö£©

£¨5£©ÔÚÁ½¸öСÉÕ±­Öзֱð¼ÓÈëÊÊÁ¿ÕôÁóË®£¨»òµÈŨ¶ÈµÄÑÎËᣩ£¨1·Ö£©£¬È»ºóͶÈëÐÎ×´´óСÏàͬµÄ½ðÊôƬ£¨1·Ö£©£¬ÈôM·´Ó¦±Èþ¾çÁÒ£¬ÔòMµÄ½ðÊôÐÔ±ÈMgÇ¿  £¨1·Ö£©

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø