ÌâÄ¿ÄÚÈÝ

ÏÂÁйØÓÚÈÈ»¯Ñ§·´Ó¦µÄÃèÊöÖÐÕýÈ·µÄÊÇ

A£®HClºÍNaOH·´Ó¦µÄÖкÍÈȦ¤H£½£­57.3kJ/mol£¬ÔòH2SO4ºÍCa(OH)2·´Ó¦µÄÖкÍÈȦ¤H£½2¡Á(£­57.3)kJ/mol

B£®CO(g)µÄȼÉÕÈÈÊÇ283.0kJ/mol£¬Ôò2CO2(g)£½2CO(g)£«O2(g)·´Ó¦µÄ¦¤H£½+566.0kJ/mol

C£®ÐèÒª¼ÓÈȲÅÄÜ·¢ÉúµÄ·´Ó¦Ò»¶¨ÊÇÎüÈÈ·´Ó¦

D£®1mol¼×ÍéȼÉÕÉú³ÉÆøÌ¬Ë®ºÍ¶þÑõ»¯Ì¼Ëù·Å³öµÄÈÈÁ¿ÊǼ×ÍéȼÉÕÈÈ

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Ϊ̽¾¿Ag£«ÓëFe3£«Ñõ»¯ÐÔµÄÏà¹ØÎÊÌ⣬ijС×éͬѧ½øÐÐÈçÏÂʵÑ飺ÒÑÖª£ºÏà¹ØÎïÖʵÄKsp£¨20¶È£© AgCl£º1£®8¡Á10£­10 Ag2SO4£º1£®4¡Á10£­5

£¨1£©¼×ͬѧµÄʵÑéÈçÏ£º

×¢£º¾­¼ìÑéºÚÉ«¹ÌÌåΪAg¡£

¢Ù°×É«³ÁµíµÄ»¯Ñ§Ê½ÊÇ______________________¡£

¢Ú¼×ͬѧµÃ³öAg£«Ñõ»¯ÁËFe2£«µÄÒÀ¾ÝÊÇ_________________¡£

£¨2£©ÒÒͬѧΪ̽¾¿Ag£«ºÍFe2£«·´Ó¦µÄ³Ì¶È£¬½øÐÐʵÑé¢ò¡£

a£®°´ÓÒͼÁ¬½Ó×°Öò¢¼ÓÈëÒ©Æ·£¨ÑÎÇÅÖеÄÎïÖʲ»²ÎÓë·´Ó¦£©£¬·¢ÏÖµçѹ±íÖ¸ÕëÆ«ÒÆ¡£Æ«ÒƵķ½Ïò±íÃ÷£ºµç×ÓÓÉʯī¾­µ¼ÏßÁ÷ÏòÒø¡£·ÅÖÃÒ»¶Îʱ¼äºó£¬Ö¸ÕëÆ«ÒÆ¼õС¡£

b£®ËæºóÏò¼×ÉÕ±­ÖÐÖð½¥¼ÓÈëŨFe2£¨SO4£©3ÈÜÒº£¬·¢ÏÖµçѹ±íÖ¸ÕëµÄ±ä»¯ÒÀ´ÎΪ£ºÆ«ÒƼõС¡ú»Øµ½Áãµã¡úÄæÏòÆ«ÒÆ¡£

¢ÙaÖм×ÉÕ±­ÀïµÄµç¼«·´Ó¦Ê½ÊÇ______________________¡£

¢ÚbÖеçѹ±íÖ¸ÕëÄæÏòÆ«ÒÆºó£¬ÒøÎª_______________¼«£¨Ìî¡°Õý¡±»ò¡°¸º¡±£©¡£

¢ÛÓÉʵÑéµÃ³öAg£«ºÍFe2£«·´Ó¦µÄÀë×Ó·½³ÌʽÊÇ___________¡£

£¨3£©Îª½øÒ»²½ÑéÖ¤ÒÒͬѧµÄ½áÂÛ£¬±ûͬѧÓÖ½øÐÐÁËÈçÏÂʵÑ飺

¢ÙʵÑé¢ó_________£¨Ìî¡°ÄÜ¡±»ò¡°²»ÄÜ¡±£©Ö¤Ã÷Fe3£«Ñõ»¯ÁËAg£¬ÀíÓÉÊÇ_______________¡£

¢ÚÓû¯Ñ§·´Ó¦Ô­Àí½âÊÍʵÑé¢ôÓëVµÄÏÖÏóÓÐËù²»Í¬µÄÔ­Òò_____________________¡£

¡¾»¯Ñ§¡ª¡ªÎïÖʽṹÓëÐÔÖÊ¡¿

µª¼°Æä»¯ºÏÎïÓëÈËÀàÉú²ú¡¢Éú»îϢϢÏà¹Ø¡£»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©»ù̬NÔ­×ÓÖеç×ÓÔÚ2p¹ìµÀÉϵÄÅŲ¼×ñÑ­µÄÔ­ÔòÊÇ________¡£Ç°4ÖÜÆÚÔªËØÖУ¬»ù̬ԭ×ÓºËÍâµç×ÓÅŲ¼³Éµ¥µç×ÓÊý×î¶àµÄÔªËØµÄ¼Û²ãµç×ÓÅŲ¼Ê½Îª__________________¡£

£¨2£©C¡¢N¡¢OÈýÖÖÔªËØµÚÒ»µçÀëÄÜ´Ó´óµ½Ð¡µÄ˳ÐòÊÇ__________________________

£¨3£©N2F2·Ö×ÓÖÐNÔ­×ÓµÄÔÓ»¯·½Ê½ÊÇ___________________£¬l mol N2F2º¬ÓÐ______mol¼ü¡£

£¨4£©NF3µÄ¼ü½Ç______NH3µÄ¼ü½Ç(Ìî¡°<¡±¡°>¡±»ò¡°=¡±)£¬Ô­ÒòÊÇ__________________¡£

£¨5£©NH4BF4(·úÅðËáï§)ÊǺϳɵª»¯ÅðÄÉÃ׹ܵÄÔ­ÁÏÖ®Ò»¡£l mol NH4BF4_________molÅäλ¼ü¡£

£¨6£©°²È«ÆøÄÒµÄÉè¼ÆÔ­ÀíΪ6NaN3+FeIO3Na2O+2Fe+9N2¡ü

¢ÙµÈµç×ÓÌåµÄÔ­ÀíÊÇ£ºÔ­×Ó×ÜÊýÏàͬ£¬¼Ûµç×Ó×ÜÊýÏàͬµÄ·Ö×Ó»òÀë×Ó¾ßÓÐÏàËÆµÄ»¯Ñ§¼üÌØÕ÷£¬¾ßÓÐÐí¶àÏà½üµÄÐÔÖÊ¡£Ð´³öÁ½ÖÖÓëN3-»¥ÎªµÈµç×ÓÌåµÄ·Ö×Ó»òÀë×Ó____________¡£

¢ÚNa2OµÄ¾§°û½á¹¹ÈçͼËùʾ£¬Æ·°û±ß³¤Îª566pm£¬¾§°ûÖÐÑõÔ­×ÓµÄÅäλÊýΪ_____£¬Na2O¾§ÌåµÄÃܶÈΪ_____g¡¤cm-3(Ö»ÒªÇóÁÐËãʽ£¬²»±Ø¼ÆËã³ö½á¹û)

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø