ÌâÄ¿ÄÚÈÝ

£¨14·Ö£©Ï±íÊÇÔªËØÖÜÆÚ±íµÄÒ»²¿·Ö¡£±íÖÐËùÁеÄ×Öĸ·Ö±ð´ú±íÒ»ÖÖ»¯Ñ§ÔªËØ¡£

Óû¯Ñ§·ûºÅ»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©±íÖÐ×î»îÆÃµÄ½ðÊôÓë×î»îÆÃµÄ·Ç½ðÊôÐγɵÄÎïÖÊÊÇ             £»
£¨2£©¢Ý¡¢¢Þ¡¢¢àµÄ×î¸ß¼ÛË®»¯ÎïµÄ¼îÐÔÓÉÇ¿µ½ÈõµÄ˳ÐòÊÇ           £»
¢Û¡¢¢Ü¡¢¢ßÇ⻯ÎïÎȶ¨ÐÔÓÉÇ¿µ½ÈõµÄ˳ÐòÊÇ                    £»
£¨3£©¢ÛÓë¢Ý°´Ô­×Ó¸öÊý1£º1Ëù³ÉµÄ»¯ºÏÎïµÄµç×ÓʽΪ________________£»¸Ã»¯ºÏÎïÓëË®·´Ó¦µÄÀë×Ó·½³ÌʽΪ________________¡£
£¨4£©¢ÞºÅÔªËØ×î¸ßÑõ»¯ÎïË®»¯ÎïÓë¢ÝºÅÔªËØ×î¸ß¼ÛÑõ»¯ÎïË®»¯Îï·´Ó¦µÄÀë×Ó·½³ÌʽΪ                                                £»
£¨5£©ÇëÉè¼ÆÒ»¸öʵÑé·½°¸£¬±È½Ï¢á¡¢¢âµÄµ¥ÖÊÑõ»¯ÐÔµÄÇ¿Èõ£º           ¡£

£¨Ã¿¿Õ2£©(1)KF£¨2£© KOH>NaOH>Al(OH)3     HF>H2O>H2
£¨3£©    2Na2O2+2H2O=4Na+ +4OH¡ª+O2¡ü
£¨4£©Al(OH)3+OH- =AlO2-+2H2O
£¨5£©½«äåË®¼ÓÈëµâ»¯ÄÆÈÜÒºÖУ¬ÔÙ¼ÓÈëµí·Û,ÈôÈÜÒº±äÀ¶£¬Ö¤Ã÷µ¥ÖÊäå±Èµ¥ÖʵâÑõ»¯ÐÔÇ¿(ÆäËûºÏÀí´ð°¸Ò²¿É)

½âÎö

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
ϱíÊÇÔªËØÖÜÆÚ±íµÄÒ»²¿·Ö£®±íÖÐËùÁеÄ×Öĸ·Ö±ð´ú±íÒ»ÖÖ»¯Ñ§ÔªËØ£®
A B C D E
F G H
I J K
L
M N
O
ÊԻشðÏÂÁÐÎÊÌ⣺
£¨1£©IµÄÔªËØ·ûºÅΪ
Sc
Sc
£¬KµÄÔªËØÃû³ÆÎª
ïØ
ïØ
£®
£¨2£©Ð´³ö»ù̬ʱJÔªËØÔ­×ӵĵç×ÓÅŲ¼Ê½
1s22s22p63s23p63d64s2
1s22s22p63s23p63d64s2
£¬NÔªËØÔ­×ӵļò»¯µç×ÓÅŲ¼Ê½
[Xe]4f145d106s26p5
[Xe]4f145d106s26p5
£®
£¨3£©ÏÂÁжԱÈÕýÈ·µÄÊÇ
cd
cd
£®
a£®Ô­×Ó°ë¾¶H£¾G£¾B£¾A£»          b£®µÚÒ»µçÀëÄÜE£¾D£¾C£¾B£»
c£®µç¸ºÐÔA£¾H£¾G£¾K£»            d£®×î¸ß¼ÛÑõ»¯ÎïµÄË®»¯ÎïËáÐÔB£¾A£¾H£¾G£»
£¨4£©ÏÂÁйØÓÚÔªËØÔÚÔªËØÖÜÆÚ±íÖеÄλÖÃÒÔ¼°ÔªËØÔ­×ÓµÄÍâΧµç×ÓÅŲ¼ÌصãµÄÓйØÐðÊö²»ÕýÈ·µÄÊÇ
bc
bc
£®
a£®LλÓÚÔªËØÖÜÆÚ±íÖеÚÎåÖÜÆÚ¡¢¢ñA×壬ÊôÓÚsÇøÔªËØ£»
b£®OλÓÚÔªËØÖÜÆÚ±íÖÐµÚÆßÖÜÆÚ¡¢¢øB×壬ÊôÓÚdÇøÔªËØ£»
c£®MµÄÍâΧµç×ÓÅŲ¼Ê½Îª6s1£¬ÊôÓÚdsÇøÔªËØ£»
d£®HËùÔÚ×åµÄÍâΧµç×ÓÅŲ¼Ê½Îªns2np2£¬ÊôÓÚpÇøÔªËØ£»
£¨5£©¶ÌÖÜÆÚÖÐijÖÖÔªËØµÄ×î¸ß¼ÛÑõ»¯Îï1molÓë12molNaOHÇ¡ºÃÍêÈ«·´Ó¦Éú³ÉÕýÑΣ¬¸ÃÔªËØÔÚÔªËØÖÜÆÚ±íÖеÄλÖÃΪ
Èý
Èý
ÖÜÆÚ
¢õA
¢õA
×壮

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø