ÌâÄ¿ÄÚÈÝ


ÏÂÁÐÓ뻯ѧ·´Ó¦ÄÜÁ¿±ä»¯Ïà¹ØµÄÐðÊöÕýÈ·µÄÊÇ(  )

A£®ÓÉH+(aq)£«OH£­(aq)£½H2O(l£© ¦¤H£½-57.3 kJ¡¤mol£­1£¬ÔòÏòº¬0.1 mol HClµÄÑÎËáÖмÓÈë4£®0 gNaOH¹ÌÌ壬·Å³öÈÈÁ¿µÈÓÚ5.73 kJ

B£®µÈÁ¿H2ÔÚO2ÖÐÍêȫȼÉÕÉú³ÉH2O(g)ÓëÉú³ÉH2O(l)£¬·Å³öµÄÄÜÁ¿Ïàͬ

C£®Í¬ÎÂͬѹÏ£¬H2(g)£«Cl2(g)=2HCl(g)ÔÚ¹âÕպ͵ãȼÌõ¼þϵĦ¤H²»Í¬

D£®ÇâÆøµÄȼÉÕÈÈΪ285.8 kJ¡¤mol-1£¬ÔòË®·Ö½âµÄÈÈ»¯Ñ§·½³ÌʽΪ£º2H2O(l)=2H2(g) + O2(g)  ¦¤H£½+ 571.6 kJ¡¤mol-1

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø