ÌâÄ¿ÄÚÈÝ

¡¾ÌâÄ¿¡¿¼×´¼ÊÇÖØÒªµÄ»¯¹¤Ô­ÁÏ£¬ÓֿɳÆÎªÈ¼ÁÏ¡£ÀûÓÃºÏ³ÉÆø£¨Ö÷Òª³É·ÖΪCO¡¢CO2ºÍH2£©ÔÚ´ß»¯¼ÁµÄ×÷ÓÃϺϳɼ״¼£¬·¢ÉúµÄÖ÷·´Ó¦ÈçÏ£º

¢ÙCO(g)+2H2(g)CH3OH(g) ¡÷H1

¢ÚCO2(g)+3H2(g)CH3OH£¨g£©+H2O(g) ¡÷H2

¢ÛCO2(g)+H2(g)CO(g)+H2O(g) ¡÷H3

£¨1£©ÒÑÖª·´Ó¦¢ÙÖеÄÏà¹ØµÄ»¯Ñ§¼ü¼üÄÜÊý¾ÝÈçÏ£º

»¯Ñ§¼ü

H¡ªH

C¡ªO

C¡ÔO

H¡ªO

C¡ªH

E/(kJ¡¤mol-1)

436

343

1076

465

413

Óɴ˼ÆËã¡÷H1=__________kJ¡¤mol-1£¬ÒÑÖª¡÷H2=-58kJ¡¤mol-1£¬Ôò¡÷H3=_________kJ¡¤mol-1

£¨2£©·´Ó¦¢ÙµÄ»¯Ñ§Æ½ºâ³£ÊýKµÄ±í´ïʽΪ_______________£»¢ÛµÄ»¯Ñ§Æ½ºâ³£ÊýKµÄ±í´ïʽΪ_____________£»

¡¾´ð°¸¡¿-99 +41 K= K=

¡¾½âÎö¡¿

(1)·´Ó¦ÈÈ=·´Ó¦Îï×ܼüÄÜ-Éú³ÉÎï×ܼüÄÜ£»¸ù¾Ý¸Ç˹¶¨ÂÉ£º·´Ó¦¢Ú-·´Ó¦¢Ù=·´Ó¦¢Û£¬·´Ó¦ÈÈÒ²½øÐÐÏàÓ¦µÄ¼ÆË㣻(2)»¯Ñ§Æ½ºâ³£ÊýÖ¸¿ÉÄæ·´Ó¦µÃµ½Æ½ºâʱ£¬¸÷Éú³ÉÎïŨ¶ÈµÄ»¯Ñ§¼ÆÁ¿Êý´ÎÃݵij˻ý³ýÒÔ¸÷·´Ó¦ÎïŨ¶ÈµÄ»¯Ñ§¼ÆÁ¿Êý´ÎÃݵij˻ýËùµÃµÄ±ÈÖµ£»¾Ý´Ë·ÖÎö½â´ð¡£

(1)·´Ó¦ÈÈ=·´Ó¦Îï×ܼüÄÜ-Éú³ÉÎï×ܼüÄÜ£¬¹Ê¡÷H1=1076kJ¡¤mol-1+2¡Á436kJ¡¤mol-1-(3¡Á413+343+465)kJ¡¤mol-1=-99kJ¡¤mol-1£¬¸ù¾Ý¸Ç˹¶¨ÂÉ£º·´Ó¦¢Ú-·´Ó¦¢Ù=·´Ó¦¢Û£¬¹Ê¡÷H3=¡÷H2-¡÷H1=-58kJ¡¤mol-1-(-99kJ¡¤mol-1)=+41kJ¡¤mol-1£¬¹Ê´ð°¸Îª£º-99£»+41£»

(2)·´Ó¦¢ÙCO(g)+2H2(g)CH3OH(g)µÄƽºâ³£Êý±í´ïʽK=£¬·´Ó¦¢ÛCO2(g)+H2(g)CO(g)+H2O(g)µÄ»¯Ñ§Æ½ºâ³£ÊýK=£¬¹Ê´ð°¸Îª£º K=£»K=¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

¡¾ÌâÄ¿¡¿°±ÎªÖØÒªµÄ»¯¹¤Ô­ÁÏ£¬Óй㷺ÓÃ;¡£

(1)ºÏ³É°±ÖеÄÇâÆø¿ÉÓÉÏÂÁз´Ó¦ÖÆÈ¡£º

a£®CH4(g)£«H2O(g)CO(g)£«3H2(g) ¦¤H1£½£«216.4 kJ¡¤mol£­1

b£®CO(g)£«H2O(g)CO2(g)£«H2(g) ¦¤H2£½£­41.2 kJ¡¤mol£­1

Ôò·´Ó¦CH4(g)£«2H2O(g)CO2(g)£«4H2(g)¡¡¦¤H£½_________________________¡£

(2)ÆðʼʱͶÈëµªÆøºÍÇâÆøµÄÎïÖʵÄÁ¿·Ö±ðΪ1 mol¡¢3 mol£¬ÔÚ²»Í¬Î¶ȺÍѹǿϺϳɰ±¡£Æ½ºâʱ»ìºÏÎïÖа±µÄÌå»ý·ÖÊýÓëζȵĹØÏµÈçͼ¡£

¢Ùºãѹʱ£¬·´Ó¦Ò»¶¨´ïµ½Æ½ºâ״̬µÄ±êÖ¾ÊÇ________(ÌîÐòºÅ)¡£

A N2ºÍH2µÄת»¯ÂÊÏàµÈ B ·´Ó¦ÌåϵÃܶȱ£³Ö²»±ä

C c(H2)/c(NH3 )±£³Ö²»±ä D c(NH3 )/c(N2)£½2

¢Úp1________(Ìî¡°>¡±¡¢¡°<¡±¡¢¡°£½¡±»ò¡°²»È·¶¨¡±£¬ÏÂͬ)p2£»·´Ó¦µÄƽºâ³£Êý£ºBµã________Dµã¡£

¢ÛCµãH2µÄת»¯ÂÊΪ________£»ÔÚA¡¢BÁ½µãÌõ¼þÏ£¬¸Ã·´Ó¦´Ó¿ªÊ¼µ½Æ½ºâʱÉú³É°±ÆøµÄƽ¾ùËÙÂÊ£ºv(A)________v(B)¡£

(3)N2H4¿É×÷»ð¼ýÍÆ½ø¼Á£¬NH3ºÍNaClOÔÚÒ»¶¨Ìõ¼þÏ·´Ó¦¿ÉÉú³ÉN2H4¡£

¢Ùд³öNH3ºÍNaClO·´Ó¦Éú³ÉN2H4µÄ»¯Ñ§·½³Ìʽ________________________________¡£

¢ÚÒÑÖª25 ¡æÊ±£¬N2H4µÄË®ÈÜÒº³ÊÈõ¼îÐÔ£ºN2H4£«H2ON2H5+£«OH£­K1£½1¡Á10£­a N2H5+£«H2ON2H62+£«OH£­¡¡K2£½1¡Á10£­b25 ¡æÊ±£¬ÏòN2H4Ë®ÈÜÒºÖмÓÈëH2SO4£¬Óûʹc(N2H5+)>c(N2H4)£¬Í¬Ê±c(N2H5+)>c(N2H62+)£¬Ó¦¿ØÖÆÈÜÒºpHµÄ·¶Î§Îª__________________________________(Óú¬a¡¢bµÄʽ×Ó±íʾ)¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø