ÌâÄ¿ÄÚÈÝ

ϱíÊÇÔªËØÖÜÆÚ±íµÄÒ»²¿·Ö£¬»Ø´ðÏÂÁÐÓйØÎÊÌ⣺

×å

ÖÜÆÚ

¢ñA

¢òA

¢óA

¢ôA

¢õA

¢öA

¢÷A

0

2

a

b

3

c

d

e

f

g

h

4

J

k

£¨1£©gµÄÀë×ӽṹʾÒâͼ________       £¬kµÄÔªËØÃû³ÆÊÇ________¡£aÓëf¿ÉÒÔÐγÉÒ»ÖÖÓ²¶È´ó¡¢Ä͸ßεÄÌմɲÄÁÏ£¬¸ÃÎïÖʵĻ¯Ñ§Ê½ÊÇ________    ¡£

£¨2£©ÉÏÊöÔªËØ×î¸ß¼ÛÑõ»¯Îï¶ÔÓ¦µÄË®»¯ÎïÖУ¬×îÇ¿ËáµÄ»¯Ñ§Ê½ÊÇ_______  £¬×îÇ¿¼îÓëÁ½ÐÔÇâÑõ»¯Îï·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ                                             ¡£

£¨3£©ÉÏÊöÁ½ÖÖÔªËØÄܽáºÏ³ÉXYÐÍÀë×Ó»¯ºÏÎÇÒÿ¸öÒõ¡¢ÑôÀë×ÓÖоùº¬10¸öµç×Ó£¬¸ÃÎïÖʵĵçÀë·½³ÌʽΪ________________       £»ÒÑÖª³£ÎÂϸÃÎïÖʵÄË®ÈÜÒºÏÔ¼îÐÔ£¬ÆäÔ­ÒòÊÇ________________                                 £¨ÓÃÀë×Ó·½³Ìʽ±íʾ£©¡£

£¨4£©´ÓÔ­×ӽṹ½Ç¶È½âÊÍcµÄ½ðÊôÐÔÇ¿ÓÚdµÄÔ­ÒòÊÇ£º

________                                                                   ¡£

£¨1£©äå     Si3N

£¨2£©HClO4£¬Al(OH)3 + KOH = KAlO2 + 2H2O

£¨3£©NaF=Na++F-£»   F- + H2O  HF + OH-

£¨4£©¶þÕßµç×Ó²ãÊýÏàͬ£¬µ«ÄÆÔ­×Ó°ë¾¶´óÓÚþԭ×Ó£¬ËùÒÔÄÆÔ­×Ó¸üÒ×ʧµç×Ó

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
ϱíÊÇÔªËØÖÜÆÚ±íµÄÒ»²¿·Ö£®±íÖÐËùÁеÄ×Öĸ·Ö±ð´ú±íÒ»ÖÖ»¯Ñ§ÔªËØ£®
A B C D E
F G H
I J K
L
M N
O
ÊԻشðÏÂÁÐÎÊÌ⣺
£¨1£©IµÄÔªËØ·ûºÅΪ
Sc
Sc
£¬KµÄÔªËØÃû³ÆÎª
ïØ
ïØ
£®
£¨2£©Ð´³ö»ù̬ʱJÔªËØÔ­×ӵĵç×ÓÅŲ¼Ê½
1s22s22p63s23p63d64s2
1s22s22p63s23p63d64s2
£¬NÔªËØÔ­×ӵļò»¯µç×ÓÅŲ¼Ê½
[Xe]4f145d106s26p5
[Xe]4f145d106s26p5
£®
£¨3£©ÏÂÁжԱÈÕýÈ·µÄÊÇ
cd
cd
£®
a£®Ô­×Ó°ë¾¶H£¾G£¾B£¾A£»          b£®µÚÒ»µçÀëÄÜE£¾D£¾C£¾B£»
c£®µç¸ºÐÔA£¾H£¾G£¾K£»            d£®×î¸ß¼ÛÑõ»¯ÎïµÄË®»¯ÎïËáÐÔB£¾A£¾H£¾G£»
£¨4£©ÏÂÁйØÓÚÔªËØÔÚÔªËØÖÜÆÚ±íÖеÄλÖÃÒÔ¼°ÔªËØÔ­×ÓµÄÍâΧµç×ÓÅŲ¼ÌصãµÄÓйØÐðÊö²»ÕýÈ·µÄÊÇ
bc
bc
£®
a£®LλÓÚÔªËØÖÜÆÚ±íÖеÚÎåÖÜÆÚ¡¢¢ñA×壬ÊôÓÚsÇøÔªËØ£»
b£®OλÓÚÔªËØÖÜÆÚ±íÖÐµÚÆßÖÜÆÚ¡¢¢øB×壬ÊôÓÚdÇøÔªËØ£»
c£®MµÄÍâΧµç×ÓÅŲ¼Ê½Îª6s1£¬ÊôÓÚdsÇøÔªËØ£»
d£®HËùÔÚ×åµÄÍâΧµç×ÓÅŲ¼Ê½Îªns2np2£¬ÊôÓÚpÇøÔªËØ£»
£¨5£©¶ÌÖÜÆÚÖÐijÖÖÔªËØµÄ×î¸ß¼ÛÑõ»¯Îï1molÓë12molNaOHÇ¡ºÃÍêÈ«·´Ó¦Éú³ÉÕýÑΣ¬¸ÃÔªËØÔÚÔªËØÖÜÆÚ±íÖеÄλÖÃΪ
Èý
Èý
ÖÜÆÚ
¢õA
¢õA
×壮

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø