ÌâÄ¿ÄÚÈÝ


ÓÃ9mol/LµÄŨÁòËáÏ¡ÊÍ³É 0.9mol/LµÄÏ¡ÁòËá 100mL £¬»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©ÅäÖÆ²Ù×÷¿É·Ö½â³ÉÈçϼ¸²½£¬ÒÔÏÂÕýÈ·µÄ²Ù×÷˳ÐòÊÇ_____________________

A.ÏòÈÝÁ¿Æ¿ÖÐ×¢ÈëÉÙÁ¿ÕôÁóË®£¬¼ì²éÊÇ·ñ©ˮ

B.ÓÃÉÙÁ¿ÕôÁóˮϴµÓÉÕ±­¼°²£Á§°ô£¬½«ÈÜҺעÈëÈÝÁ¿Æ¿£¬²¢Öظ´²Ù×÷Á½´Î

C.ÓÃÒÑÀäÈ´µÄÏ¡ÁòËá×¢ÈëÒѼì²é²»Â©Ë®µÄÈÝÁ¿Æ¿ÖÐ

D.¸ù¾Ý¼ÆË㣬ÓÃÁ¿Í²Á¿È¡Ò»¶¨Ìå»ýµÄŨÁòËá

E.½«Å¨ÁòËáÑØÉÕ±­±ÚÂýÂý×¢ÈëÊ¢ÓÐÕôÁóË®µÄСÉÕ±­ÖУ¬²¢²»¶ÏÓò£Á§°ô½Á°è

F.¸ÇÉÏÈÝÁ¿Æ¿Èû×Ó£¬Õñµ´£¬Ò¡ÔÈ

G.ÓýºÍ·µÎ¹ÜµÎ¼ÓÕôÁóË®£¬Ê¹ÈÜÒº°¼ÃæÇ¡ºÃÓë¿Ì¶ÈÏàÇÐ

H.¼ÌÐøÍùÈÝÁ¿Æ¿ÖÐСÐĵؼÓÕôÁóË®£¬Ê¹ÒºÃæ½Ó½ü¿Ì¶ÈÏß1~2 cm

£¨2£©Èç¹ûʵÑéÊÒÓÃ98£¥µÄŨÁòËá(ÃܶÈΪ1.8g¡¤cm-3 ) ÅäÖÆ3. 6 mol¡¤L-1µÄÏ¡ÁòËá250mL¡£¼ÆËãËùÐèŨÁòËáµÄÌå»ýΪ_____________mL¡£

£¨3£©ÓÉÓÚ´íÎó²Ù×÷, ʹµÃµ½µÄŨ¶ÈÊý¾Ý±ÈÕýÈ·µÄÆ«´óµÄÊÇ___________£¨ÌîдÐòºÅ£©¡£

A.ʹÓÃÈÝÁ¿Æ¿ÅäÖÆÈÜҺʱ, ¸©ÊÓÒºÃæ¶¨ÈݺóËùµÃÈÜÒºµÄŨ¶È

B.ûÓÐÓÃÕôÁóˮϴÉÕ±­2-3´Î£¬²¢½«Ï´ÒºÒÆÈëÈÝÁ¿Æ¿ÖÐ

C.ÈÝÁ¿Æ¿ÓÃÕôÁóˮϴ¾»£¬Ã»Óкæ¸É

D.¶¨ÈÝʱ£¬µÎ¼ÓÕôÁóË®£¬ÏÈÊ¹ÒºÃæÂÔ¸ßÓڿ̶ÈÏߣ¬ÔÙÎü³öÉÙÁ¿Ë®Ê¹ÒºÃæ°¼ÃæÓë¿Ì¶ÈÏßÏàÇÐ

E.°ÑÅäºÃµÄÈÜÒºµ¹ÈëÓÃÕôÁóˮϴ¾»¶øÎ´¸ÉµÄÊÔ¼ÁÆ¿Öб¸ÓÃ


 (1)  ADECBHGF     (2) 50.0       (3) A


Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

 2012Äê3ÔÂ22ÈÕÊǵڶþÊ®½ì¡°ÊÀ½çË®ÈÕ¡±£¬±£»¤Ë®×ÊÔ´£¬´ÓÎÒ×öÆð!

  (1)C102ºÍC12(»¹Ô­²úÎﶼΪClÒ»)ÊÇÉú»îÖг£ÓõÄÏû¶¾¼Á¡£µ±ÏûºÄµÈÎïÖʵÄÁ¿µÄÁ½ÖÖÎïÖÊʱ£¬C102µÄÏû¶¾Ð§ÂÊÊÇC12µÄ              ±¶¡£

  (2)×ÔÀ´Ë®³§³£ÓøßÌúËáÄÆ(Na2Fe04£¬Ç¿Ñõ»¯¼Á)¸ÄÉÆË®ÖÊ¡£¼òÊö¸ßÌúËáÄÆÓÃÓÚɱ¾úÏû¶¾Í¬Ê±ÓÖÆðµ½¾»Ë®×÷ÓõÄÔ­Àí£º                     £®

  (3)ijÎÞÉ«·ÏË®ÖпÉÄܺ¬ÓÐFe3+¡¢A13+¡¢Mg2+¡¢Na+¡¢NO3-¡¢CO32Ò»¡¢SO42-Àë×ÓÖеļ¸ÖÖ£¬Îª·ÖÎöÆä³É·Ö£¬·Ö±ðÈ¡·ÏË®ÑùÆ·100 mL£¬½øÐÐÁËÈý×éʵÑ飬Æä²Ù×÷ºÍÓйØÏÖÏóÈçͼËùʾ£º

  Çë¸ù¾ÝÉÏͼ»Ø´ðÏÂÁÐÎÊÌ⣺

¢ÙʵÑéÖÐÐèÅäÖÆ1£®0 mol£¯lµÄNaOHÈÜÒº80 ml£¬ËùÐèÒÇÆ÷³ýÁ˲£Á§°ô¡¢ÍÐÅÌÌìÆ½¡¢Á¿Í²¡¢Ò©³×¡¢ÉÕ±­¡¢½ºÍ·µÎ¹Ü£¬»¹È±ÉÙµÄÒÇÆ÷Ϊ                                                 

¢ÚʵÑé¢ÛÖгÁµíÁ¿ÓÉA¡úB¹ý³ÌÖÐËù·¢Éú·´Ó¦µÄÀë×Ó·½³ÌʽΪ                               ¡£

¢ÛÊÔÈ·¶¨NO3-ÊÇ·ñ´æÔÚ?            (Ìî¡°´æÔÚ¡±¡°²»´æÔÚ¡±»ò¡°²»È·¶¨¡±)£¬Èô´æÔÚ£¬ÊÔ¼ÆËã

  c(NO3-)            (Èô²»´æÔÚ£¬´ËÎʲ»±Ø×÷´ð)¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø