ÌâÄ¿ÄÚÈÝ


 (1)³£ÎÂʱ£¬ËÄÖÖÈÜÒº£º¢ñ.pH£½4µÄCH3COOHÈÜÒº£»¢ò.pH£½4µÄHClÈÜÒº£»¢ó.pH£½10µÄNaOHÈÜÒº£»¢ô.pH£½10µÄCH3COONaÈÜÒº¡£

¢Ù¢óºÍ¢ôµÄÈÜÒºÖÐË®µçÀëµÄc(H£«)Ũ¶ÈÖ®±È_____________________________________¡£

¢ÚÏÂÁÐÓйØÐðÊöÕýÈ·µÄÊÇ________¡£

A£®¢ò¡¢¢óµÄÈÜÒº·Ö±ðÓë10 gÂÁ·Û·´Ó¦£¬Éú³ÉH2µÄÁ¿¢ó¸ü¶à

B£®½«¢ñºÍ¢óµÈÌå»ý»ìºÏºó£¬ÈÜÒºpHСÓÚ7

C£®ËÄÖÖÈÜÒº¸÷10 mL·Ö±ð¼ÓˮϡÊÍÖÁ100 mLºó£¬ÈÜÒºµÄpH£º¢ó£¾¢ô£¾¢ñ£¾¢ò

(2)CH3COOHÈÜÒºµÄKa£½1.6¡Á10£­5£¬Ôò1.0 mol¡¤L£­1µÄCH3COONaÈÜÒºÖÐc(OH£­)£½________________________________________________________________________¡£

(3)½«CO2ͨÈëNaOHÈÜÒºÖУ¬»Ø´ðÏÂÁÐÎÊÌâ¡£

¢Ùµ±CO2ÓëNaOHÎïÖʵÄÁ¿Ö®±ÈΪ1¡Ã2ʱ£¬ÈÜÒºÖÐÀë×ÓŨ¶ÈµÄ´óС˳ÐòΪ________________________________________________________________________¡£

¢Úµ±c(Na£«)£½c(CO)£«c(HCO)£«c(H2CO3)ʱ£¬·´Ó¦ºóÈÜÒºÖеÄÈÜÖÊΪ________¡£

(4)ÓÃNaOHÈÜÒºµÎ¶¨´×ËáÈÜÒºµÄ¹ý³ÌÖУ¬×¶ÐÎÆ¿ÖеÄÈÜÒºÆäÀë×ÓŨ¶È¹ØÏµÓÐÈçÏÂʽ×Ó£¬Ôڵζ¨¹ý³ÌÖÐÕâЩʽ×Ó³öÏÖµÄÏȺó˳ÐòΪ________(ÇëÑ¡³öÕýÈ·µÄ˳Ðò)¡£

¢Ùc(Na£«)£¾c(CH3COO£­)£¾c(OH£­)£¾c(H£«)

¢Úc(CH3COO£­)£¾c(Na£«)£¾c(H£«)£¾c(OH£­)

¢Ûc(CH3COO£­)£¾c(H£«)£½c(Na£«)£¾c(OH£­)

¢Üc(Na£«)£¾c(CH3COO£­)£½c(OH£­)£¾c(H£«)

¢Ýc(CH3COO£­)£¾c(H£«)£¾c(Na£«)£¾c(OH£­)

¢Þc(Na£«)£½c(CH3COO£­)£¾c(OH£­)£½c(H£«)

¢ßc(Na£«)£¾c(OH£­)£¾c(CH3COO£­)£¾c(H£«)

A£®¢ß¢Ü¢Ù¢Þ¢Ú¢Û¢Ý¡¡¡¡¡¡                     B£®¢Ý¢Ú¢Û¢Ù¢Þ¢Ü¢ß

C£®¢Û¢Ý¢Ú¢Ù¢Þ¢Ü¢ß                           D£®¢Ý¢Û¢Ú¢Þ¢Ù¢Ü¢ß


´ð°¸¡¡(1)¢Ù10£­6¡¡¢ÚB¡¡(2)2.5¡Á10£­5 mol¡¤L£­1¡¡

(3)¢Ùc(Na£«)£¾c(CO)£¾c(OH£­)£¾c(HCO)£¾c(H£«)¡¡¢ÚNaHCO3¡¡(4)D


Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø