ÌâÄ¿ÄÚÈÝ


Ò»¶¨Ìõ¼þÏ£¬ÈÜÒºµÄËá¼îÐÔ¶ÔTiO2¹â´ß»¯È¾ÁÏR½µ½â·´Ó¦µÄÓ°Ïì ÈçÓÒͼËùʾ¡£ÏÂÁÐÅжÏÕýÈ·µÄÊÇ(      ) 

   A£®ÔÚ0-50 minÖ®¼ä£¬ pH = 2ºÍPH = 7ʱRµÄ½µ½â°Ù·ÖÂʲ»ÏàµÈ

   B£®ÔÚ 20-25 minÖ®¼ä£¬ pH = 10 ʱRµÄƽ¾ù½µ½âËÙÂÊΪ  0.04 mol•L-1•min-1

   C£®ÈÜÒºËáÐÔԽǿ£¬ R µÄ½µ½âËÙÂÊԽС

   D£®RµÄÆðʼŨ¶ÈºÍÈÜÒºµÄPH¾ùÓ°ÏìRµÄ½µ½âËÙÂÊ


¡¾¿¼µã¡¿±¾Ì⿼²é»¯Ñ§·´Ó¦ËÙÂʵÄͼÏñÎÊÌ⣬·´Ó¦Ìõ¼þ¶Ô·´Ó¦ËÙÂʵÄÓ°ÏìµÈ֪ʶµã¡£

¡¾½âÎö¡¿ÓÉͼÏñ¿ÉµÃ0-50 minÖ®¼ä£¬ pH = 2ºÍPH = 7ʱRµÄŨ¶È±ä»¯Ïàͬ£¬RµÄ½µ½â°Ù·ÖÂÊÏàͬ£¬A´íÎó£»ÔÚ 20-25 minÖ®¼ä£¬ pH = 10 ʱRµÄƽ¾ù½µ½âËÙÂÊΪ  0.2¡Á10-4mol•L-1¡¢/5min=0.04 ¡Á10-4mol•L-1•min-1 £¬B´íÎó£»ÓÉͼÏñ¿ÉµÃÈÜÒºËáÐÔԽǿ£¬ R µÄ½µ½âËÙÂÊÔ½´ó£¬pH=2ʱ£¬·´Ó¦ËÙÂÊ×î´ó£¬C´íÎó£»ÈÜÒºµÄŨ¶ÈºÍÈÜÒºµÄpH¶Ô½µ½âËÙÂÊÓÐÓ°Ï죬DÕýÈ·¡£¡¾´ð°¸¡¿D


Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

µí·ÛË®½âµÄ²úÎC6H12O6£©ÓÃÏõËáÑõ»¯¿ÉÒÔÖÆ±¸²ÝËᣬװÖÃÈçͼËùʾ£¨¼ÓÈÈ¡¢½Á°èºÍÒÇÆ÷¹Ì¶¨×°ÖþùÒÑÂÔÈ¥£©£ºÊµÑé¹ý³ÌÈçÏ£º¢Ù½«1¡Ã1µÄµí·ÛË®ÈéÒºÓëÉÙÐíÁòËá(98%)¼ÓÈëÉÕ±­ÖУ¬Ë®Ô¡¼ÓÈÈÖÁ85¡æ¡«90¡æ£¬±£³Ö30 min£¬È»ºóÖð½¥½«Î¶ȽµÖÁ60¡æ×óÓÒ£»¢Ú½«Ò»¶¨Á¿µÄµí·ÛË®½âÒº¼ÓÈëÈý¾±ÉÕÆ¿ÖУ»¢Û¿ØÖÆ·´Ó¦ÒºÎ¶ÈÔÚ55¡«60¡æÌõ¼þÏ£¬±ß½Á°è±ß»ºÂýµÎ¼ÓÒ»¶¨Á¿º¬ÓÐÊÊÁ¿´ß»¯¼ÁµÄ»ìËᣨ65%HNO3¡¢98%H2SO4µÄÖÊÁ¿±ÈΪ2£º1.5£©ÈÜÒº£»¢Ü·´Ó¦3h×óÓÒ£¬ÀäÈ´£¬¹ýÂ˺óÔÙÖØ½á¾§µÃ²ÝËá¾§Ìå¡£

ÏõËáÑõ»¯µí·ÛË®½âÒº¹ý³ÌÖпɷ¢ÉúÏÂÁз´Ó¦£º

C6H12O6£«12HNO3¡ú3H2C2O4£«9NO2¡ü£«3NO¡ü£«9H2O         

C6H12O6£«8HNO3¡ú6CO2£«8NO¡ü£«10H2O                                           3H2C2O4£«2HNO3¡ú6CO2£«2NO¡ü£«4H2O

Çë»Ø´ðÏÂÁÐÎÊÌ⣺

 (1)ʵÑé¢Ù¼ÓÈë98%ÁòËáÉÙÐíµÄÄ¿µÄÊÇ£º  ¡ø   ¡£

(2)ÀäÄýË®´Óa¿Ú½øÈ룬µ«ÊµÑéÖÐÈô»ìËáµÎ¼Ó¹ý¿ì£¬½«µ¼Ö²ÝËá²úÁ¿Ï½µ£¬ÆäÔ­ÒòÊÇ  ¡ø   ¡£

(3)¼ìÑéµí·ÛÊÇ·ñË®½âÍêÈ«ËùÓõÄÊÔ¼ÁΪ  ¡ø   ¡£

(4) µ±Î²ÆøÖÐn(NO2):n(NO)£½1£º1ʱ£¬¹ýÁ¿µÄNaOHÈÜÒºÄܽ«NOxÈ«²¿ÎüÊÕ£¬·¢ÉúµÄ»¯Ñ§·´Ó¦·½³ÌʽΪ£º  ¡ø   ¡£

(5) ½«²úÆ·ÔÚºãÎÂÏäÄÚÔ¼90¡æÒÔϺæ¸ÉÖÁºãÖØ£¬µÃµ½¶þË®ºÏ²ÝËá¡£ÓÃKMnO4±ê×¼ÈÜÒºµÎ¶¨£¬¸Ã·´Ó¦µÄÀë×Ó·½³ÌʽΪ£º2MnO4- + 5H2C2O4 + 6H+ = 2Mn2+ + 10CO2¡ü+ 8H2O

³ÆÈ¡¸ÃÑùÆ·0.12 g£¬¼ÓÊÊÁ¿Ë®ÍêÈ«Èܽ⣬ȻºóÓÃ0.020 mol¡¤L-1µÄËáÐÔKMnO4ÈÜÒºµÎ¶¨ÖÁÖյ㣨ÔÓÖʲ»²ÎÓë·´Ó¦£©£¬´ËʱµÎ¶¨ÖÕµãµÄÏÖÏóΪ  ¡ø   ¡£µÎ¶¨Ç°ºóµÎ¶¨¹ÜÖеÄÒºÃæ¶ÁÊýÈçͼËùʾ£¬Ôò¸Ã²ÝËá¾§ÌåÑùÆ·ÖжþË®ºÏ²ÝËáµÄÖÊÁ¿·ÖÊýΪ  ¡ø   ¡£


ÓÃÈçͼËùʾװÖýøÐÐʵÑé(¼Ð³Ö×°ÖÃÒÑÂÔÈ¥)¡£Çë»Ø´ðÏÂÁÐÎÊÌ⣺

(1)ÈôAÖÐΪŨÁòËᣬBÖÐΪÌúµ¥ÖÊ£¬CÖÐΪÇâÑõ»¯ÄÆÈÜÒº¡£½«Å¨ÁòËáµÎÈëBÖУ¬ÔòBÖн«·¢Éú________ÏÖÏó£»ÌúÔªËØÔÚÖÜÆÚ±íÖеÄλÖÃΪ____________________£»»ù̬ÌúÔ­×ÓºËÍâµç×ÓÅŲ¼Ê½Îª________________________________________________________________________¡£

(2)ÈôAÖÐΪŨÏõËᣬBÖÐΪͭµ¥ÖÊ£¬CÖÐΪÇâÑõ»¯ÄÆÈÜÒº¡£½«Å¨ÏõËáµÎÈëBÖУ¬ÔòBÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ_______________________________________________¡£

(3)ÈôAÖÐΪŨ°±Ë®£¬BÖÐΪij¹ÌÌ壬CÖÐΪÃ÷·¯ÈÜÒº¡£

¢Ù½«Å¨°±Ë®ÖðµÎµÎÈëBÖУ¬¿É²úÉú´óÁ¿°±Æø£¬ÔòBÖйÌÌå¿ÉÄÜÊÇ________(ÌîÐòºÅ)¡£

a£®CaO¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡                      b£®NaOH

c£®NaCl                                         d£®P2O5

¢ÚCÖÐͨÈë¹ýÁ¿°±ÆøÊ±£¬·´Ó¦µÄÀë×Ó·½³ÌʽΪ________________________________¡£

(4)ÈôAÖÐΪϡÑÎËᣬBÖÐΪ̼Ëá¸Æ£¬CÖÐΪNaAlO2ÈÜÒº£¬½«Ï¡ÑÎËáµÎÈëBÖкó£¬BÖз´Ó¦µÄÀë×Ó·½³ÌʽΪ_____________________________________________________________£»

²»¿¼ÂÇHClµÄ»Ó·¢£¬Èô²úÉúµÄÆøÌå×ãÁ¿£¬ÔòCÖз¢Éú·´Ó¦µÄÀë×Ó·½³ÌʽΪ________________________________________________________________________¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø