ÌâÄ¿ÄÚÈÝ


ÔÚÒ»¶¨Î¶ÈÏ£¬½«ÆøÌåXºÍÆøÌåY¸÷0.16 mol³äÈë10 LºãÈÝÃܱÕÈÝÆ÷ÖУ¬·¢Éú·´Ó¦X(g)£«Y(g) 2Z(g)¡¡¦¤H£¼0£¬Ò»¶Îʱ¼äºó´ïµ½Æ½ºâ¡£·´Ó¦¹ý³ÌÖвⶨµÄÊý¾ÝÈçÏÂ±í£º

t/min

2

4

7

9

n(Y)/mol

0.12

0.11

0.10

0.10

ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ(¡¡¡¡)

A£®·´Ó¦Ç°2 minµÄƽ¾ùËÙÂÊv(Z)£½2.0¡Á10£­3 mol/(L·min)

B£®ÆäËûÌõ¼þ²»±ä£¬½µµÍζȣ¬·´Ó¦´ïµ½ÐÂÆ½ºâǰvÄæ£¾vÕý

C£®¸ÃζÈÏ´˷´Ó¦µÄƽºâ³£ÊýK£½1.44

D£®ÆäËûÌõ¼þ²»±ä£¬ÔÙ³äÈë0.2 mol Z£¬Æ½ºâʱXµÄÌå»ý·ÖÊýÔö´ó

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

ÀûÓû¯Ê¯È¼ÁÏ¿ª²É¡¢¼Ó¹¤¹ý³Ì²úÉúµÄH2S ·ÏÆøÖÆÈ¡ÇâÆø£¬¼È¼ÛÁ®ÓÖ»·±£¡£

(1)¹¤ÒµÉÏ¿ÉÓÃ×é³ÉΪK2O·M2O3·2RO2·nH2OµÄÎÞ»ú²ÄÁÏ´¿»¯ÖÆÈ¡µÄÇâÆø¡£

¢ÙÒÑÖªÔªËØM¡¢R¾ùλÓÚÔªËØÖÜÆÚ±íÖеÚ3ÖÜÆÚ£¬Á½ÖÖÔªËØÔ­×ÓµÄÖÊ×ÓÊýÖ®ºÍΪ27£¬ÔòRµÄÔ­×ӽṹʾÒâͼΪ________¡£

¢Ú³£ÎÂÏ£¬²»ÄÜÓëMµ¥ÖÊ·¢Éú·´Ó¦µÄÊÇ____________(ÌîÐòºÅ)¡£

a£®CuSO4ÈÜÒº¡¡b£®Fe2O3¡¡c£®Å¨ÁòËá

d£®NaOHÈÜÒº¡¡e£®Na2CO3¹ÌÌå

(2)ÀûÓÃH2S·ÏÆøÖÆÈ¡ÇâÆøµÄ·½·¨ÓжàÖÖ¡£

¢Ù¸ßÎÂÈȷֽⷨ

ÒÑÖª£ºH2S(g) H2(g)£«S2(g)

ÔÚºãÈÝÃܱÕÈÝÆ÷ÖУ¬¿ØÖƲ»Í¬Î¶ȽøÐÐH2S·Ö½âʵÑé¡£ÒÔH2SÆðʼŨ¶È¾ùΪc mol·L£­1²â¶¨H2SµÄת»¯ÂÊ£¬½á¹û¼ûͼËùʾ¡£Í¼ÖÐaΪH2SµÄƽºâת»¯ÂÊÓëζȹØÏµÇúÏߣ¬bÇúÏß±íʾ²»Í¬Î¶ÈÏ·´Ó¦¾­¹ýÏàͬʱ¼äÇÒδ´ïµ½»¯Ñ§Æ½ºâʱH2SµÄת»¯ÂÊ¡£¾Ýͼ¼ÆËã 985 ¡æÊ±H2S°´ÉÏÊö·´Ó¦·Ö½âµÄƽºâ³£ÊýK£½________£»ËµÃ÷ËæÎ¶ȵÄÉý¸ß£¬ÇúÏßbÏòÇúÏßa±Æ½üµÄÔ­Òò£º_______________________________¡£

¢Úµç»¯Ñ§·¨

¸Ã·¨ÖÆÇâ¹ý³ÌµÄʾÒâͼÈçͼËùʾ¡£·´Ó¦³ØÖз´Ó¦ÎïµÄÁ÷Ïò²ÉÓÃÆø¡¢ÒºÄæÁ÷·½Ê½£¬ÆäÄ¿µÄÊÇ

________________________________________________________________________£»

·´Ó¦³ØÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ_____________________________________________

________________________________________________________________________¡£

·´Ó¦ºóµÄÈÜÒº½øÈëµç½â³Ø£¬µç½â×Ü·´Ó¦µÄÀë×Ó·½³ÌʽΪ__________________________________¡£


µâÔÚ¿ÆÑÐÓëÉú»îÖÐÓÐÖØÒªÓ¦Óá£Ä³ÐËȤС×éÓÃ0.50 mol·L£­1 KI¡¢0.2%µí·ÛÈÜÒº¡¢0.20 mol·L£­1 K2S2O8¡¢0.10 mol·L£­1 Na2S2O3µÈÊÔ¼Á£¬Ì½¾¿·´Ó¦Ìõ¼þ¶Ô»¯Ñ§·´Ó¦ËÙÂʵÄÓ°Ïì¡£

ÒÑÖª£ºS2O£«2I£­===2SO£«I2 (Âý)

I2£«2S2O===2I£­£«S4O (¿ì)

(1)ÏòKI¡¢Na2S2O3Óëµí·ÛµÄ»ìºÏÈÜÒºÖмÓÈëÒ»¶¨Á¿µÄK2S2O8ÈÜÒº£¬µ±ÈÜÒºÖеÄ________ºÄ¾¡ºó£¬ÈÜÒºÑÕÉ«½«ÓÉÎÞÉ«±äΪÀ¶É«¡£ÎªÈ·±£Äܹ۲쵽À¶É«£¬S2OÓëS2O³õʼµÄÎïÖʵÄÁ¿ÐèÂú×ãµÄ¹ØÏµÎªn(S2O)¡Ãn(S2O)__________¡£

(2)Ϊ̽¾¿·´Ó¦ÎïŨ¶È¶Ô»¯Ñ§·´Ó¦ËÙÂʵÄÓ°Ï죬Éè¼ÆµÄʵÑé·½°¸ÈçÏÂ±í£º

ʵÑé

ÐòºÅ

Ìå»ýV/mL

K2S2O8ÈÜÒº

Ë®

KIÈÜÒº

Na2S2O3ÈÜÒº

µí·ÛÈÜÒº

¢Ù

10.0

0.0

4.0

4.0

2.0

¢Ú

9.0

1.0

4.0

4.0

2.0

¢Û

8.0

Vx

4.0

4.0

2.0

±íÖÐVx£½______________£¬ÀíÓÉÊÇ___________________________________¡£

(3)ÒÑ֪ijÌõ¼þÏ£¬Å¨¶Èc(S2O)¡«·´Ó¦Ê±¼ätµÄ±ä»¯ÇúÏßÈçͼËùʾ£¬Èô±£³ÖÆäËûÌõ¼þ²»±ä£¬ÇëÔÚ×ø±êͼÖУ¬·Ö±ð»­³ö½µµÍ·´Ó¦Î¶ȺͼÓÈë´ß»¯¼Áʱc(S2O)¡«tµÄ±ä»¯ÇúÏßʾÒâͼ(½øÐÐÏàÓ¦µÄ±ê×¢)¡£

 (4)µâÒ²¿ÉÓÃ×÷ÐÄÔàÆð²«Æ÷µçÔ´——﮵âµç³ØµÄ²ÄÁÏ¡£

¸Ãµç³Ø·´Ó¦Îª2Li(s)£«I2(s)===2LiI(s)¡¡¦¤H

ÒÑÖª£º4Li(s)£«O2(g)===2Li2O(s)¡¡¦¤H1

4LiI(s)£«O2(g)===2I2(s)£«2Li2O(s)¡¡¦¤H2

Ôòµç³Ø·´Ó¦µÄ¦¤H£½__________£»µâµç¼«×÷Ϊ¸Ãµç³ØµÄ________¼«¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø