ÌâÄ¿ÄÚÈÝ
ÔÚÏÂÁм¸ÖÖ¼òµ¥µÄÔµç³ØÖУ¬°´ÒªÇóÌî¿Õ£º
£¨1£©½«Ð¿¡¢ÍÓõ¼ÏßÁ¬½Óºó¹²Í¬½þÈë2mol/LµÄÏ¡ÁòËáÖУ¬Õý¼«µç¼«·´Ó¦Ê½Îª__________£¬·¢Éú __________·´Ó¦£¨ÌîÑõ»¯»ò»¹Ô£©£»µç×Ó´Ó_______¾Íâµç·µ½________£¨Ìîп»òÍ£©£¬ÈÜÒºÖÐH+ Ïò________ ÒÆ¶¯£¨ÌîÕý¼«»ò¸º¼«£©£¬·ÅµçÒ»¶Îʱ¼äºó£¬Õý¼«ÇøpHÖµ__________ £¨Ìî±ä´ó¡¢±äС»ò²»±ä£©¡£
£¨2£©½«ÍƬºÍÌúƬÓõ¼ÏßÁ¬½Óºó²åÈëÈýÂÈ»¯ÌúÈÜÒºÖУ¬Ò²ÓеçÁ÷ͨ¹ýµçÁ÷±í¡£»³ö¸Ãµç³Ø½á¹¹µÄʾÒâͼ£¬ÔÚͼÉϱê³öÕý¡¢¸º¼«£¬µç½âÖʺ͵ç×ÓÁ÷Ïò
д³ö¸º¼«µç¼«·´Ó¦Ê½Îª__________£¬×Ü·´Ó¦µÄÀë×Ó·½³ÌʽΪ______ ¡£
£¨1£©½«Ð¿¡¢ÍÓõ¼ÏßÁ¬½Óºó¹²Í¬½þÈë2mol/LµÄÏ¡ÁòËáÖУ¬Õý¼«µç¼«·´Ó¦Ê½Îª__________£¬·¢Éú __________·´Ó¦£¨ÌîÑõ»¯»ò»¹Ô£©£»µç×Ó´Ó_______¾Íâµç·µ½________£¨Ìîп»òÍ£©£¬ÈÜÒºÖÐH+ Ïò________ ÒÆ¶¯£¨ÌîÕý¼«»ò¸º¼«£©£¬·ÅµçÒ»¶Îʱ¼äºó£¬Õý¼«ÇøpHÖµ__________ £¨Ìî±ä´ó¡¢±äС»ò²»±ä£©¡£
£¨2£©½«ÍƬºÍÌúƬÓõ¼ÏßÁ¬½Óºó²åÈëÈýÂÈ»¯ÌúÈÜÒºÖУ¬Ò²ÓеçÁ÷ͨ¹ýµçÁ÷±í¡£»³ö¸Ãµç³Ø½á¹¹µÄʾÒâͼ£¬ÔÚͼÉϱê³öÕý¡¢¸º¼«£¬µç½âÖʺ͵ç×ÓÁ÷Ïò
д³ö¸º¼«µç¼«·´Ó¦Ê½Îª__________£¬×Ü·´Ó¦µÄÀë×Ó·½³ÌʽΪ______ ¡£
£¨3£©½«ÌúƬºÍʯīµç¼«Óõ¼ÏßÁ¬½Óºó²åÈëÂÈ»¯ÄÆÈÜÒºÖУ¬Ò²ÓеçÁ÷ͨ¹ýµçÁ÷±í£¬Çëд³ö¸º¼«µç¼«·´Ó¦Ê½____________£¬Õý¼«µç¼«·´Ó¦Ê½Îª_____________¡£
£¨1£©2H++2e-==H2¡ü £»»¹Ô £»Ð¿ £»Í £»Õý¼« £»±ä´ó
£¨2£©Í¼¡°ÂÔ¡± Cu-2e-==Cu2+ £»Cu+2Fe3+==Cu2++2Fe2+
£¨3£©¸º¼«£º2Fe-4e-==2Fe2+ £»Õý¼«£ºO2+4e-+2H2O==4OH-
£¨2£©Í¼¡°ÂÔ¡± Cu-2e-==Cu2+ £»Cu+2Fe3+==Cu2++2Fe2+
£¨3£©¸º¼«£º2Fe-4e-==2Fe2+ £»Õý¼«£ºO2+4e-+2H2O==4OH-
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿