ÌâÄ¿ÄÚÈÝ
ϱíΪ²¿·Ö¶ÌÖÜÆÚÔªËØÐÔÖʵÄÊý¾Ý£º
(1)д³öÏÂÁÐÔªËØµÄÔªËØ·ûºÅ£ºC________ £¬D _______£¬I____¡£
(2)AÓëB°´Ô×Ó¸öÊý±È2£º1×é³ÉÒ»ÖÖ»¯ºÏÎï¼×£¬BÓëC°´Ô×Ó¸öÊý±È1£º1×é³ÉÒ»ÖÖ»¯ºÏÎïÒÒ£¬¼×ÓëÒÒ·¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ____¡£
(3)EºÍGµÄµ¥Öʳ£ÓÃÓÚÖÆÔìºÏ½ð£¬Ä³Í¬Ñ§Îª²â¶¨Ä³ÖÖE¡¢GºÏ½ðÖÐEµ¥Öʵĺ¬Á¿£¬ÔÚ±ê×¼×´¿öϽøÐмס¢ÒÒ¡¢±ûÈý×éʵÑ飺 Èý×é¸÷È¡30.0mLͬŨ¶ÈµÄÑÎËᣬ¼ÓÈë¸ÃºÏ½ðÑùÆ··ÛÄ©£¬²úÉúÆøÌ壬ÓйØÊý¾ÝÈçϱíËùʾ£ºÔò¸ÃºÏ½ðÖÐEµ¥ÖʵÄÖÊÁ¿·ÖÊýΪ__________________ ¡£
(2)AÓëB°´Ô×Ó¸öÊý±È2£º1×é³ÉÒ»ÖÖ»¯ºÏÎï¼×£¬BÓëC°´Ô×Ó¸öÊý±È1£º1×é³ÉÒ»ÖÖ»¯ºÏÎïÒÒ£¬¼×ÓëÒÒ·¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ____¡£
(3)EºÍGµÄµ¥Öʳ£ÓÃÓÚÖÆÔìºÏ½ð£¬Ä³Í¬Ñ§Îª²â¶¨Ä³ÖÖE¡¢GºÏ½ðÖÐEµ¥Öʵĺ¬Á¿£¬ÔÚ±ê×¼×´¿öϽøÐмס¢ÒÒ¡¢±ûÈý×éʵÑ飺 Èý×é¸÷È¡30.0mLͬŨ¶ÈµÄÑÎËᣬ¼ÓÈë¸ÃºÏ½ðÑùÆ··ÛÄ©£¬²úÉúÆøÌ壬ÓйØÊý¾ÝÈçϱíËùʾ£ºÔò¸ÃºÏ½ðÖÐEµ¥ÖʵÄÖÊÁ¿·ÖÊýΪ__________________ ¡£
(1)Na£»S£»P
(2)2H2O+2Na2O2==4NaOH+O2¡ü
(3)47.1%
(2)2H2O+2Na2O2==4NaOH+O2¡ü
(3)47.1%
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿