ÌâÄ¿ÄÚÈÝ

(8·Ö)ÉèÈýÖÖ²»Í¬ÓлúÎïµÄ·Ö×Óʽ·Ö±ðΪ£ºCxHy¡¢CmHn¡¢CaHbOc ¡£
£¨1£©ÈôCxHy¡¢CmHnµÈÎïÖʵÄÁ¿£¬³ä·ÖȼÉÕÏûºÄO2Á¿ÏàµÈ£¬Ôòx¡¢y¡¢m ¡¢nÒ»¶¨´æÔڵĵÈʽ¹ØÏµÊÇ              
£¨2£©ÈôCxHy¡¢CmHnµÈÖÊÁ¿£¬³ä·ÖȼÉÕÏûºÄO2Á¿ÏàµÈ£¬Ôòx¡¢y¡¢m ¡¢nÒ»¶¨´æÔڵĵÈʽ¹ØÏµÊÇ  
£¨3£©ÈôCxHy¡¢CaHbOcµÈÎïÖʵÄÁ¿£¬³ä·ÖȼÉÕÏûºÄO2Á¿ÏàµÈ£¬ÔòCaHbOc¿ÉÒÔ±í´ïΪ£º
CxHy¡¤        CO2¡¤           H2O £¨ºáÏßÉÏÌîÏà¹ØÏµÊý£©

£¨8·Ö£©£¨1£©x + y/4  =  m  + n/4 £¨2£©x/y=  m/n £¨3£©£¨a-x£©£¨b-y£©/2

½âÎö

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø