ÌâÄ¿ÄÚÈÝ

ÔÚ´×ËáÓëÇâÑõ»¯ÄÆÈÜÒºµÄ·´Ó¦¹ý³ÌÖУ¬ÈÜÒºÖеÄÏà¹ØÀë×ÓŨ¶È³ÊÏÖ³öÏÂÁÐÅÅÁÐ˳Ðò£º c(CH3COO£­)£¾c(Na+)£¾c(H+)£¾c(OH£­)¡£Âú×ã¸ÃÌõ¼þµÄ·´Ó¦ÊÇ(    )

A£®0.01mol¡¤L£­1µÄCH3COOHÓëpH=12µÄNaOHÈÜÒºµÈÌå»ý»ìºÏ

B£®0.2 mol¡¤L£­1µÄCH3COOHÈÜÒºÓë0.1 mol¡¤L£­1µÄNaOHÈÜÒºµÈÌå»ý»ìºÏ

C£®CH3COOHÈÜÒºÓëNaOHÈÜÒº»ìºÏºóËùµÃÈÜÒºµÄpH=7

D£®0.1 mol¡¤L£­1µÄCH3COOHÈÜÒºÓëµÈÎïÖʵÄÁ¿Å¨¶È¡¢µÈÌå»ýµÄNaOHÈÜÒº»ìºÏ

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø