ÌâÄ¿ÄÚÈÝ

ÒÑÖª£ºÔÚ25¡æÊ±£¬
H2OH+ + OH-£¬KW=10-14£»
CH3COOH    H+ + CH3COO£­£¬Ka=1.8¡Á10-5£»
KSP[Mg(OH)2]=1.8¡Á10-11¡¢KSP[Zn(OH)2]=1.2¡Á10-17¡¢KSP[Cd(OH)2]=2.5¡Á10-14
ÓÖÒÑÖª£º=2.2
ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ
[     ]
A£®´×ËáÄÆË®½âµÄƽºâ³£ÊýKhËæÎ¶ÈÉý¸ß¶ø¼õС£»
B£®0.5mol¡¤L-1´×ËáÄÆÈÜÒºpHΪm£¬ÆäË®½âµÄ³Ì¶È£¨ÒÑË®½âµÄ´×ËáÄÆÓëÔ­Óд×ËáÄÆµÄ±ÈÖµ£©Îªa£»1mol¡¤L-1´×ËáÄÆÈÜÒºpHΪn£¬Ë®½âµÄ³Ì¶ÈΪb£¬Ôòm£¼n¡¢a£¾b£»
C£®´×ËáÄÆµÄË®½âµÄƽºâ³£ÊýKh= KW¡¤Ka£»
D£®ÔÚijÈÜÒºÖк¬Mg2+¡¢Cd2+¡¢Zn2+ÈýÖÖÀë×ÓµÄŨ¶È¾ùΪ0.01mol¡¤L-1£¬ÏòÆäÖмÓÈë¹ÌÌå´×ËáÄÆ£¬Ê¹ÆäŨ¶ÈΪ0.9mol¡¤L-1£¬ÒÔÉÏÈýÖÖ½ðÊôÀë×ÓÖÐÖ»ÓÐZn2+ ÄÜÉú³É³Áµí¡£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
ÒÑÖª£ºÔÚ25ʱH2O?H++OH-£¬KW=10-14£»CH3COOH?H++CH3COO-£¬Ka=1.8¡Á10-5
£¨1£©È¡ÊÊÁ¿´×ËáÈÜÒº£¬¼ÓÈëÉÙÁ¿´×ËáÄÆ¹ÌÌ壬´ËʱÈÜÒºÖÐC£¨H+£©ÓëC£¨CH3COOH£©µÄ±ÈÖµ
¼õС
¼õС
£¨Ìî¡°Ôö´ó¡±»ò¡°¼õС¡±»ò¡°²»±ä¡±£©
£¨2£©´×ËáÄÆË®½âµÄÀë×Ó·½³ÌʽΪ
CH3COO-+H2O?CH3COOH+OH-£»
CH3COO-+H2O?CH3COOH+OH-£»
£®µ±Éý¸ßζÈʱ£¬C£¨OH-£©½«
Ôö´ó
Ôö´ó
£¨Ìî¡°Ôö´ó¡±¡°¼õС¡±¡°²»±ä¡±£©£»
£¨3£©0.5mol?L-1´×ËáÄÆÈÜÒºpHΪm£¬ÆäË®½âµÄ³Ì¶È£¨ÒÑË®½âµÄ´×ËáÄÆÓëÔ­Óд×ËáÄÆµÄ±ÈÖµ£©Îªa£»1mol?L-1´×ËáÄÆÈÜÒºpHΪn£¬Ë®½âµÄ³Ì¶ÈΪb£¬ÔòmÓënµÄ¹ØÏµÎª
СÓÚ
СÓÚ
£¬aÓëbµÄ¹ØÏµÎª
´óÓÚ
´óÓÚ
£¨Ìî¡°´óÓÚ¡±¡°Ð¡ÓÚ¡±¡°µÈÓÚ¡±£©£»
£¨4£©½«µÈÌå»ýµÈŨ¶ÈµÄ´×ËáºÍÇâÑõ»¯ÄÆÈÜÒº»ìºÏºó£¬ËùµÃÈÜÒºÖÐÀë×ÓŨ¶ÈÓÉ´óµ½Ð¡µÄ˳ÐòÊÇ
c£¨Na+£©£¾c£¨CH3COO-£©£¾c£¨OH-£©£¾c£¨H+£©
c£¨Na+£©£¾c£¨CH3COO-£©£¾c£¨OH-£©£¾c£¨H+£©
£®
£¨5£©Èô´×ËáºÍÇâÑõ»¯ÄÆÈÜÒº»ìºÏºópH£¼7£¬Ôòc£¨Na+£©
СÓÚ
СÓÚ
 c£¨CH3COO-£©£¨Ìî¡°´óÓÚ¡±¡¢¡°Ð¡ÓÚ¡±»ò¡°µÈÓÚ¡±£©£¬
£¨6£©ÈôÓÉpH=3µÄHAÈÜÒºV1mLÓëpH=11µÄNaOHÈÜÒºV2 mL£®»ìºÏ¶øµÃ£¬ÔòÏÂÁÐ˵·¨²»ÕýÈ·µÄÊÇ
BC
BC
£®
A£®Èô·´Ó¦ºóÈÜÒº³ÊÖÐÐÔ£¬Ôòc£¨H+£©+c£¨OH-£©=2¡Á10-7mol?L-1
B£®ÈôV1=V2£¬·´Ó¦ºóÈÜÒºpHÒ»¶¨µÈÓÚ7
C£®Èô·´Ó¦ºóÈÜÒº³ÊËáÐÔ£¬ÔòV1Ò»¶¨´óÓÚV2
D£®Èô·´Ó¦ºóÈÜÒº³Ê¼îÐÔ£¬ÔòV1Ò»¶¨Ð¡ÓÚV2
£¨7£©ÔÚijÈÜÒºÖк¬Mg2+¡¢Cd2+¡¢Zn2+ÈýÖÖÀë×ÓµÄŨ¶È¾ùΪ0.01mol?L-1£®ÏòÆäÖмÓÈë¹ÌÌå´×ËáÄÆºó²âµÃÈÜÒºµÄC£¨OH-£©Îª2.2¡Á10-5mol?L-1£¬£¨²»¿¼ÂÇÈÜÒºÌå»ý±ä»¯£©ÒÔÉÏÈýÖÖ½ðÊôÀë×ÓÖÐ
Cd2+¡¢Zn2+
Cd2+¡¢Zn2+
ÄÜÉú³É³Áµí£¬Ô­ÒòÊÇ
[OH-]=2.2¡Á10-5mol?L-1 ¡¢[M2+][OH-]2=5¡Á10-12£¨mol?L-1£©3¡¢5¡Á10-12СÓÚKSP[Mg£¨OH£©2]=1.8¡Á10-11 £¬5¡Á10-12´óÓÚKSP[Zn£¨OH£©2]=1.2¡Á10-17 £¬5¡Á10-12´óÓÚKSP[Cd£¨OH£©2]=2.5¡Á10-14£®
[OH-]=2.2¡Á10-5mol?L-1 ¡¢[M2+][OH-]2=5¡Á10-12£¨mol?L-1£©3¡¢5¡Á10-12СÓÚKSP[Mg£¨OH£©2]=1.8¡Á10-11 £¬5¡Á10-12´óÓÚKSP[Zn£¨OH£©2]=1.2¡Á10-17 £¬5¡Á10-12´óÓÚKSP[Cd£¨OH£©2]=2.5¡Á10-14£®

£¨KSP[Mg£¨OH£©2]=1.8¡Á10-11¡¢KSP[Zn£¨OH£©2]=1.2¡Á10-17¡¢KSP[Cd£¨OH£©2]=2.5¡Á10-14£©
£¨8£©È¡10mL 0.5mol?L-1ÑÎËáÈÜÒº£¬¼ÓˮϡÊ͵½500mL£¬Ôò¸ÃÈÜÒºÖÐÓÉË®µçÀë³öµÄc£¨H+£©=
1¡Á10-12
1¡Á10-12
£®

£¨¢ñ£©£¨6·Ö£©ÏÖÓÐÏÂÁÐÎïÖÊ£º ¢ÙNaCl¾§Ìå¡¡¢ÚҺ̬SO2¡¡¢Û´¿´×Ëá¡¡¢ÜÁòËá±µ¡¡¢ÝÍ­  ¢Þ¾Æ¾«£¨C2H5OH£© ¢ßÈÛ»¯µÄKCl¡¡¢àNaOHÈÜÒº¡¡
ÇëÓÃÒÔÉÏÎïÖʻشðÏÂÁÐÎÊÌâ¡££¨ÌîÐòºÅ£©
£¨1£©ÔÚÉÏÊö״̬ÏÂÄܵ¼µçµÄÎïÖÊÊÇ¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡ £»
£¨2£©ÊôÓÚÈõµç½âÖʵÄÊÇ¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡ £»
£¨3£©ÊôÓڷǵç½âÖÊ£¬µ«ÈÜÓÚË®ºóµÄË®ÈÜÒºÄܵ¼µçµÄÊÇ¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡ £»
£¨¢ò£©£¨4·Ö£©
ij»¯Ñ§ÊµÑéС×é̽¾¿ÊÐÊÛʳÓð״×Öд×ËáµÄµÄ׼ȷŨ¶È£¬È¡25.00mLÄ³Æ·ÅÆÊ³Óð×
´×ÓÚ×¶ÐÎÆ¿ÖУ¬ÔÚʵÑéÊÒÓÃŨ¶ÈΪcb mol/LµÄ±ê×¼NaOHÈÜÒº¶ÔÆä½øÐеζ¨¡£
£¨1£©×óͼ±íʾ50mLµÎ¶¨¹ÜÖÐÒºÃæµÄλÖã¬ÈôAÓëC¿Ì¶È¼äÏà²îl mL£¬  
A´¦µÄ¿Ì¶ÈΪ25£¬µÎ¶¨¹ÜÖÐÒºÃæ¶ÁÊýӦΪ¡¡¡¡¡¡¡¡¡¡mL¡£

£¨2£©ÎªÁ˼õСʵÑéÎó²î£¬¸Ãͬѧһ¹²½øÐÐÁËÈý´ÎʵÑ飬¼ÙÉèÿ´Î
ËùÈ¡°×´×Ìå»ý¾ùΪVmL£¬NaOH±ê׼ҺŨ¶ÈΪc mo1/L£¬Èý´Îʵ
Ñé½á¹û¼Ç¼ÈçÏ£º  

ʵÑé´ÎÊý
µÚÒ»´Î
µÚ¶þ´Î
µÚÈý´Î
ÏûºÄNaOHÈÜÒºÌå»ý/mL
26.02
25.35
25.30
´ÓÉϱí¿ÉÒÔ¿´³ö£¬µÚÒ»´ÎʵÑéÖмǼÏûºÄNaOHÈÜÒºµÄÌå»ýÃ÷ÏÔ¶àÓÚºóÁ½´Î£¬
ÆäÔ­Òò¿ÉÄÜÊÇ¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡ ¡£
A£®µÎ¶¨Ç°µÎ¶¨¹Ü¼â×ìÓÐÆøÅÝ£¬µÎ¶¨½áÊøÎÞÆøÅÝ
B£®Ê¢×°±ê×¼ÒºµÄµÎ¶¨¹ÜװҺǰÓÃÕôÁóË®ÈóÏ´¹ý£¬Î´Óñê×¼ÒºÈóÏ´
C£®µÚÒ»´ÎµÎ¶¨ÓõÄ×¶ÐÎÆ¿Î´ÈóÏ´
D£®µÎ¶¨½áÊøÊ±£¬¸©ÊÓ¶ÁÊý
£¨3£©¸ù¾ÝËù¸øÊý¾Ý£¬Ð´³ö¼ÆËã¸Ã°×´×Öд×ËáµÄÎïÖʵÄÁ¿Å¨¶ÈµÄ±í´ïʽ(²»±Ø»¯¼ò)£º
c£½¡¡¡¡¡¡¡¡¡¡    ¡¡¡¡¡¡ ¡£
£¨¢ó£©£¨15·Ö£©
ÒÑÖª£ºÔÚ25ʱH2OH++OH-¡¡KW=10-14¡¡ CH3COOH H++ CH3COO£­¡¡Ka=1.8¡Á10-5
£¨1£©È¡ÊÊÁ¿´×ËáÈÜÒº£¬¼ÓÈëÉÙÁ¿´×ËáÄÆ¹ÌÌ壬´ËʱÈÜÒºÖÐC£¨H+£©ÓëC£¨CH3COOH£©
µÄ±ÈÖµ¡¡  ¡¡ £¨Ìî¡°Ôö´ó¡±»ò¡°¼õС¡±»ò¡°²»±ä¡±£©
£¨2£©´×ËáÄÆË®½âµÄÀë×Ó·½³ÌʽΪ¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡ ¡£µ±Éý¸ßζÈʱ£¬C(OH¡ª)½«¡¡¡¡¡¡¡¡
£¨Ìî¡°Ôö´ó¡±¡°¼õС¡±¡°²»±ä¡±£©£»
£¨3£©0£®5mol¡¤L-1´×ËáÄÆÈÜÒºpHΪm£¬ÆäË®½âµÄ³Ì¶È£¨ÒÑË®½âµÄ´×ËáÄÆÓëÔ­Óд×ËáÄÆ
µÄ±ÈÖµ£©Îªa£»1mol¡¤L-1´×ËáÄÆÈÜÒºpHΪn£¬Ë®½âµÄ³Ì¶ÈΪb£¬ÔòmÓënµÄ¹ØÏµ
Ϊ¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡ £¬aÓëbµÄ¹ØÏµÎª¡¡¡¡¡¡¡¡¡¡£¨Ìî¡°´óÓÚ¡±¡°Ð¡ÓÚ¡±¡°µÈÓÚ¡±£©£»
£¨4£©½«µÈÌå»ýµÈŨ¶ÈµÄ´×ËáºÍÇâÑõ»¯ÄÆÈÜÒº»ìºÏºó£¬ËùµÃÈÜÒºÖÐÀë×ÓŨ¶ÈÓÉ´óµ½Ð¡µÄ˳ÐòÊÇ¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡      ¡¡¡¡¡¡ ¡£
£¨5£©Èô´×ËáºÍÇâÑõ»¯ÄÆÈÜÒº»ìºÏºópH<7£¬Ôòc£¨Na+£©_______________ c£¨CH3COO£­£©£¨Ìî¡°´óÓÚ¡±¡¢¡°Ð¡ÓÚ¡±»ò¡°µÈÓÚ¡±£©£¬
£¨6£©ÈôÓÉpH£½3µÄHAÈÜÒºV1mLÓëpH£½11µÄNaOH{ÈÜÒºV2 mL¡£»ìºÏ¶øµÃ£¬ÔòÏÂÁÐ˵·¨²»ÕýÈ·µÄÊÇ____________¡£
A£®Èô·´Ó¦ºóÈÜÒº³ÊÖÐÐÔ£¬Ôòc£¨H+£©+c£¨OH£­£©£½2¡Á10£­7mol¡¤L£­1
B£®ÈôV1=V2£¬·´Ó¦ºóÈÜÒºpHÒ»¶¨µÈÓÚ7
C£®Èô·´Ó¦ºóÈÜÒº³ÊËáÐÔ£¬ÔòV1Ò»¶¨´óÓÚV2
D£®Èô·´Ó¦ºóÈÜÒº³Ê¼îÐÔ£¬ÔòV1Ò»¶¨Ð¡ÓÚV2
£¨7£©ÔÚijÈÜÒºÖк¬Mg2+¡¢Cd2+¡¢Zn2+ÈýÖÖÀë×ÓµÄŨ¶È¾ùΪ0.01mol¡¤L-1¡£ÏòÆäÖмÓÈë¹Ì
Ìå´×ËáÄÆºó²âµÃÈÜÒºµÄC(OH-)Ϊ2.2¡Á10-5mol¡¤L-1£¬ÒÔÉÏÈýÖÖ½ðÊôÀë×ÓÖÐ
¡¡¡¡¡¡¡¡           ÄÜÉú³É³Áµí£¬Ô­ÒòÊÇ¡¡¡¡                            ¡¡
£¨KSP£ÛMg£¨OH£©2£Ý=1.8¡Á10-11¡¢KSP£ÛZn£¨OH£©2£Ý=1.2¡Á10-17¡¢KSP£ÛCd£¨OH£©2£Ý=2.5¡Á10-14£©
£¨8£©È¡10mL0.5mol¡¤L-1ÑÎËáÈÜÒº£¬¼ÓˮϡÊ͵½500mL£¬Ôò¸ÃÈÜÒºÖÐÓÉË®µçÀë³öµÄc£¨H+£©
=¡¡¡¡¡¡   ¡¡¡£

£¨¢ñ£©£¨6·Ö£©ÏÖÓÐÏÂÁÐÎïÖÊ£º ¢ÙNaCl¾§Ìå¡¡¢ÚҺ̬SO2¡¡¢Û´¿´×Ëá¡¡¢ÜÁòËá±µ¡¡¢ÝÍ­  ¢Þ¾Æ¾«£¨C2H5OH£© ¢ßÈÛ»¯µÄKCl¡¡¢àNaOHÈÜÒº¡¡

 ÇëÓÃÒÔÉÏÎïÖʻشðÏÂÁÐÎÊÌâ¡££¨ÌîÐòºÅ£©

£¨1£©ÔÚÉÏÊö״̬ÏÂÄܵ¼µçµÄÎïÖÊÊÇ¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡ £»

£¨2£©ÊôÓÚÈõµç½âÖʵÄÊÇ¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡ £»

£¨3£©ÊôÓڷǵç½âÖÊ£¬µ«ÈÜÓÚË®ºóµÄË®ÈÜÒºÄܵ¼µçµÄÊÇ¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡ £»

£¨¢ò£©£¨4·Ö£©

ij»¯Ñ§ÊµÑéС×é̽¾¿ÊÐÊÛʳÓð״×Öд×ËáµÄµÄ׼ȷŨ¶È£¬È¡25.00mLÄ³Æ·ÅÆÊ³Óð×

´×ÓÚ×¶ÐÎÆ¿ÖУ¬ÔÚʵÑéÊÒÓÃŨ¶ÈΪcb mol/LµÄ±ê×¼NaOHÈÜÒº¶ÔÆä½øÐеζ¨¡£

£¨1£©×óͼ±íʾ50mLµÎ¶¨¹ÜÖÐÒºÃæµÄλÖã¬ÈôAÓëC¿Ì¶È¼äÏà²îl mL£¬  

A´¦µÄ¿Ì¶ÈΪ25£¬µÎ¶¨¹ÜÖÐÒºÃæ¶ÁÊýӦΪ¡¡¡¡¡¡¡¡¡¡mL¡£

£¨2£©ÎªÁ˼õСʵÑéÎó²î£¬¸Ãͬѧһ¹²½øÐÐÁËÈý´ÎʵÑ飬¼ÙÉèÿ´Î

    ËùÈ¡°×´×Ìå»ý¾ùΪVmL£¬NaOH±ê׼ҺŨ¶ÈΪc mo1/L£¬Èý´Îʵ

    Ñé½á¹û¼Ç¼ÈçÏ£º  

ʵÑé´ÎÊý

µÚÒ»´Î

µÚ¶þ´Î

µÚÈý´Î

ÏûºÄNaOHÈÜÒºÌå»ý/mL

26.02

25.35

25.30

´ÓÉϱí¿ÉÒÔ¿´³ö£¬µÚÒ»´ÎʵÑéÖмǼÏûºÄNaOHÈÜÒºµÄÌå»ýÃ÷ÏÔ¶àÓÚºóÁ½´Î£¬

ÆäÔ­Òò¿ÉÄÜÊÇ¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡ ¡£

A£®µÎ¶¨Ç°µÎ¶¨¹Ü¼â×ìÓÐÆøÅÝ£¬µÎ¶¨½áÊøÎÞÆøÅÝ

B£®Ê¢×°±ê×¼ÒºµÄµÎ¶¨¹ÜװҺǰÓÃÕôÁóË®ÈóÏ´¹ý£¬Î´Óñê×¼ÒºÈóÏ´

C£®µÚÒ»´ÎµÎ¶¨ÓõÄ×¶ÐÎÆ¿Î´ÈóÏ´

D£®µÎ¶¨½áÊøÊ±£¬¸©ÊÓ¶ÁÊý

£¨3£©¸ù¾ÝËù¸øÊý¾Ý£¬Ð´³ö¼ÆËã¸Ã°×´×Öд×ËáµÄÎïÖʵÄÁ¿Å¨¶ÈµÄ±í´ïʽ(²»±Ø»¯¼ò)£º

c£½¡¡¡¡¡¡¡¡¡¡     ¡¡¡¡¡¡ ¡£

£¨¢ó£©£¨15·Ö£©

ÒÑÖª£ºÔÚ25ʱH2OH++OH-¡¡KW=10-14¡¡ CH3COOH H++ CH3COO£­¡¡Ka=1.8¡Á10-5

£¨1£©È¡ÊÊÁ¿´×ËáÈÜÒº£¬¼ÓÈëÉÙÁ¿´×ËáÄÆ¹ÌÌ壬´ËʱÈÜÒºÖÐC£¨H+£©ÓëC£¨CH3COOH£©

µÄ±ÈÖµ¡¡   ¡¡ £¨Ìî¡°Ôö´ó¡±»ò¡°¼õС¡±»ò¡°²»±ä¡±£©

£¨2£©´×ËáÄÆË®½âµÄÀë×Ó·½³ÌʽΪ¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡ ¡£µ±Éý¸ßζÈʱ£¬C(OH¡ª)½«¡¡¡¡¡¡¡¡

£¨Ìî¡°Ôö´ó¡±¡°¼õС¡±¡°²»±ä¡±£©£»

£¨3£©0£®5mol¡¤L-1´×ËáÄÆÈÜÒºpHΪm£¬ÆäË®½âµÄ³Ì¶È£¨ÒÑË®½âµÄ´×ËáÄÆÓëÔ­Óд×ËáÄÆ

µÄ±ÈÖµ£©Îªa£»1mol¡¤L-1´×ËáÄÆÈÜÒºpHΪn£¬Ë®½âµÄ³Ì¶ÈΪb£¬ÔòmÓënµÄ¹ØÏµ

Ϊ¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡ £¬aÓëbµÄ¹ØÏµÎª¡¡¡¡¡¡¡¡¡¡£¨Ìî¡°´óÓÚ¡±¡°Ð¡ÓÚ¡±¡°µÈÓÚ¡±£©£»

£¨4£©½«µÈÌå»ýµÈŨ¶ÈµÄ´×ËáºÍÇâÑõ»¯ÄÆÈÜÒº»ìºÏºó£¬ËùµÃÈÜÒºÖÐÀë×ÓŨ¶ÈÓÉ´óµ½Ð¡µÄ˳ÐòÊÇ¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡       ¡¡¡¡¡¡ ¡£

£¨5£©Èô´×ËáºÍÇâÑõ»¯ÄÆÈÜÒº»ìºÏºópH<7£¬Ôòc£¨Na+£©_______________ c£¨CH3COO£­£©£¨Ìî¡°´óÓÚ¡±¡¢¡°Ð¡ÓÚ¡±»ò¡°µÈÓÚ¡±£©£¬

£¨6£©ÈôÓÉpH£½3µÄHAÈÜÒºV1mLÓëpH£½11µÄNaOH{ÈÜÒºV2 mL¡£»ìºÏ¶øµÃ£¬ÔòÏÂÁÐ˵·¨²»ÕýÈ·µÄÊÇ____________¡£

A£®Èô·´Ó¦ºóÈÜÒº³ÊÖÐÐÔ£¬Ôòc£¨H+£©+c£¨OH£­£©£½2¡Á10£­7mol¡¤L£­1

B£®ÈôV1=V2£¬·´Ó¦ºóÈÜÒºpHÒ»¶¨µÈÓÚ7

C£®Èô·´Ó¦ºóÈÜÒº³ÊËáÐÔ£¬ÔòV1Ò»¶¨´óÓÚV2

D£®Èô·´Ó¦ºóÈÜÒº³Ê¼îÐÔ£¬ÔòV1Ò»¶¨Ð¡ÓÚV2

£¨7£©ÔÚijÈÜÒºÖк¬Mg2+¡¢Cd2+¡¢Zn2+ÈýÖÖÀë×ÓµÄŨ¶È¾ùΪ0.01mol¡¤L-1¡£ÏòÆäÖмÓÈë¹Ì

Ìå´×ËáÄÆºó²âµÃÈÜÒºµÄC(OH-)Ϊ2.2¡Á10-5mol¡¤L-1£¬ÒÔÉÏÈýÖÖ½ðÊôÀë×ÓÖÐ

¡¡¡¡¡¡¡¡            ÄÜÉú³É³Áµí£¬Ô­ÒòÊÇ¡¡¡¡                             ¡¡

£¨KSP£ÛMg£¨OH£©2£Ý=1.8¡Á10-11¡¢KSP£ÛZn£¨OH£©2£Ý=1.2¡Á10-17¡¢KSP£ÛCd£¨OH£©2£Ý=2.5¡Á10-14£©

£¨8£©È¡10mL0.5mol¡¤L-1ÑÎËáÈÜÒº£¬¼ÓˮϡÊ͵½500mL£¬Ôò¸ÃÈÜÒºÖÐÓÉË®µçÀë³öµÄc£¨H+£©

 =¡¡¡¡¡¡    ¡¡¡£

 

ÒÑÖª£ºÔÚ25ʱH2O?H++OH-£¬KW=10-14£»CH3COOH?H++CH3COO-£¬Ka=1.8×10-5
£¨1£©È¡ÊÊÁ¿´×ËáÈÜÒº£¬¼ÓÈëÉÙÁ¿´×ËáÄÆ¹ÌÌ壬´ËʱÈÜÒºÖÐC£¨H+£©ÓëC£¨CH3COOH£©µÄ±ÈÖµ______£¨Ìî¡°Ôö´ó¡±»ò¡°¼õС¡±»ò¡°²»±ä¡±£©
£¨2£©´×ËáÄÆË®½âµÄÀë×Ó·½³ÌʽΪ______£®µ±Éý¸ßζÈʱ£¬C£¨OH-£©½«______£¨Ìî¡°Ôö´ó¡±¡°¼õС¡±¡°²»±ä¡±£©£»
£¨3£©0.5mol?L-1´×ËáÄÆÈÜÒºpHΪm£¬ÆäË®½âµÄ³Ì¶È£¨ÒÑË®½âµÄ´×ËáÄÆÓëÔ­Óд×ËáÄÆµÄ±ÈÖµ£©Îªa£»1mol?L-1´×ËáÄÆÈÜÒºpHΪn£¬Ë®½âµÄ³Ì¶ÈΪb£¬ÔòmÓënµÄ¹ØÏµÎª______£¬aÓëbµÄ¹ØÏµÎª______£¨Ìî¡°´óÓÚ¡±¡°Ð¡ÓÚ¡±¡°µÈÓÚ¡±£©£»
£¨4£©½«µÈÌå»ýµÈŨ¶ÈµÄ´×ËáºÍÇâÑõ»¯ÄÆÈÜÒº»ìºÏºó£¬ËùµÃÈÜÒºÖÐÀë×ÓŨ¶ÈÓÉ´óµ½Ð¡µÄ˳ÐòÊÇ______£®
£¨5£©Èô´×ËáºÍÇâÑõ»¯ÄÆÈÜÒº»ìºÏºópH£¼7£¬Ôòc£¨Na+£©______ c£¨CH3COO-£©£¨Ìî¡°´óÓÚ¡±¡¢¡°Ð¡ÓÚ¡±»ò¡°µÈÓÚ¡±£©£¬
£¨6£©ÈôÓÉpH=3µÄHAÈÜÒºV1mLÓëpH=11µÄNaOH{ÈÜÒºV2 mL£®»ìºÏ¶øµÃ£¬ÔòÏÂÁÐ˵·¨²»ÕýÈ·µÄÊÇ______£®
A£®Èô·´Ó¦ºóÈÜÒº³ÊÖÐÐÔ£¬Ôòc£¨H+£©+c£¨OH-£©=2×10-7mol?L-1
B£®ÈôV1=V2£¬·´Ó¦ºóÈÜÒºpHÒ»¶¨µÈÓÚ7
C£®Èô·´Ó¦ºóÈÜÒº³ÊËáÐÔ£¬ÔòV1Ò»¶¨´óÓÚV2
D£®Èô·´Ó¦ºóÈÜÒº³Ê¼îÐÔ£¬ÔòV1Ò»¶¨Ð¡ÓÚV2
£¨7£©ÔÚijÈÜÒºÖк¬Mg2+¡¢Cd2+¡¢Zn2+ÈýÖÖÀë×ÓµÄŨ¶È¾ùΪ0.01mol?L-1£®ÏòÆäÖмÓÈë¹ÌÌå´×ËáÄÆºó²âµÃÈÜÒºµÄC£¨OH-£©Îª2.2×10-5mol?L-1£¬£¨²»¿¼ÂÇÈÜÒºÌå»ý±ä»¯£©ÒÔÉÏÈýÖÖ½ðÊôÀë×ÓÖÐ______ÄÜÉú³É³Áµí£¬Ô­ÒòÊÇ______
£¨KSP[Mg£¨OH£©2]=1.8×10-11¡¢KSP[Zn£¨OH£©2]=1.2×10-17¡¢KSP[Cd£¨OH£©2]=2.5×10-14£©
£¨8£©È¡10mL 0.5mol?L-1ÑÎËáÈÜÒº£¬¼ÓˮϡÊ͵½500mL£¬Ôò¸ÃÈÜÒºÖÐÓÉË®µçÀë³öµÄc£¨H+£©=______£®

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø