ÌâÄ¿ÄÚÈÝ


ÏÖÓг£ÎÂϵÄËÄ·ÝÈÜÒº£º

¢Ù0.01 mol/L CH3COOHÈÜÒº£»¢Ú0.01 mol/L HClÈÜÒº£»¢ÛpH£½12µÄ°±Ë®£»¢ÜpH£½12µÄNaOHÈÜÒº¡£

ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ(¡¡¡¡)

A£®¢ÙÖÐË®µÄµçÀë³Ì¶È×îС£¬¢ÛÖÐË®µÄµçÀë³Ì¶È×î´ó

B£®½«¢Ù¢Ü»ìºÏ£¬Èôc(CH3COO£­)>c(H£«)£¬Ôò»ìºÏÒºÒ»¶¨³Ê¼îÐÔ

C£®½«ËÄ·ÝÈÜÒº·Ö±ðÏ¡Ê͵½Ô­Ìå»ýÏàͬ±¶Êýºó£¬ÈÜÒºµÄpH£º¢Û>¢Ü£¬¢Ú>¢Ù

D£®½«¢Ú¢Û»ìºÏ£¬ÈôpH£½7£¬ÔòÏûºÄÈÜÒºµÄÌå»ý£º¢Ú>¢Û


½âÎö£º´×ËáΪÈõËᣬ¢ÙÖÐË®µÄµçÀë³Ì¶È´óÓÚ¢ÚÖÐË®µÄµçÀë³Ì¶È£¬A´íÎó£»½«¢Ù¢Ü»ìºÏ£¬µ±¢Ù¹ýÁ¿Ê±£¬µÃµ½CH3COOHºÍCH3COONaµÄ»ìºÏÈÜÒº£¬ÈÜÒºÏÔËáÐÔ£¬´Ëʱc(CH3COO£­)>c(Na£«)>c(H£«)>c(OH£­)£¬B´íÎó£»½«ËÄ·ÝÈÜÒº·Ö±ðÏ¡Ê͵½Ô­Ìå»ýÏàͬ±¶Êýºó£¬ÈÜÒºµÄpH£º¢Û>¢Ü£¬¢Ú<¢Ù£¬C´íÎ󣻢ڢ۵ÈÌå»ý»ìºÏ£¬µÃµ½µÄÊǰ±Ë®ºÍNH4Cl»ìºÏÈÜÒº£¬ÈÜÒºÏÔ¼îÐÔ£¬ÈôpH£½7£¬ÔòÑÎËáµÄÌå»ý±È°±Ë®µÄÌå»ý´ó£¬DÕýÈ·¡£

´ð°¸£ºD


Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø