ÌâÄ¿ÄÚÈÝ
ÅäÖÆ1.0mol/L
ÈÜÒº500mL£¬Íê³ÉÏÂÁÐʵÑ飺
(1)ÐèÓÃÖÊÁ¿·ÖÊýΪ98%(ÃܶÈΪ1.84
)µÄ
________mL£®
(2)ÐèÓÃ________Á¿È¡ËùÐèŨÁòËáµÄÌå»ý£¬ÑØ________×¢ÈëÊÂÏÈÒÑÊ¢ÓÐÊÊÁ¿Ë®µÄ________ÖУ¬±ßµ¹±ß________£¬´ýÈÜÒºÀäÖÁÊÒκó²ÅÄܽ«ÈÜ񼄯________×¢Èë________mLµÄ________ÖУ®
(3)ÓÃÉÙÁ¿ÕôÁóË®³åÏ´________ºÍ________2¡«3´Î£¬²¢½«Ï´ÒºÒ²¶¼×¢Èë________ÖУ¬Õñµ´ÈÝÁ¿Æ¿ÀïµÄÈÜҺʹ»ìºÏ¾ùÔÈ£¬ÔÚ²Ù×÷Öв»µÃËðʧÈÜÒº(Ï´Òº)£¬·ñÔò»áʹËùÅäÈÜÒºµÄŨ¶ÈÆ«(Ìî¸ß»òµÍ)________ £®
(4)Ïò________ÖмÓË®ÖÁ¾à¿Ì¶ÈÏß________´¦£¬¸ÄÓÃ________£¬¼ÌÐø¼ÓÕôÁóË®£¬Ê¹ÈÜÒº________ºÍ¿Ì¶ÈÏß________£®
(5)×îºó¸ÇºÃÆ¿Èû£¬ÔÙ________£¬Ê¹ÈÜÒº»ìºÏ¾ùÔÈ£¬ÔÙ½«ÅäºÃµÄÈÜÒºÒÆÈë________ÖУ¬ÌùºÃ±êÇ©±¸Óã®
½âÎö£º
|
(1)27.2;(2)Á¿Í²¡¢²£Á§°ô¡¢ÉÕ±£¬½Á°è£¬²£Á§°ô¡¢500¡¢ÈÝÁ¿Æ¿£®;(3)ÉÕ±¡¢²£Á§°ô£¬500mLÈÝÁ¿Æ¿£¬µÍ£®;(4)ÈÝÁ¿Æ¿£¬2cm¡«3cm£¬½ºÍ·µÎ¹Ü£¬°¼Ãæ¡¢ÏàÇУ®;(5)µ¹×ªÒ¡ÔÈ£¬ÊÔ¼ÁÆ¿ ½âÎö£º(1)
½âµÃV=27.2 mL |
| A¡¢ÕôÁóʱ£¬Ó¦½«½«Î¶ȼƵÄË®ÒøÇò·ÅÔÚÕôÁóÉÕÆ¿µÄÖ§¹Ü¿Ú´¦ | B¡¢ÕôÁóʱ£¬ÀäȴˮӦ´ÓÀäÄý¹ÜµÄÏ¿ÚͨÈ룬ÉÏ¿ÚÁ÷³ö | C¡¢Ó÷ÖҺ©¶··ÖҺʱ£¬Ï²ãÒºÌå´ÓÏ¿ڷųö£¬ÉϲãÒºÌå´ÓÉϿڵ¹³ö | D¡¢ÅäÖÆ1.0mol/LµÄNaClÈÜҺʱ£¬½«³ÆºÃµÄNaCl¹ÌÌåÖ±½Ó·ÅÈëÈÝÁ¿Æ¿ÖÐÈܽâ |
| A¡¢ÓÃÍÐÅÌÌìÆ½³Æ2.10gNaCl | B¡¢ÓÃÁ¿¼òÈ¡21.35mLÑÎËá | C¡¢ÓÃ10.4gNaOH¹ÌÌåºÍÈÝÁ¿Æ¿ÅäÖÆ1.0mol?L-1µÄNaOHÈÜÒº260mL | D¡¢ÓÃ0.12mol?L-1ÑÎËáµÎ¶¨NaOHÈÜÒº£¬ÏûºÄÑÎËá19.32mL |