ÌâÄ¿ÄÚÈÝ
£¨1£©Ä³ÔªËØÔ×Ó¹²ÓÐ3¸ö¼Ûµç×Ó£¬ÆäÖÐÒ»¸ö¼Ûµç×ÓλÓÚµÚÈýÄܲãd¹ìµÀ£¬ÊԻش𣺸ÃÔªËØºËÍâ¼Ûµç×ÓÅŲ¼Í¼ £¬µç×ÓÅŲ¼Ê½ £®¸ÃÔªËØµÄÔ×ÓÐòÊýΪ £¬¸ÃÔªËØÊÇ ÔªËØ£¨Ìî¡°½ðÊô¡±»ò¡°·Ç½ðÊô¡±£©£¬Ðγɵĵ¥ÖÊΪ ¾§Ì壮
£¨2£©ÊԱȽÏÏÂÁк¬ÑõËáµÄËáÐÔÇ¿Èõ£¨Ìî¡°£¾¡±¡¢¡°£¼¡±»ò¡°=¡±£©£ºHClO3 HClO4£»H3PO4 H3PO3£®
£¨3£©¸ù¾Ý¼Û²ãµç×Ó¶Ô»¥³âÀíÂÛÅжÏÏÂÁÐÎÊÌ⣺
NH3ÖÐÐÄÔ×ÓµÄÔÓ»¯·½Ê½Îª ÔÓ»¯£¬VSEPR¹¹ÐÍΪ £¬·Ö×ÓµÄÁ¢Ìå¹¹ÐÍΪ £®
£¨2£©ÊԱȽÏÏÂÁк¬ÑõËáµÄËáÐÔÇ¿Èõ£¨Ìî¡°£¾¡±¡¢¡°£¼¡±»ò¡°=¡±£©£ºHClO3
£¨3£©¸ù¾Ý¼Û²ãµç×Ó¶Ô»¥³âÀíÂÛÅжÏÏÂÁÐÎÊÌ⣺
NH3ÖÐÐÄÔ×ÓµÄÔÓ»¯·½Ê½Îª
¿¼µã£ºÔ×ӽṹÓëÔªËØµÄÐÔÖÊ,Åжϼòµ¥·Ö×Ó»òÀë×ӵĹ¹ÐÍ,Ô×Ó¹ìµÀÔÓ»¯·½Ê½¼°ÔÓ»¯ÀàÐÍÅжÏ
רÌ⣺Ô×Ó×é³ÉÓë½á¹¹×¨Ìâ,»¯Ñ§¼üÓë¾§Ìå½á¹¹
·ÖÎö£º£¨1£©Ä³ÔªËØÔ×Ó¹²ÓÐ3¸ö¼Ûµç×Ó£¬ÆäÖÐÒ»¸ö¼Ûµç×ÓλÓÚµÚÈýÄܲãd¹ìµÀ£¬¼Ûµç×ÓÅŲ¼Ê½Îª3d14s2£¬Æä»ù̬Ô×ÓºËÍâµç×ÓÅŲ¼Ê½Îª£º1s22s22p63s23p63d14s2£¬´¦ÓÚµÚËÄÖÜÆÚ¢óB×壬Ϊ½ðÊôÔªËØ£»
£¨2£©Í¬Ò»ÔªËصĺ¬ÑõËᣬ¸ÃÔªËØµÄ»¯ºÏ¼ÛÔ½¸ß£¬¶ÔÓ¦µÄº¬ÑõËáµÄËáÐÔԽǿ£»
£¨3£©NÔ×Ó¼Û²ãµç×Ó¶Ô¸öÊý=¦Ò¼ü¸öÊý+¹Âµç×Ó¶Ô¸öÊý£¬¾Ý´Ë·ÖÎö½â´ð£®
£¨2£©Í¬Ò»ÔªËصĺ¬ÑõËᣬ¸ÃÔªËØµÄ»¯ºÏ¼ÛÔ½¸ß£¬¶ÔÓ¦µÄº¬ÑõËáµÄËáÐÔԽǿ£»
£¨3£©NÔ×Ó¼Û²ãµç×Ó¶Ô¸öÊý=¦Ò¼ü¸öÊý+¹Âµç×Ó¶Ô¸öÊý£¬¾Ý´Ë·ÖÎö½â´ð£®
½â´ð£º
½â£º£¨1£©Ä³ÔªËØÔ×Ó¹²ÓÐ3¸ö¼Ûµç×Ó£¬ÆäÖÐÒ»¸ö¼Ûµç×ÓλÓÚµÚÈýÄܲãd¹ìµÀ£¬¼Ûµç×ÓÅŲ¼Ê½Îª3d14s2£¬Æä¼Ûµç×ÓÅŲ¼Í¼Îª£º
£¬Æä»ù̬Ô×ÓºËÍâµç×ÓÅŲ¼Ê½Îª£º1s22s22p63s23p63d14s2£¬Ô×ÓÐòÊýΪ21£¬´¦ÓÚµÚËÄÖÜÆÚ¢óB×壬ÊôÓÚ½ðÊôÔªËØ£¬ÐγɽðÊô¾§Ì壬
¹Ê´ð°¸Îª£º
£»1s22s22p63s23p63d14s2£»21£»½ðÊô£»½ðÊô£»
£¨2£©Í¬Ò»ÔªËصĺ¬ÑõËᣬ¸ÃÔªËØµÄ»¯ºÏ¼ÛÔ½¸ß£¬¶ÔÓ¦µÄº¬ÑõËáµÄËáÐÔԽǿ£¬¹ÊËáÐÔ£ºHClO3£¼HClO4£»H3PO4£¾H3PO3£¬
¹Ê´ð°¸Îª£º£¼£»£¾£»
£¨3£©NH3·Ö×ÓÖÐÐÄNÔ×ӹµç×Ó¶ÔÊý=
£¬¼Û²ãµç×Ó¶ÔÊý=3+1=4£¬¹ÊNÔ×Ó²ÉÈ¡sp3ÔÓ»¯£¬VSEPR¹¹ÐÍΪÕýËÄÃæÌ壬·Ö×ÓµÄÁ¢Ìå¹¹ÐÍΪÈý½Ç×¶ÐΣ¬
¹Ê´ð°¸Îª£ºsp3£»ÕýËÄÃæÌ壻Èý½Ç×¶ÐΣ®
¹Ê´ð°¸Îª£º
£¨2£©Í¬Ò»ÔªËصĺ¬ÑõËᣬ¸ÃÔªËØµÄ»¯ºÏ¼ÛÔ½¸ß£¬¶ÔÓ¦µÄº¬ÑõËáµÄËáÐÔԽǿ£¬¹ÊËáÐÔ£ºHClO3£¼HClO4£»H3PO4£¾H3PO3£¬
¹Ê´ð°¸Îª£º£¼£»£¾£»
£¨3£©NH3·Ö×ÓÖÐÐÄNÔ×ӹµç×Ó¶ÔÊý=
| 5-1¡Á3 |
| 2 |
¹Ê´ð°¸Îª£ºsp3£»ÕýËÄÃæÌ壻Èý½Ç×¶ÐΣ®
µãÆÀ£º±¾ÌâÊǶÔÎïÖʽṹµÄ¿¼²é£¬Éæ¼°ºËÍâµç×ÓÅŲ¼¡¢·Ö×ӽṹÓëÐÔÖÊ¡¢¼Û²ãµç×Ó¶Ô»¥³âÀíÂ۵ȣ¬ÄѶȲ»´ó£¬²àÖØ¶Ô»ù´¡ÖªÊ¶¹®¹Ì£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
ÏÂÁÐʵÑéÄÜ´ïµ½Ô¤ÆÚÄ¿µÄÊÇ£¨¡¡¡¡£©
| A¡¢ÏòÖó·ÐµÄ1mol?L-1 NaOHÈÜÒºÖеμÓFeCl3±¥ºÍÈÜÒºÖÆ±¸Fe£¨OH£©3½ºÌå |
| B¡¢ÓÃÇâÑõ»¯Í·ÛÄ©¼ì²âÄòÌÇ |
| C¡¢³ÆÈ¡19.0g SnCl2£¬ÓÃ100mLÕôÁóË®£¬ÅäÖÆ1.0mol?L-1 SnCl2ÈÜÒº |
| D¡¢ÏòÒÒËáÒÒõ¥ÖмÓÈë±¥ºÍNa2CO3ÈÜÒº£¬Õñµ´£¬·ÖÒº·ÖÀë³ýÈ¥ÒÒËáÒÒõ¥ÖеÄÉÙÁ¿ÒÒËá |
ÒÑÖª°¢·ü¼ÓµÂÂÞ³£ÊýΪNA£¬ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ£¨¡¡¡¡£©
| A¡¢1molÄÆÓë×ãÁ¿ÑõÆø·´Ó¦Éú³ÉNa2O»òNa2O2ʱ£¬Ê§µç×ÓÊýÄ¿¾ùΪNA |
| B¡¢1mol Na2O2Óë×ãÁ¿CO2·´Ó¦Ê±£¬×ªÒÆ2NA¸öµç×Ó |
| C¡¢1mol/LµÄNaOHÈÜÒºÖк¬Na+ÊýÄ¿NA |
| D¡¢1mol Na2O2¾§ÌåÖк¬ÓеÄÒõÀë×ÓÊýĿΪ2NA |
ÔÚÏÂÁÐÆøÌåÖУ¬ÓÐÒ»ÖÖÆøÌåÓëÆäËü3ÖÖÆøÌå¶¼²»ÄÜ·´Ó¦£¬¸ÃÆøÌåÊÇ£¨¡¡¡¡£©
| A¡¢°±Æø | B¡¢ÒÒÏ© | C¡¢¼×Íé | D¡¢ÂÈ»¯Çâ |
ÒÑÖª£ºÇ¿ËáºÍÇ¿¼îÔÚÏ¡ÈÜÒºÖз¢Éú·´Ó¦Ê±µÄÖкÍÈÈΪ-57.3kJ?mol-1£¬101kPaʱÐÁÍéµÄȼÉÕÈÈΪ5518kJ?mol-1£®ÔòÏÂÁÐÈÈ»¯Ñ§·½³ÌʽÊéдÕýÈ·µÄÊÇ£¨¡¡¡¡£©
| A¡¢H++OH-¨TH2O¡÷H=-57.3 kJ?mol-1 |
| B¡¢2NaOH£¨aq£©+H2SO4£¨aq£©¨TNa2SO4£¨aq£©+2H2O£¨l£©¡÷H=-114.6 kJ?mol-1 |
| C¡¢2C8H18£¨l£©+25O2£¨g£©¨T16CO2£¨g£©+18H2O£¨g£©¡÷H=-11036 kJ?mol-1 |
| D¡¢2C8H18£¨l£©+25O2£¨g£©¨T16CO2£¨g£©£©+18H2O£¨l£©¡÷H=-5518kJ?mol-1 |