ÌâÄ¿ÄÚÈÝ

ÏÂͼÊDz¿·Ö¶ÌÖÜÆÚÔªËØµÄµ¥Öʼ°»¯ºÏÎïµÄת»¯¹ØÏµÍ¼(Óйط´Ó¦µÄÌõ¼þ¼°Éú³ÉµÄH2OÒÑÂÔÈ¥)£®
ÒÑÖª£º
(a)A¡¢B¡¢C¡¢DÊǷǽðÊôµ¥ÖÊ£¬ÆäÖÐB¡¢C¡¢DÔÚ³£Î³£Ñ¹ÏÂÊÇÆøÌ壮
(b)·´Ó¦¢Ù¡¢¢ÚÊÇ»¯¹¤Éú²úÖеÄÖØÒª·´Ó¦£®
(c)»¯ºÏÎïEÊÇÐγÉËáÓêµÄÎÛȾÎïÖ®Ò»£¬»¯ºÏÎïKÊdz£Óõĵª·Ê£®
(d)»¯ºÏÎïL¾ßÓÐÆ¯°×ÐÔ£¬¿ÉÓÉCl2ÓëNaOHÈÜÒº·´Ó¦¶øÖƵã®
(e)»¯ºÏÎïJÓÉÁ½ÖÖÔªËØ×é³É£¬ÆäÏà¶Ô·Ö×ÓÖÊÁ¿Îª32.
Çë°´ÒªÇóÌî¿Õ£º
(1)·´Ó¦¢ÛµÄ»¯Ñ§·½³ÌʽΪ____________________________________£®
(2)CµÄ½á¹¹Ê½Îª________£»HµÄ»¯Ñ§Ê½Îª________£®
(3)д³öLµÄÈÜÒºÓ뻯ºÏÎïE·´Ó¦µÄÀë×Ó·½³Ìʽ£º ____________________.
(4)»¯ºÏÎïJµÄ»¯Ñ§Ê½Îª________£®
(1)2NH3£«H2SO4===(NH4)2SO4
(2)NN£»(NH4)2SO3»òNH4HSO3
(3)ClO£­£«SO2£«2OH£­===Cl£­£«SO42-£«H2O
(4)N2H4
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø