Question

Óɽðºìʯ£¨TiO₂£©ÖÆÈ¡µ¥ÖÊTi£¬Éæ¼°µ½µÄ²½ÖèΪ£ºTiO₂¡úTiCl₄

Mg        .

800¡æ£®Al

TiÒÑÖª£º
¢Ù

C(s)+O2(g)=CO2(g)¡÷H=-393.5kJ/mol

¢Ú

2CO(g)+O2(g)=2CO2(g)¡÷H=-566kJ/mol

¢Û

TiO2(s)+2Cl2(g)=TiCl4(s)+O2(g)¡÷H=+141kJ/mol

Ôò£¨1£©TiO₂£¨s£©+2Cl₂£¨g£©+2C£¨s£©=TiCl₄£¨s£©+2CO£¨g£©µÄ¡÷H=______£®
£¨2£©Ì¼ÔÚÑõÆøÖв»ÍêȫȼÉÕÉú³ÉCOµÄÈÈ»¯Ñ§·½³ÌʽΪ______£®

Answer 1

£¨1£©ÒÑÖª£º¢Ù

C(s)+O2(g)=CO2(g)¡÷H=-393.5kJ/mol

¢Ú

2CO(g)+O2(g)=2CO2(g)¡÷H=-566kJ/mol

¢Û

TiO2(s)+2Cl2(g)=TiCl4(s)+O2(g)¡÷H=+141kJ/mol

ÀûÓøÇ˹¶¨Âɽ«¢Û+2¡Á¢Ù-¢Ú¿ÉµÃ£º
TiO₂£¨s£©+2Cl₂£¨g£©+2C£¨s£©=TiCl₄£¨s£©+2CO£¨g£©£»¡÷H=£¨+141kJ/mol£©+2¡Á£¨-393.5kJ/mol£©-£¨-566kJ/mol£©=-80kJ/mol£¬¹Ê´ð°¸Îª£º-80KJ/mol£»
£¨2£©ÀûÓøÇ˹¶¨Âɽ«¢Ù¡Á2-¢Ú¿ÉµÃ£º
2C£¨s£©+O₂£¨g£©¨T2CO£¨g£©£»¡÷H=2¡Á£¨-393.5kJ/mol£©-£¨-566kJ/mol£©=-221kJ/mol£¬
»òC£¨s£©+

1

2

 O₂£¨g£©¨TCO£¨g£©£»¡÷H=-110.5kJ/mol
¹Ê´ð°¸Îª£º2C£¨s£©+O₂£¨g£©¨T2CO£¨g£©£»¡÷H=-221kJ/mol»òC£¨s£©+

1

2

 O₂£¨g£©¨TCO£¨g£©£»¡÷H=-110.5kJ/mol£®