ÌâÄ¿ÄÚÈÝ
ʵÑéÊÒÓûÅäÖÆ80mL 1.4mol/LµÄNaNO3ÈÜÒº£¬ÊԻشð£º
£¨1£©Óò»µ½µÄÒÇÆ÷ÊÇ£º £»
¡¡¡¡A.ÉÕ± B.500mLÈÝÁ¿Æ¿ C.Á¿Í² D.½ºÍ·µÎ¹Ü E.²£Á§°ô F.100mLÈÝÁ¿Æ¿
£¨2£©ÅäÖÆÊ±Ó¦³ÆÈ¡NaNO3 g£»
£¨3£©ÏÂÁвÙ×÷µÄ˳ÐòÊÇ£¨ÓÃ×Öĸ±íʾ£© £»
¡¡¡¡A.ÀäÈ´ B.³ÆÁ¿ C.Ï´µÓ D.¶¨ÈÝ E.Èܽâ F.Ò¡ÔÈ G.×ªÒÆ
£¨4£©ÔÚÅäÖÆÒ»¶¨ÎïÖʵÄÁ¿Å¨¶ÈÈÜÒºµÄʵÑéÖУ¬ÏÂÁвÙ×÷¶ÔËùÅäµÃÈÜÒºÎÞÓ°ÏìµÄÊÇ£¨Ð´ÐòºÅ£© £»»áʹËùÅäÈÜÒºµÄŨ¶ÈÆ«´óµÄÊÇ ¡£
A£®ÔÚÉÕ±ÖÐÈܽâÈÜÖÊ£¬½Á°èʱ²»É÷½¦³öÉÙÁ¿ÈÜÒº£»
B£®Î´½«Ï´µÓÉÕ±ÄÚ±ÚµÄÈÜÒº×ªÒÆÈëÈÝÁ¿Æ¿£»
C£®ÈÝÁ¿Æ¿ÖÐËùÅäµÄÈÜÒºÒºÃæÎ´µ½¿Ì¶ÈÏß±ãÍ£Ö¹¼ÓË®£»
D£®½«ÅäµÃµÄÈÜÒº´ÓÈÝÁ¿Æ¿×ªÒƵ½¸ÉÔï¡¢½à¾»µÄÊÔ¼ÁÆ¿ÖÐʱ£¬ÓÐÉÙÁ¿½¦³ö£»
E£®½«ÉÕ±ÖÐÈÜÒº×ªÒÆµ½ÈÝÁ¿Æ¿Ö®Ç°£¬ÈÝÁ¿Æ¿ÖÐÓÐÉÙÁ¿ÕôÁóË®£»
F£®½«ÈÝÁ¿Æ¿ÖÐÒºÃæ½«´ïµ½¿Ì¶ÈÏßʱ£¬¸©Êӿ̶ÈÏߺÍÒºÃæ¡£
£¨1£©B¡¢C£»£¨2£©11.9 £»£¨3£© BEAGCGDF £» £¨4£©DE¡¢ CF¡££¨Ã¿¿Õ1·Ö£¬Â©Ñ¡²»µÃ·Ö£¬¹²5·Ö£©
¡¾½âÎö¡¿
| A¡¢ÐèÔÚÍÐÅÌÌìÆ½ÉϳÆÈ¡Ô¼1.7¿ËNa2CO3¹ÌÌå | B¡¢Ï´µÓÉÕ±ºóµÄÈÜÒºÓò£Á§°ôÒýÁ÷µ½ÈÝÁ¿Æ¿ÖÐ | C¡¢Ï´µÓ2-3´Îºó£¬ÓÃÕôÁóË®ÑØ²£Á§°ô×¢ÈëÈÝÁ¿Æ¿ÖÁ¿Ì¶ÈÏß | D¡¢Ä³Í¬Ñ§²ÉÓÃÑöÊӵķ½Ê½¶¨ÈÝ£¬ÔòÅä³öµÄÈÜҺŨ¶ÈÆ«¸ß |