题目内容
已知H-H键能为436KJ/mol,H-N键能为391 KJ/mol,根据热化学方程式N2(g) +3H2(g)
2NH3(g) △H=-92.4kJ/mol。则N≡N的键能约为( )
A.431 kJ/mol B.946 kJ/mol C.649 kJ/mol D.896 kJ/mol
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题目内容
已知H-H键能为436KJ/mol,H-N键能为391 KJ/mol,根据热化学方程式N2(g) +3H2(g)
2NH3(g) △H=-92.4kJ/mol。则N≡N的键能约为( )
A.431 kJ/mol B.946 kJ/mol C.649 kJ/mol D.896 kJ/mol