ÌâÄ¿ÄÚÈÝ

ijʵÑéС×éÀûÓñ¥ºÍʳÑÎË®¡¢µ¼Ïß¡¢Ö±Á÷µçÔ´£¨Óá°¡± »ò¡°¡±±íʾ£©¡¢ÉÕ±­¡¢Áé

ÃôµçÁ÷¼Æ£¨Óá°¡±±íʾ£©ºÍÁ½¸öµç¼«°ô£¨·Ö±ðÊÇM¡¢N£©½øÐе绯ѧʵÑé̽¾¿¡£

¼×ͬѧ°²×°ºÃÒÇÆ÷£¬½ÓºÃÖ±Á÷µçԴͨµç¼¸·ÖÖÓ£¬·¢ÏÖM´¦ÈÜÒºÖð½¥±ädzÂÌÉ«£¬¹ýÒ»¶Îʱ¼ä£¬ÈÜÒº±äµÃ»ë×ÇÇÒÖð½¥³öÏÖºìרɫ¡£

ÒÒͬѧËùÓõÄÒÇÆ÷ºÍ¼×ͬѧµÄ¿´ÉÏÈ¥Ïàͬ£¬µ«½ÓºÃÖ±Á÷µçԴͨµç¼¸ÃëÖÓ£¬È´Îŵ½Ò»¹É´Ì±ÇµÄÆøÎ¶£¬ÂíÉÏֹͣͨµç¡£

±ûͬѧ°²×°ºÃÒÇÆ÷£¬Ïß·±ÕºÏ¼¸ÃëÖÓºó£¬È´Ã»Óз¢ÏÖÃ÷ÏÔÏÖÏó²úÉú£¬ËûÓֺܿì½ÓÈëÁéÃôµçÁ÷¼Æ£¬·¢ÏÖµçÁ÷¼ÆµÄÖ¸Õë·¢ÉúÁËÆ«×ª¡£

Çë¸ù¾ÝÉÏÊöͬѧµÄʵÑéÏÖÏ󻨴ðÒÔÏÂÎÊÌ⣺

£¨1£©Mµç¼«°ô²ÄÁÏÊÇ£¨Ð´»¯Ñ§Ê½£©         £¬Nµç¼«°ô²ÄÁÏÊÇ£¨Ð´»¯Ñ§Ê½£©          ¡£

£¨2£©ÔÚÏÂÁÐÐé¿òÄÚÍê³É¶ÔÓ¦Èý¸öͬѧµÄ×°ÖÃͼ£º

£¨3£©°´ÒªÇóд³öÈý¸öͬѧʵÑé¹ý³ÌÖÐÉæ¼°µÄ·´Ó¦·½³Ìʽ£º

¼×ͬѧNµç¼«·½³Ìʽ                                   

ÒÒͬѧ×Ü·´Ó¦µÄÀë×Ó·½³Ìʽ                                            

±ûͬѧNµç¼«·½³Ìʽ                                   

£¨4£©Óû¯Ñ§·½³Ìʽ½âÊͼ×ͬѧʵÑéʱ¹Û²ìµ½M´¦ÈÜÒº³öÏÖ»ë×ǺóתΪºìרɫÏÖÏóµÄÔ­Òò£º

                                                                   ¡£

£¨5£©±ûͬѧΪÁ˱£»¤Mµç¼«²»±»¸¯Ê´£¬Ëû¿ÉÒÔ½«Nµç¼«°ô¸ü»»Îª£¨Ð´»¯Ñ§Ê½£©            ¡£ÎªÑéÖ¤¸Ã·À»¤·½·¨ÓÐЧ£¬ËûÓÖ×öÏÂÁжԱÈʵÑ飺½Óͨµç·2·ÖÖӺ󣬷ֱðÔÚMµç¼«ÇøµÎÈë2µÎ»ÆÉ«K3[Fe(CN)6]ÈÜÒº£¬·¢ÏÖûÓиü»»Nµç¼«°ôµÄÉÕ±­ÖеÄÏÖÏóÊÇ                     ¡£

 

£¨1£©Fe  £¬C»òPt

£¨2£©

£¨3£©2H++2e-===H2¡ü

2Cl-+2H2O===Cl2¡ü+H2¡ü+2OH-

O2+2H2O+4e-===4OH-

£¨4£©4Fe(OH)2+O2+2H2O===4Fe(OH)3

£¨5£©ZnµÈ¡¢³öÏÖÀ¶É«³Áµí

½âÎö:

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
£¨2011?³çÃ÷ÏØÒ»Ä££©Èçͼ£¬Ä³Ñ§Ï°Ð¡×éÀûÓÃÏÂÁÐ×°ÖÃ̽¾¿ÂÈÆø°±ÆøÖ®¼äµÄ·´Ó¦£¬ÆäÖÐA¡¢F·Ö±ðΪÂÈÆøºÍ°±ÆøµÄ·¢Éú×°Öã¬DΪ´¿¾»µÄÂÈÆøºÍ°±ÆøµÄ·´Ó¦×°Öã®

Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©×°ÖÃFÖÐÉÕÆ¿ÄڵĹÌÌå¿ÉÑ¡ÓÃ
BD
BD

A¡¢ÂÈ»¯ÂÁ       B¡¢Éúʯ»Ò    C¡¢ÎåÑõ»¯¶þÁ×    D¡¢ÉÕ¼î
£¨2£©ÊµÑéÖÐËùÓõÄŨÑÎËáµÄÖÊÁ¿·ÖÊýΪ36.5%£¬ÆäÃܶÈΪ1.19 g/cm3£¬ÔòÆäÎïÖʵÄÁ¿Å¨¶ÈΪ
11.9mol/L
11.9mol/L
£¨±£ÁôÁ½Î»Ð¡Êý£©£¬ÔÚ±ê¿öÏÂÐè
266.56
266.56
L£¨±£ÁôÁ½Î»Ð¡Êý£©ÂÈ»¯ÇâÈÜÓÚ1LË®ÖвſɵôËŨ¶ÈµÄÑÎËᣮ
£¨3£©ÐéÏß¿òÄÚÓ¦Ìí¼Ó±ØÒªµÄ³ýÔÓ×°Öã¬Ç뽫³ýÔÓ×°ÖÃÖÐÏàÓ¦µÄÊÔ¼ÁÃû³ÆÌîÈëÏÂÁпոñÖУºB
±¥ºÍʳÑÎË®
±¥ºÍʳÑÎË®
£»C
ŨÁòËá
ŨÁòËá
£»E
¼îʯ»Ò
¼îʯ»Ò
£®
£¨4£©×°ÖÃDÄÚ³öÏÖ°×Ñ̲¢ÔÚÈÝÆ÷ÄÚ±ÚÄý½á£¬¼ø¶¨¸Ã¹ÌÌåÊÇÂÈ»¯ï§ËùÐèÒªµÄÊÔ¼ÁÓУº
NaOHÈÜÒººÍʪÈóµÄºìɫʯÈïÊÔÖ½£»ÏõËáÒøÈÜÒººÍÏ¡ÏõËá
NaOHÈÜÒººÍʪÈóµÄºìɫʯÈïÊÔÖ½£»ÏõËáÒøÈÜÒººÍÏ¡ÏõËá
£®
£¨5£©ÓÐͬѧÈÏΪDÖгýÁËÓÐÂÈ»¯ï§Éú³ÉÍ⣬»¹Ó¦ÓÐÆäËûÎïÖÊÉú³É£¬ÄãÈÏΪËûµÄÀíÓÉÊÇ
»¯ºÏ¼ÛÈç¹ûÖ»Éú³ÉÂÈ»¯ï§£¬»¯ºÏ¼ÛÖ»Óнµ¶øÃ»ÓÐÉý£¬²»·ûºÏÑõ»¯»¹Ô­·´Ó¦µÃʧµç×ÓÏàµÈµÄ¹æÂÉ
»¯ºÏ¼ÛÈç¹ûÖ»Éú³ÉÂÈ»¯ï§£¬»¯ºÏ¼ÛÖ»Óнµ¶øÃ»ÓÐÉý£¬²»·ûºÏÑõ»¯»¹Ô­·´Ó¦µÃʧµç×ÓÏàµÈµÄ¹æÂÉ
£®Èç¹ûDÖÐÆøÌåδ³öÏÖºìרɫ£¬Ò²Ã»Óа×Ñ̲úÉú£¬ÔòDÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ
2NH3+3Cl2¨TN2+6HCl
2NH3+3Cl2¨TN2+6HCl
£®

ÎÒ¹úÓÉÓÚÁò»ÇÖ÷ÒªÒÀ¿¿½ø¿Ú£¬ËùÒÔĿǰÖ÷ÒªÒÔÁòÌú¿ó£¨FeS2£©ÎªÔ­ÁÏÖÆÁòËᣬË׳ÆÁòÌú¿ó·¨¡£

£¨1£©Ð´³öÁòÌú¿óÓëÑõÆø·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡

     ¹¤ÒµÉÏ£¬¸Ã·´Ó¦ÔÚ¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡£¨ÌîÉ豸Ãû³Æ£©ÖнøÐС£

£¨2£©Ä³º¬ÓÐSiO2µÄÁòÌú¿óÊÔÑù1¿Ë£¬ÔÚÑõÆøÖгä·ÖׯÉÕºó²ÐÓà¹ÌÌåΪ0.76g£¬Ôò¸ÃÁòÌú¿óʽÑùµÄ´¿¶ÈΪ¡¡¡¡¡¡¡¡¡¡%

ÒÑÖªSO3ÈÛµã16.83¡æ¡¢·Ðµã44.8¡æ¡£Ä³ÐËȤС×éÀûÓÃSO2ºÍO2ÔÚ´ß»¯¼ÁV2O5µÄ×÷ÓÃÏÂÖÆ±¸SO3¹ÌÌå¡£×°ÖÃÈçÏÂͼËùʾ

 


£¨3£©Ð´³öBÖд߻¯¼ÁV2O5±íÃæËù·¢ÉúµÄ·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡

£¨4£©Ñ§ÉúʵÑéʱ·¢ÏÖÔÚC×°ÖÃUÐιܵÄÓÒ±ßÓа×ÎíÉú³É¡£¸Ä½øµÄ°ì·¨ÊÇ¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡£

£¨5£©×°ÖÃDµÄ×÷ÓÃÊÇÎüÊÕÎ²Æø£¬ÆäÖиÉÔï¹ÜµÄ×÷ÓÃÊÇ¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡£×°ÖÃD

ÖÐËù×°ÒºÌåÊÔ¼Á¿ÉÄÜΪ£¨     £©

A£®±¥ºÍʳÑÎË®            B£®¾Æ¾«                       C£®BaCl2ÈÜÒº              D£®NaOHÈÜÒº

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø